DISCOVERY OF THE ELECTRON Flashcards

You may prefer our related Brainscape-certified flashcards:
1
Q

What is a cathode ray? And what is the setup?

A
  • A cathode ray is a beam of electrons, called a cathode ray as it appears to be a glowing ray that originates from the cathode
  • The glow is caused by excitation: the free electrons excite the gas particles and when they de-excite they release photons, this is also called “recombination”
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Thermionic emission and their use in electron beams

A
  • This is when a metal is heated, and it’s free electrons gain enough kinetic energy to break free of the surface of the metal
  • This is used to create electron beams as when free electrons are emitted they can be accelerated through a P.D
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Defining the electron volt

A
  • Work done on a particle of charge Q, accelerated through a PD of V, is equal to QV joules
  • replace Q with the charge of an electron, and we get eV
  • work done = 1/2 mv^2 = eV
  • new unit of energy
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Measuring specific charge of an electron

A
  • fire an electron beam in a glass bulb containing hydrogen at low pressure
  • the beam will excite the hydrogen atoms, and allow us to see its path
  • put magnetic field coils either side of the bulb to create a uniform magnetic field that causes the electron beam to have a circular path
  • this means magnetic force = centripetal force
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Millikan’s oil drop experiment

A
  • an atomiser creates a thin mist of oil drops that are charged by friction as they leave the atomiser
  • some drops fall through a hole in the top plate and reach terminal velocity where mg = 6π x viscosity x rv

mg = 4/3 πr3 x density x g

r2 = 9 x visc x v / 2 x density x g

  • when the electric field is turned on it is adjusted so that the drop is stationary, as F = QV / d

QV/d = mg = 4/3 πr3 x density x g

  • values for Q were all multiples of 1.6 x 10-19 so it was assumed this was the fundamental unit of charge and the charge of the electron
How well did you know this?
1
Not at all
2
3
4
5
Perfectly