electronic configuration Flashcards
formula for maximum no. of electrons in a shell:
2n^2
shells are made of atomic orbitals - atomic orbitals definition:
a region around the nucleus that can hold up to two electrons, with opposite spins
what is an s-orbital?
shape of a sphere - can hold up to 2 electrons
what is a p-orbital?
dumb-bell shape, three separate p orbitals ( Px, Py and Pz) therefore in total, can hold up to 6 electrons as one orbital holds up to two electrons
what are the d and f orbitals?
more complex shapes - but from the 3rd shell, five d-orbitals are present therefore 10 electrons in total as (each orbital can hold up to 2)
- from the 4th shell - seven f-orbitals present therefore 14 electrons in total
how to fill each shell/what orbitals are in each shell and max no of electrons?
1st:
2nd:
3rd:
4th:
1st (n=1) shell - 1s (2 electrons)
2nd (n=2) shell - 2s, 2p (8 electrons)
3rd (n=3) shell - 3s, 3p, 3d (18 electrons)
4th (n=4) shell - 4s, 4p, 4d, 4f (32 electrons)
why does the 4s subshell need to fill before the 3d subshell?
therefore order of filling?
because the 3d subshell is higher in energy, and orbitals fill in order of increasing energy
so order of filling is 3p, 4s, 3d
in an electron in-a-box model, why must one electron occupy each box (orbital) before pairing starts?
to prevent any repulsion between paired electrons until there is no further orbital available at the same energy level
how can you express electron configurations more simply eg
Na which is: 1s2 2s2 2p6 3s1
[Ne] 3s1
why is the 4s sub shell emptied first during ionisation process?
since the energies of the 3d and 4s sub-shells are very close together, once both filled, the 3d energy level suddenly falls below the 4s energy level, therefore it’s emptied out first