Differential Equations Flashcards

1
Q

An equation that contains one of more terms involving derivatives.

A

Differential Equations

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2
Q

An equation containing only one independent variable

A

Ordinary Differential Equation

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3
Q

An equation containing two or more independent variables

A

Partial Differential Equation

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4
Q

order of the highest ordered derivative

A

Order

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5
Q

Highest power of the highest ordered derivative

A

Degree

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6
Q

The solution has at least one arbitrary constant

A

General Solution

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7
Q

The solution has no arbitrary constant

A

Particular Solution

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8
Q

Variable Separable

A

It is variable if you can rearrange the equation to form

P(x)dx = Q(y)dy

then derive respectively to obtain solution

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9
Q

Homogeneous DE

A

It is homogeneous if M(x,y)dx + N(x,y)dy = 0 has all terms of equal degree

to solve:
let:
y = vx
dy = vdx + xdv

and rearrange to form variable separable

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10
Q

Exact DE

A

M(x,y)dx + N(x,y)dy = 0

is exact if:

dM/dy = dN/dx

to solve:

integrate M wrt x and N wrt y and combine unique terms

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11
Q

Linear DE

A

dy/dx + y P(x) = Q(x)

General Solution:

y(e^∫Pdx) = ∫Q(e^∫Pdx) dx

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12
Q

Bernoulli’s Equation

A

dy/dx + y P(x) = (y^n)Q(x)

IF = e^(1-n)∫Pdx

General Solution:

(y^(1-n)) (e^∫(1-n)(Pdx)) = ∫(1-n)(Q)(e^∫(1-n)(Pdx)) dx

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13
Q

Population Growth Problems / Population Dynamics

A

dP/dt = kP

k-const of proportionality
P-population at any given time

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14
Q

Radioactive Decay Problems

A

dQ/dt = kQ

k-const of proportionality
Q-amount of substance at any given time

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15
Q

Economics: Continuous compound interest

A

dP/dt = rP

r-nominal rate of interest
P-money present in the account at any time

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16
Q

Temperature: Law of Cooling

A

dT/dt = k(T-ts)

T-Temperature of body at any time
ts-surrounding temperature

17
Q

Flow problem & Mixture Problem

A

dQ/dt = RiCi - RoCo

Co = Q/(V + (Ri-Ro)t)

*Qo Qu, Vi Ri Ro Tee

18
Q

Kinematics

A

F = m(dv/dt)

a = dv/dt

v = ds/dt

19
Q

Hooke’s Law (Spring)

A

F = kx

20
Q

Geometrical Problems (Orthogonal Trajectory)

A

dy/dx new = -dx/dy original