Derivatives Flashcards
For a function f to be differentiable at x=a, the function has to be..
If f is differentiable at a point x0, then f must also be continuous at x0. In particular, any differentiable function must be continuous at every point in its domain. The converse does not hold:
A continuous function need not be differentiable. True or False?
True. A continuous function need not be differentiable. For example, a function with a bend, cusp, or vertical tangent may be continuous, but fails to be differentiable at the location of the anomaly.
Example of of a function which is continous but not differentiable.
An ordinary cusp on the cubic curve (semicubical parabola) x3 – y2 = 0, which is equivalent to the multivalued function f(x) = ± x3/2. This relation is continuous, but is not differentiable at the cusp.
Rolle’s theorem
If a real-valued function ƒ is continuous on aclosed interval [a, b], differentiable on the open interval(a, b), and ƒ(a) = ƒ(b), then there exists a c in the open interval (a, b) such that f’(c) = 0.
Indian mathematician Bhāskara II (1114–1185) is credited with knowledge of Rolle’s theorem.[1]
Mean Value Theorem
For any function that is continuous on [a, b] and differentiable on (a, b) there exists some c in the interval (a, b) such that the secant joining the endpoints of the interval [a, b] is parallel to the tangent at c.
Proof of Mean Value Theorem
- Let g(x) = f(x) − rx, where r is a constant.
- Since f is continuous on [a, b] and differentiable on (a, b), the same is true for g.
- Choose r so that g satisfies the conditions of Rolle’s theorem.
- Since g is differentiable and g(a) = g(b), there is some c in (a, b) for which g′(c) = 0, and it follows from the equality g(x) = f(x) − rx that,
Which theorem do we use to prove the Mean Value Theorem
Rolle’s theorem
If f is differentiable at x = a then
The limit h approaching 0, (f(a+h) - f(a))/h
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