Electric Circuits Spec Points

Question 1

Ohms law when temperature is constant

Answer 1

The current flowing through a conductor is directly proportional to the potential difference across its ends.

Question 2

Kirchoff’s first law - the electric current rule

Answer 2

The algebraic sum of the current entering and leaving a junction is equal to zero

This is a consequence of conservation of charge - current shouldn’t decrease or increase in a circuit when it splits

Question 3

Conservation of charge

Answer 3

Charge cannot be created or destroyed, so in a closed loop, the flow of charge must be the same throughout

Question 4

Kirchoff’s second law

Answer 4

The sum of all the voltages in a series circuit is equal to the battery voltage or the sum of all the voltages in a loop is zero.

Question 5

Potential differences in circuits due to energy conservation

Answer 5

Series - battery p.d. Is shared across all elements in the circuit, therefore the total sum of the voltages across all elements is equal to the supply p.d.

Parallel - the p.d. Across each branch is the same

Question 6

Deriving resistance in parallel

Answer 6

Electrical current rule
I = I1 + I2
Electrical voltage rule
V = V1 = V2
Rearranging ohms law for current (I=V/R)
V/R = V/R1 + V/R2
Since p.d. Is the same for all resistors, divide by V
1/R = 1/R1 + 1/R2

Question 7

Deriving resistance in a series circuit

Answer 7

V = V1 + V2
Ohms law V=IR
IR = IR1 + IR2
Divide by I because it is the same for all resistors
R = R1 + R2

Question 8

Diode I-V graph

Answer 8

• when the current is in the direction of the arrowhead symbol, this is forward bias.
  This is shown by the sharp increase in p.d. And the current on the right side of the graph
• when the diode is switched around, it does not conduct and is called reverse bias. This is shown by a zero reading of current or p.d. On the left side of the graph
• the threshold voltage at which a diode starts to conduct is typically 0.6V

Question 9

Filament lamp I-V graph

Answer 9

Shows the current increasing at a proportionally slower rate than the potential difference
- because: as current increases, temp of the filament in the lamp increases
- since the filament is a metal, the higher temp causes an increase in resistance
- resistance opposes the current, causing the current to increase at a slower rate.

-where the graph is a straight line, the resistance is constant
- the resistance increases as the graph curves
- the filament lamp obeys ohm’s law for small voltages

Question 10

Thermistor I-V grpah

Answer 10

Shallow curve upwards
- increase in pd results in an increase in current causing temp of thermistor to rise
- as temp rises, resistance decreases
- this means more current is able to flow through

Question 11

Core practical 2: investigating resistivity
Aim + variables

Answer 11

Aim - to determine the resistivity of a length of wire
Independent - length of wire (m)
Dependent - the current through the wire (A)
Control - voltage across the wire
- material the wire is made from

Question 12

Core practical 2: investigating resistivity
Equipment list

Answer 12

Ammeter
Voltmeter
2.0m of wire
Flying lead ( a wire with a crocodile clip at one end to allow connection at any point along the test wire)
Metre ruler
Micrometer
Power supply

Question 13

Core practical 2: investigating resistivity
Resolution of measuring equipment

Answer 13

Metre ruler - 1mm
Micrometer - 0.01 mm
Voltmeter - 0.1V
Ammeter - 0.01A

Question 14

Core practical 2: investigating resistivity
Method

Answer 14

• measure the diameter of wire using a micrometer
• measurement should be taken between 5-10 times randomly along the wire
• calculate mean diameter from these results
  Set up equipment so the wire is taped or clamped to the ruler with one end of the circuit attached to the wire where the ruler reads 0.
• the ammeter is connected in series and the voltmeter in parallel with the wire.
• attach the flying lead to the test wire at 0.25m and set the power supply at a voltage of 6.0V
• check that this is the voltage across the wire on the voltmeter
• read and record the current from the ammeter then switch off the current immediately after the reading
• this is to prevent the wire from heating up and changing the resistivity.
• vary the distance between the fixed end of the wire and the flying lead in 0.25m intervals until the full length
• record the current for each length at least three times and calculate an average current, I
• for each length calculate the average resistance of the length of the wire using the equation r=v/I
• R - average resistance of the length of the wire
• V - potential difference across the circuit
• I - the average current through the wire for the chosen length

Question 15

Core practical 2: investigating resistivity
Analysis of resuslts

Answer 15

Resistivity = RA/l
Rearrange
R = pL/A
Y = mx
Y = R
X = L
M = p/A

Therefore to find resistivity:
- plot a graph of the length of the wire against the average resistance of the wire
- draw a line of best fit
- calculate the gradient
- multiply the gradient by cross-sectional area

A = pid^2/4

Question 16

Core practical 2: investigating resistivity
Systematic errors

Answer 16

• the end of the wire that is attached to the circuit must start at 0 on the ruler
  Otherwise this could cause a zero error in your measurements of the length

Question 17

Core practical 2: investigating resistivity
Random errors

Answer 17

• only allow small currents to flow through wire
• the resistivity of a material depends on its temperature
  -the current flowing through the wire will cause its temperature to increase
• therefore the temperature is kept constant by small currents
• the current should be switched off in between readings so that there isnt a temperature rise
• calculate an average diameter
• this will reduce random errors in the reading
• make at least 5-10 measurements of the diameter of the wire with the micrometer

Question 18

Core practical 2: investigating resistivity
Safety considerations

Answer 18

• when there is a high current, and a thin wire, the wire will become very hot
• do not touch the wire directly when the circuit is switched on
• switch off the power supply between readings and immediately if you smell burning
• keep liquids away from electrical equipment.

Question 19

Why does the potential along a uniform current-carrying wire vary with the distance along it

Answer 19

Resistance of an object is dependent on its length
A uniform current-carrying wire has a constant resistivity and cross-sectional area.
When length increases, the resistance will increase uniformly. Using ohm’s law, potential will also increase

Question 20

Principles of a potential divider circuit

Answer 20

A circuit with several resistors in series connected across a voltage source, used to produce a required fraction of the source potential difference, which remains constant.
You can also make the pd supply a variable pd by using a variable resistors as one

Question 21

Potential divider equation

Answer 21

Vout = Vin (R2/R1+R2)

Question 22

A LDR’s resistance decreases as light intensity increases
LDR = R1
Resistor = R2
What will V out do when light intensity falls

Answer 22

Resistance across R1 will increase
Total circuit resistance increases
Circuit current will decrease
Using Ohm’s law, voltage across R2 will decrease
So V out decreases

Question 23

Define electromotive force

Answer 23

Energy transferred by a cell per coulomb of charge

Question 24

What is internal resistance

Answer 24

Resistance within a battery that causes a drop in the source voltage when there is a current
Caused by electrons colliding with atoms inside the battery, therefore some energy is lost before electrons leave battery
Represented as a small resistor inside the battery

Question 25

What is terminal potential difference

Answer 25

P.d. Across resistance R (load resistance)

Question 26

When can the emf be measured using a voltmeter

Answer 26

Voltage across a cell when there is no current running through the cell which means it is an open circuit

Question 27

Core practical 3: determine the emf and internal resistance of an electrical cell Variables

Answer 27

Independent - resistance Dependant - voltage and current Control - emf of cell , internal resistance of cell

Question 28

Core practical 3: determine the emf and internal resistance of an electrical cell Equipment list + resolutions

Answer 28

1.5 V cell Resistor - unknown resistance to act as internal resistance 100 ohm variable resistor Voltmeter 1mV Ammeter 0.1mA Wires Switch

Question 29

Core practical 3: determine the emf and internal resistance of an electrical cell Method

Answer 29

1. Cell and resistor (r) shld be connected in series, considered to be a single cell 2. Record V when switch is open 3. Set variable resistor to its max value, close switch and record V and I 4. Vary resistance up to a minimum of 8-10 readings Ensure you take readings for the whole range of the variable resistor

Question 30

Core practical 3: determine the emf and internal resistance of an electrical cell Analysing results

Answer 30

E=I(R+r) Rearrange to V = -rI + E Y = mx + c Plot a graph of V against I and draw line of best fit Measure gradient - negative internal resistance Y intercept - emf

Question 31

Core practical 3: determine the emf and internal resistance of an electrical cell Evaluating - errors

Answer 31

Systematic Only close the switch for as long as it takes to take each pair of readings. This will prevent internal resistance of the battery changing during the experiment Random Only use fairly new cells. Run down batteries can vary their internal resistance during an experiment Wait for reading on ammeter and voltmeter to stabilise before reading results Take multiple readings to reduce random errors

Question 32

Core practical 3: determine the emf and internal resistance of an electrical cell Safety considerations

Answer 32

- electrical components can get hot when used for a long period of time - switch off power supply right away if there is a burning smell - make sure there are no liquids close to the equipment

Question 33

How can changes in resistance with temperature be modelled in terms of lattice vibrations and number of conduction electrons

Answer 33

As the temperature increases, the intensity of the vibration of its atoms also increases The more intense the lattice vibrations are, the more difficult it is for free electrons to pass through it This is because the electrons will be more likely to collide with the vibrating atoms if they are oscillating more intensely, causing them to slow down. This increases the resistance

Question 34

Apply to metallic conductors: Changes of resistance with temperature modelled in terms of lattice vibrations

Answer 34

As temperature of a metal conductor increases, its atoms gain energy and once they gain enough energy, they begin to release electrons (thermionic emission). This increases the number of charge carriers available in the conductor, which decreases its resistance

Question 35

Apply to NTC thermistors: Changes of resistance with temperature modelled in terms of lattice vibrations

Answer 35

When their temperature increases, resistance decreases Because they release a large amount of electrons as their temperature increases which frees up charge carriers (outweighing the effects of lattice vibrations)

Question 36

How can resistance changes with illumination be modelled in terms of the number of conduction electrons

Answer 36

When light above a certain frequency is shone onto a metal, it releases electrons, which are known as photoelectrons. This is called the photoelectric effect

Question 37

Apply to LDR: Changes of resistance with illumination, modelled in terms of number of conduction electrons

Answer 37

LDRs are made from photoconductive materials, meaning that they release electrons in the presence of light. Therefore, as light intensity increases, electrons are released, which increases the number of charge carries available to conduct electricity, and the resistance of the LDR decreases

Question 38

I =

Answer 38

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