Dynamics & Relativity 1 Flashcards
for uniform motion r(t)=
r(t0)+v(to)(t-t0)+1/2A(t-t0)^2
velocity
defined as rate of change of positions
v(t) = dr/dt = dxp/dt i + dyp/dt j + dzp/dt k
acceleration
defined as the rate of change of velocity
a(t)=dv/dt=d^2r/dt^2 (same idea in vector components as velocity but with second derivative)
simpler notation for time dependence
r0 = r(t0)
r = r(t)
hence r=ro+vo(t-t0)+1/2a(t-t0)^2
motion in 1 dimension
pick just a single direction eg x
r=xi, v=vxi, a=axi
vx=dx/dt, ax=d&2x/dt^2 = constant
derivation of vx=vx0+ax(t-t0) using integration
start with ax=dvx/dt and integration both sides wrt time
on lhs, a constant so get ax(t-t0)
rhs gives vx-vx0
put together a rearrange
derivation of x-x0=vx0(t-t0)+ax/2(t-t0)^2
use vx=dx/dt
integrate both sides wrt time
insert previous equation for velocity and rearrange
how to make x-x0=vx0(t-t0)+ax/2(t-t0)^2 more familiar?
setting initial position and time to zero gives
x=vx0t+1/2axt^2
derivation of vx^2=vx0^2+2ax(x-x0)
combining previous two equations and eliminating (t-t0)
derivation of x-x0=1/2(vx+vx0)(t-t0)
combining previous two equations and eliminating acceleration
assumptions for free falling bodies
- gravitational acceleration due to Earth’s gravity is constant
- ignore gravity from everything but Earth
- ignore rotation of Earth
- Pretend Earth is flat
- Ignore air resistance
free falling body setup
ay=-g
vy=vy0-g(t-t0)
y-y0=vy0(t-t0)-1/2g(t-t0)^2
free falling bodies - things to check
- units
- signs (heights +Ve or 0, object moving down so y-component of velocity is -ve
3.magnitudes (timescale a few secodns, distance few tens of metres etc)
motion in 2 dimensions
study the motion in each dimension seperately
acceleration in x direction
0
hence vx=vx0
separating velocity into components
vx0=v0costheta
vy0=v0sintheta
how to find y as a function of x
take equation for y and use equation for x to eliminate t
how far does an object travel (x direction)
set vertical position to zero and rearrange for Xr