Algebra-RatioProportionWork Flashcards
At a time of day when a 12 foot flagpole casts a 7 foot shadow, how long is the shadow of a 5 foot person?
The ratio (height of object)/(length of shadow) is constant:
(height_of_object)/(length_of_shadow)=12/7.
5/x = 12/7
=> x = 35/12
How do you write the fraction 12/5 in Latex?
$ \frac{35}{12} $
Lee can make 18 cookies with two cups of flour. How many cookies can he make with three cups of flour?
(18 cookies)/(2 cups_of_flour) =(x cookies)/(3_cups_of_flour)
=> x = 27
Amount of butter, number of cookies you can bake. DP or IP?
DP
Speed you drive, time to get to destination
IP
Base of a triangle, area of a triangle (assume the height stays the same)
DP
Side length of a square, area of a square
Neither! Although doubling the side length does increase the area, it doesn’t double it - it quadruples it! To get DP, you actually need the ratio of these ideas to be CONSTANT. Here, it is (s^2)/s=s, which isn’t a constant. Be careful.
A rectangle is formed by increasing one pair of sides of a square by 25 percent. By what percent must the other two sides be decreased to form a new rectangle with the same area as the original square?
The product LW is constant. => L and W are in inverse proportion.
In a square, L_square = W_square.
To increase by 25% means to take the original length s and to add 25% of s.
s+(25/100)⋅s=s+(1/4)⋅s=(5/4)⋅s
==> L_rect=(5/4)⋅s L_square * W_square = L_rect * W_rect ==> s⋅s = L_rect ⋅ W_rect ==> s⋅s = (5/4)⋅s⋅ W_rect ==> W_rect = (4/5)⋅s
==> We start with s (or 1⋅s), and we end with 0.8s. Thus, the change is 0.2s=20% of the original width.
Two quantities are in direct proportion if ….
Two quantities are in direct proportion if their ratio remains constant.
Two quantities are in inverse proportion if …
Two quantities are in inverse proportion if their product remains constant.
What is the fundamental equation relating rate, time and distance?
d=rt
if the rate is held constant, what do we know about time and distance?
If the rate is a constant, then we have d/t=constant. Direct Proportion.
if the distance is constant, then what’s the relationship between rate and time?
IP. If distance is constant, then rt = constant. So rate and time are inversely proportional.
If we double the rate of speed, keep distance constant, what happens to time?
if we double our rate of speed, then we can cover the same distance in half the time.
If I drive to work at 50 miles per hour, it takes me 40 minutes to get to work. How long will it take me to get to work if I drive at 60 miles per hour?
40*50=60t 40*5=6t 20*5=3t 100=3t 33 1/3