Energetics I & II Flashcards
Lattice Energy/Enthalpy
The amount of energy released when one mole of a solid ionic lattice is formed from its ions in the gaseous state
(lattice formation)
Always negative
Enthalpy Change of Atomisation
Enthalpy change when an element is converted into one mole of free gaseous atoms
If the element is a solid, the enthalpy of atomisation is the same as the enthalpy of sublimation
If the element is a diatomic molecule, the atomisation energy is half the bond dissociation energy
Electron Affinity
The energy change per mole when an electron is added to a gaseous atom to form a gaseous anion
Ionisation Enthalpy
Amount of energy required to remove completely an electron from one mole of gaseous atoms to form one mole of gaseous +1 cations
Bond Dissociation Enthalpy
The amount of energy required per mole to break a covalent bond in the gas phase forming two gas-phase free radicals
The mean bond enthalpy is an average of the bond dissociation enthalpy measured in a variety of different compounds
Lattice Enthalpy and Ionic Lattices
Lattice enthlapy is a measure of the strength of the electrostatic force between the ions in an ionic solid.
- the greater the lattice enthalpy, the stronger the electrostatic forces
- the forces are only completely broken when the ions are present as gaseous ions, that are so far apart that there is negligable attraction between them
Factors affecting the strength of an Ionic Bond
Ionic Radius
- Smaller ions pack closer together so the electrostatic forces of attraction are much stronger so the lattice enthalpy is more exothermic
- The larger the ions, the further apart they are in the ionic lattice, so the electrostatic forces are weaker
- smaller radius = more exothermic LE
Ionic Charge
- As the size of the charge increases, the electrostatic forces of attraction get stronger
- As the charge increases,thedecreasein ionic radius produces agreater attractionbetween the positive and negative ions, bringing the ions in the latticecloser together, producingstronger electrostatic attractions
- greater charge = more exothermic LE
Enthalpy Change of Solution
The enthalpy change when one mole of a compound dissolves to form a solution of infinite dilution under standard conditions
Enthalpy Change of Hydration
The enthalpy change when one mole of isolated gas ions is dissolved in water to give and infinitely dilute solution under standard conditions
It is an exothermic process that is affected by ionic radius and ionic charge
- as ionic radius decreases, the enthalpy of hydration becomes more exothermic as small ions will approach closer to the water molecules, to the small ions form stronger electrostatic forces of attraction so more energy is released when hydrated
- as the charge on an ion increases, the ion formsstronger forces of attractionwith the water molecules somore energyis released on hydration of ions with ahigher charge
Polarisation of Ions
Polarisation is caused by the distortion of a negative ion by a positive ion
When a polarising effect is placed on an anion, it can distort the charge cloud, but the Born-Haber lattice enthalpy and theoretical values will differ
The polarising power of a cation increases when:
- the positive ion has a smaller ionic radius
- the positive ion has a larger charge
- charge density
The polarisability of an anion depends on:
- its size - the bigger the ion, the more easily it is distorted
Theoretical VS Experimental
Theoretical lattice enthalpies assume a perfect ionic model when the ions are 100% ionic and spherical and the attractions are purely electrostatic
The born-haber lattice enthalpy is the real experimental value
When 100% ionic, the ions are spherical and the experimental and theoretical values are the same, however, when a polarising effect is placed on an anion, there will be some covalence and the values will differ.
Constructing Born Haber Cycles
- construct cycle using lattice enthalpy and enthalpy change of solution
- add in the hydration enthalpies for both ions
Entropy of Surroundings
∆Ssurr = -∆H/T
Total Entropy Change
∆Stot = ∆Ssys + ∆Ssurr
Entropy of System
∆Ssys = ΣSproducts - ΣSreactants