Electrode Potentials and Fuel Cells Flashcards
What is the oxidation state of uncombined elements?
Zero.
For a monoatomic ion, what is the oxidation state of the element?
Its the same charge of the ion.
What are the oxidation states of oxygen?
The oxygen state in all compounds is -2 but in hydrogen peroxide (H2O2), when it is -1, or in OF2 when it’s +2.
What is the sum of all oxidation states in a neutral compound?
Zero.
What must the sum of all the oxidation states in a compound equal?
The overall charge.
What is oxidation?
The loss of electrons.
What is reduction?
The gain of electrons.
What is a reducing agent?
A reactant that causes another reactant to be reduced in a reaction (itself, usually, being oxidised).
What is an oxidising agent?
A reactant that causes another reactant to be oxidised (itself usually being reduced).
What do fuel cells do?
They generate electricity from an electrochemical reaction in which oxygen (from air) and a fuel (e.g. hydrogen) combine to form water. The electricity produced can be use to power cars, buses etc. The by-product, heat, can also be used.
Describe the structures of fuel cells.
Fuel cells consist of 2 electrodes, a negative anode and a positive cathode.
The electrodes are separated by a by a solid or liquid electrolyte.
Catalysts (e.g. Pt) are often used to speed up reaction.
Electricity is generated when oxygen and hydrogen combine to form water.
In a Proton Exchange Membrane Fuel Cell (PEMFC), what is the fuel and what is the catalyst?
Fuel is Hydrogen, catalyst is Platinum.
In a Proton Exchange Membrane Fuel Cell (PEMFC), describe the operation.
- Hydrogen is oxidised to protons at the anode
- Protons move through the electrolyte
- Electrons pass through the external circuit
- Oxygen is produced at the cathode
- Water is produced
- A catalyst accelerates the reaction at the electrodes
In a Proton Exchange Membrane FUEL CELL (PEMFC), What happens at the anode?
2H2(g) -> 4H+(aq) + 4e-
Eo = 0.00V
In a Proton Exchange Membrane FUEL CELL (PEMFC), what happens at the cathode?
O2(g) + 4H+(aq) + 4e- -> 2H2O(l)
E0 = +1.23V