DSA - Clearance : FENa Flashcards
renal elimination equatino
elimination = filtered load - reabsorbed load + secreted load
the volume of plasma from which a specific compound is completely eliminated per unit time
renal clearance
A FLOW RATE
renal input = renal output +
urinary excretion rate
renal input
renal input = Pax * RPFa
Pax - arterial concentration of x
RPFa - renal arterial plasma flow
urinary excretion rate
urinary excretion = Ux * V
Ux = urine cncentration of x
V = urine flow rate
from how many mls of plasma entering the kindey perminute was substance x removed
clearance answers this
Cx = Ux *Vspot / Px
if a substance is freely filterd but NOT reabsorbed nor secreted, the renal elimination rate equals
the GFR
inulin
requirements of substances suitable for measurement of GFR
freely filtered across the glomerulus (not bound to plasma proteins)
undergoes no reabsorption
undergoes no tubular secretion
is neither metabolized nor synthesized in the kidney
does not alter GFR
endogenous replacement of inulin
creatinine
substance that is completely eliminated from the kidney during passage through the kidney
its clearance equals renal plasma flow
PAH
measures effective RPF
filtered load equation
GFR X Px
excreted load equation
el = v * vx
