electric field due to pt charge and extended bodies Flashcards
the main part basically
electric field due to a point charge
Kq/x^2
electric field due to uniformly charged rod AT AXIAL POINT
KQ/L [1/R + 1/(R+L)]
L is length of rod and R is distance from the end
electric field at an equatorial point of uniformly charged rod
2KQ/[R√(L² + 4R²)]
L is rod length R is perpendicular distance from centre of rod
field due to uniformly charged infinite thread
2Kλ/r
where λ is linear charge density C/m
r is perp. distance from the thread
field due to uniformly charged semi-infinite thread (infinite from one end and the point is perpendicular right to the other end so there is no symmetry involved)
√2Kλ/r
r is perp. distance from one end of the thread
pls look up this derivation its long asf
field at general point due to a uniformly charged rod
2Kλ/r
where r is perpendicular distance from rod at any point
electric field due to uniformly charged ring
at axial point-
KQx/[(R² + x²)^3/2]
0 at centre
when it is cut, E= KQw/2piR^3 where w is the width of the cut portion
field due to uniformly charged circular arc
2KQsin(θ/2)
θR^2
R is radius of the arc
this can be used for half ring by putting pi and quarter ring by putting pi/2