Electric Circuits Spec Points Flashcards
Ohms law when temperature is constant
The current flowing through a conductor is directly proportional to the potential difference across its ends.
Kirchoff’s first law - the electric current rule
The algebraic sum of the current entering and leaving a junction is equal to zero
This is a consequence of conservation of charge - current shouldn’t decrease or increase in a circuit when it splits
Conservation of charge
Charge cannot be created or destroyed, so in a closed loop, the flow of charge must be the same throughout
Kirchoff’s second law
The sum of all the voltages in a series circuit is equal to the battery voltage or the sum of all the voltages in a loop is zero.
Potential differences in circuits due to energy conservation
Series - battery p.d. Is shared across all elements in the circuit, therefore the total sum of the voltages across all elements is equal to the supply p.d.
Parallel - the p.d. Across each branch is the same
Deriving resistance in parallel
Electrical current rule
I = I1 + I2
Electrical voltage rule
V = V1 = V2
Rearranging ohms law for current (I=V/R)
V/R = V/R1 + V/R2
Since p.d. Is the same for all resistors, divide by V
1/R = 1/R1 + 1/R2
Deriving resistance in a series circuit
V = V1 + V2
Ohms law V=IR
IR = IR1 + IR2
Divide by I because it is the same for all resistors
R = R1 + R2
Diode I-V graph
- when the current is in the direction of the arrowhead symbol, this is forward bias.
This is shown by the sharp increase in p.d. And the current on the right side of the graph - when the diode is switched around, it does not conduct and is called reverse bias. This is shown by a zero reading of current or p.d. On the left side of the graph
- the threshold voltage at which a diode starts to conduct is typically 0.6V
Filament lamp I-V graph
Shows the current increasing at a proportionally slower rate than the potential difference
- because: as current increases, temp of the filament in the lamp increases
- since the filament is a metal, the higher temp causes an increase in resistance
- resistance opposes the current, causing the current to increase at a slower rate.
-where the graph is a straight line, the resistance is constant
- the resistance increases as the graph curves
- the filament lamp obeys ohm’s law for small voltages
Thermistor I-V grpah
Shallow curve upwards
- increase in pd results in an increase in current causing temp of thermistor to rise
- as temp rises, resistance decreases
- this means more current is able to flow through
Core practical 2: investigating resistivity
Aim + variables
Aim - to determine the resistivity of a length of wire
Independent - length of wire (m)
Dependent - the current through the wire (A)
Control - voltage across the wire
- material the wire is made from
Core practical 2: investigating resistivity
Equipment list
Ammeter
Voltmeter
2.0m of wire
Flying lead ( a wire with a crocodile clip at one end to allow connection at any point along the test wire)
Metre ruler
Micrometer
Power supply
Core practical 2: investigating resistivity
Resolution of measuring equipment
Metre ruler - 1mm
Micrometer - 0.01 mm
Voltmeter - 0.1V
Ammeter - 0.01A
Core practical 2: investigating resistivity
Method
- measure the diameter of wire using a micrometer
- measurement should be taken between 5-10 times randomly along the wire
- calculate mean diameter from these results
Set up equipment so the wire is taped or clamped to the ruler with one end of the circuit attached to the wire where the ruler reads 0. - the ammeter is connected in series and the voltmeter in parallel with the wire.
- attach the flying lead to the test wire at 0.25m and set the power supply at a voltage of 6.0V
- check that this is the voltage across the wire on the voltmeter
- read and record the current from the ammeter then switch off the current immediately after the reading
- this is to prevent the wire from heating up and changing the resistivity.
- vary the distance between the fixed end of the wire and the flying lead in 0.25m intervals until the full length
- record the current for each length at least three times and calculate an average current, I
- for each length calculate the average resistance of the length of the wire using the equation r=v/I
- R - average resistance of the length of the wire
- V - potential difference across the circuit
- I - the average current through the wire for the chosen length
Core practical 2: investigating resistivity
Analysis of resuslts
Resistivity = RA/l
Rearrange
R = pL/A
Y = mx
Y = R
X = L
M = p/A
Therefore to find resistivity:
- plot a graph of the length of the wire against the average resistance of the wire
- draw a line of best fit
- calculate the gradient
- multiply the gradient by cross-sectional area
A = pid^2/4