Deducing Structures from Mass Spectra Flashcards
what would the m/z values for CH3+, OH+ and CO+ be
- CH3+ = 15
- OH+ = 17
- CO+ = 28
what would the m/z values be for CH3CH2+, CHO+, CH3CH2CH2+, CH3CHCH3+ and CH3CO+
- the first two = 29
- the last three = 43
the compounds A and B have the molecular formula C3H6O, with A’s spectrometry having peaks at m/z = 15, 29 and 58 while B’s has 15, 43 and 58. using this knowledge and the m/z values of the previous ions, what would the name of molecule A be
- C3H6O+ has the RAM of 58 so it doesnt help
- theres a peak at 15 for both so it doesnt help either
- the peak at 29 could either be CH3CH2+ or CHO+
- 58-29 = 29, but because there r no other ions or combination of ions = 29, its simply must be those two
- so the structure is CH3CH2CHO, meaning its an aldehyde (propanal)
what would molecule B be
- peak at 58 doesnt help
- the peak at 43 and 15 add up to 58 so there is an ion for each
- the only ion for 15 is CH3+
- out of the three ions for 43, only CH3CO+ has two carbon atoms which would match up with CH3+ to correctly have 3 carbon atoms, not 4
- therefore the structure is CH3COCH3, making it a ketone (propanone)
what would be the equation for the formation of the ions that form molecule A
(CH3CH3CHO)+ = CH3CH2+ + CHO. or with opposite signs
what would be the equation for the formation of the ions that form molecule B
(CH3CHCH3)+ = CH3CO+ + CH3.
what is the relative molecular mass of C3H8O
60
compound C has peaks at 60, 15 and 31 whereas D has peaks at 60, 15 and 45. with the ion CH2OH+ = 31 and COOH+ or CH3CHOH+ = 45, what is the structural formula of C
- they both have peaks at 60 so it doesnt distinguish
- they both have peaks at 15 so same thing but we know CH3+ is there
- the peak at 31 means CH2OH+ ion is present too
- this leaves an uncharged CH2 group to fill in the gap and one C and 2 H are missing
- making CH3CH2CH2OH (propan-1-ol)
what is the structural formula of D
- the peak at 15 means CH3+ is there
- peak at 45 mean one of the two ions for that m/z value are present
- however it cant be COOH+ as there are 2 oxygens
- so it has to be CH3CHOH+ combined with CH3+
- giving CH3CH(OH)CH3 (propan-2-ol)