DNA to RNA synthesis and Processing part 1 Flashcards

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1
Q

What are the steps involved in transcription?

A

Initiation: recruitment of RNA polymerase

Elongation: promoter clearance and extension

Termination: release of RNA polymerase

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2
Q

What are the steps in Eukaryote transcription?

A
  1. proper transcription by RNA polymerase II requires co-factors

Mediator and co-mediator

Specific transcription factore (ie SOI, GAG,A HSF)

Transcriptional activators (often domains of TF’s)

Chromatin remodeling complexes (such as SWI/SNF, NURF)

Elongation factors

Termination Factors

n Eukaryotes: RNA pol II (mRNA) requires co-factors mediatore co-mediators, general TF, Chromatin remodeling, complexes, elongation factors, termination factors

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3
Q

Transcription basics

A
  1. RNA produced: complementary to template strand

matches sequence in DNA coding strand

The function of RNA polymerase is to copy one strand of duplex DNA into RNA

RNA produced is complementary to the template strand matching the sequence of the coding strand

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4
Q

What is the role of RNA olymerase?

A

RNA polymerase:

adds NTP’s 5’-3’ direction at 40/sec

does not need 3’ OH primer to start

binds dsDNA at promoter sites upstream of transciption start site

may require additional proteins to aid in binding and stability

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5
Q

overview of transcription

A

a transcription unit is a sequence of DnA transcribed into a single RNA starting at the promoter and ending at the terminator

Transcription unit defined by the presence of a promoter region, a coding region and a terminator region.

not that +1 indicates the actual transcription star

definition of upstream and downstream

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6
Q

the transcription process

A
  1. works 5’ - 3’
  2. DNA is temprarily denatured (10-20 bases at a time) typically 18 5. bp
  3. RNA is hybridized at 3’ end over a few bases (less than 12 bp)
  4. Formation of a transcription bubble
  5. RNA held in position by RNA-DNA hybrid formation over only a few bp
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7
Q

describe bacterial RNA polymerase holoenzyme

A
  1. 5 subunits
  2. alpha (x2) = required to assemble core protein
         binds some activators
    
         promoter recognition (40KD)
  3. Beta + Beta” = catalytic core (`55 NS 160 KD
  4. sigma = binds 10 and 35 promoter sites
         increases specific binding
    
         is dispensable for polymerase (32-90 KD)

Bacterial RNA pol (only one) 5 SU

2 alpha SU responsible for promoter recognition and binding of activators
Catalytic SU are beta and beta prime (respectively 155 and 160KD)
Sigma SU binds at position -10 and -35 increasing specificity of binding at the proper location (-10 and -35 positions are important sequences)

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8
Q

Explain how RNA polymerase has a channel for DNA

A

The template strand is in red

Non-template strand is in yellow

DNA clamped between beta and beta’ SU.

DNA melted and formation of RNA transcript (brownish-gold)

Alpha 2 + sigman on opposite side of polymerase (grey and green)

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9
Q

Describe RNA polymerase and the unwinding of DNA

A

The ~10 and ~35 boxes

RNA polymerasa unwinds DNA ~10 bp upstream from transcription start

~10 box of Pribnow box: corresponds to the TATA box (consensus sequence is TATAAT)

~35 box: consensus sequence TTGACA

note the position +1 where transcrition starts (addition of nucleotides)

TTGACA Promoter ~35 bp upstream of start has a role in stabilizing RNA polymerase binding

[The typical prokaryotic promoter]

Typical distances between the start point ~10 and ~35 box

Start point of Pribnow box is actually 5-9 bp

Distance between TATA-box and ~35 box is between 16-19 bp

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10
Q

What is the overal process of Prokaryote Transcription?

A
  1. Polymerase bound in non-specific manner, scanning DNA
  2. Recognition of ~10 and ~35 sequences
  3. DNA in unwound around the initiation site (DNA melting Open promoter complex)
  4. RNA polymerase will resume movement downstream and start addding nucleotides (promoter clearance)
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11
Q

Explain termination for rho dependent or rho independent

A
  1. After addition of 8-9 nucleotides, the sigma SU is released and elongation phase starts
  2. termination can follow two different mechanisms rho-dep or rho-indep
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12
Q

Describe the architecture of transcribing RNA pol

A
  1. During transcription, the bubble is maintained within bacterial RNA plymerase, which unwinds and rewinds DNA
  2. the conditions of the partner and template DNA strand are maintained while RNA is synthesized
  3. B + B’ are shown to cross link with:
  • template DNA
  • product RNA
  • ribonucleotides
  1. Bubble = 12-20 bp in length
  2. RNA-DNA hybrid region = <12 bp
  3. the structure was determined by protein-protein or protein-DNA crosslinking experiments
  4. SU B and B’ are in close proximity with the template DNA, RNA transcript and NTPs
  5. RNA is added at the catalytic site
  6. After addition and movement of the pol downstream, the DNA is rewound into a typical dsDNA
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13
Q

Close up on the catalytic site DNA turns at the active site

A

Multiple clefts, tunnels and 3-D structures maintain the DNA in single stranded conformation

The rudder in the center promotes unwinding

The bridge structure acts as a guide for the DNA towards the wall structure

The tunnel between the Bridge and Wall is the entry pont for NTPs

The NTPs are added and the RNA exits between the rudder and upper protion of the Wall

Note: the enzyme moves form left to right

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14
Q

What is Rho-Independent Termination?

A

Rho-independent is linked to actual sequence transcribed

The RNA transcript forms a stem loop structure that will promote the release of the RNA polymerase (dissociation of RNA-DNA hybrid)

GC rich area + 4 A’s

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15
Q

Explain Rho-dependent termination: Hexamer

and its C rich, G poor sequence without poly U, gets a small hairpin loop

A

Rho-dependent termination:

  1. The Rho factor is required. RNA polymerase transcribes DNA
  2. It forms an hexamer that will find a specific sequence on then transcribed RNA. Rho attaches to recognition site on RNA
  3. The Rho complex moves alongside following the RNA pol.
  4. The RNA polymerase will find a sequence referred to as terminator (C-rich and G-poor, no poly-U promotes the formation of a small hairpin loop structure that Rho complex will recognize) RNA polymerase pauses at terminator
  5. the Rho complex will catch up with the RNA pol.
  6. Rho complex will unwind the DNA-RNA hybrid in transcription bubble and the RNA will be released.
  7. RNA polymerase, rho and RNA are released
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