determine seismic forces for elements of structures (Fp) architectural components

Question 1

design seismic force, Fp (strength design force level) - horizontal

Answer 1

Fp = 0.4 Ap Sds Wp / (Rp/Ip) x (1 + 2 Z/h)

Question 2

except

Answer 2

Fp ≤ 1.6 Sds Ip Wp - Max and ≥ .3 Sds Ip Wp Min.

Question 3

horizontal force factors for elements of structures (Ap & Rp)

Answer 3

Ap = 1.0 or 2.5 from ASCE7 - table 13.5.1 architectural and table 13.6.1 for mechanical & electrical components

Question 4

rigid component

Answer 4

Ap = 1.0 or fund. period less than or = 0.06 second (T ≤ 0.06 second)

Question 5

flexible

Answer 5

Ap = 2.5 and fund. period T > 0.06 second

Question 6

horizontal force factors (Ap & Rp) 6.5

Answer 6

mechanical & electrical Tp = 2∏ √Wp/(Kp x g)

Question 7

where Tp, Wp, g, and Kp = ?

Answer 7

Tp = component fund. period, Wp = component operating weight, g = acceleration gravity 32.2 ft/sec^2 or 386.4 in/sec^2 and Kp = stiffness support system