D-block ions colours Flashcards

1
Q

Excess NH3 (aq) added to [Cu(H2O)6]2+

A

pale blue [Cu(H2O)6]2+ to dark blue [Cu(NH3)4(H2O)2]2

[Cu(H2O)6]2+ + 4NH3 –> [Cu(NH3)4(H2O)2]2+ + 4H20

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2
Q

Excess ammonia added drop wise to [Cu(H2O)6]2+

A
  • pale bue Cu(OH)2 will from first
  • The Cu(OH)2 precipitate then dissolves in excess ammonia to form the dark blue [Cu(H2O)2(NH3)4]2+
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3
Q

Excess concentrated hydrochloric acid added to [Cu(H2O)6]2+

A

pale blue [Cu(H2O)6]2+ to yellow [CuCl4)2-

[Cu(H2O)6]2+ + 4Cl- –> [CuCl4]2- + 6H20

*Pale blue - green (mix of both colours) - yellow

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4
Q

Chromium (III) potassium sulfate dissolved in water

A

[Cr(H20)6]3+ A pale purple solution

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5
Q

Chromium (III) Sulfate dissolve in water

A

[Cr(H2O)5SO4]+ A green solution

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6
Q

[Cr(H2O)6]3+ will excess ammonia (aq)

A

[Cr(NH3)6]3+ a purple precipitate/solution

[Cr(H2O)6]3+(voilet) + 6NH3 –> [Cr(NH3)6]3+(purple) + 6H20

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7
Q

[Cr(H2O)6]3+ aqueous ammonia added dropwise

A
  1. initially a grey-green precipitate Cr(OH)3 formed
  2. Cr(OH)3 precipitate dissolves in the excess ammonia to from [Cr(NH3)6]3+ (purple)

violet - grey green precipitate - purple

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8
Q

Cu2+ with NaOH

A

Cu2+ + 2OH- –> Cu(OH)2 (s) (insoluble in excess sodium hydroxide)

blue solution to blue precipitate

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9
Q

Fe2+ with NaOH

A

Fe2+ + 2OH- –> Fe(OH)2 (insoluble in excess sodium hydroxide)
Pale green solution to form a green precipitate (turns brown at its surface through oxidation)

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10
Q

Fe3+ with NaOH

A

Fe3+ + 30H- –> Fe(OH)3 (insoluble in excess sodium hydroxide)

pale yellow to form an orange brown precipitate

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11
Q

Mn2+ with NaOH

A

Mn2+ + 2OH- –> Mn(OH)2 (insoluble)

pale pink to light brown precipitate (darkens in air)

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12
Q

Cr3+ with NaOH

A

Cr3+ + 3OH- –> Cr(OH)3
Violet to grey-green precipitate
Soluble in excess sodium hydroxide
Cr3+ –> Cr(OH)3 –> [Cr(OH)6]3- (dark-green solution)

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13
Q

Reaction with ammonia with [Cr(H2O)6]3+ and [Cu(H2O)6]2+

A

Cu2+ + 2OH- –> Cu(OH)2 (blue precipitate) dissolves in excess ammonia to form [Cu(NH3)4(H2O)2]2+ deep blue.

Cr3+ + 3OH- –> Cr(OH)3 (green precipitate/grey green) dissolves in excess ammonia to form [Cr(NH3)6]3+ purple solution

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14
Q

Reaction with ammonia with Fe2+, Fe3+ and Mn2+

A

reacts with same way they react wot aqueous sodium hydroxide forming
- Fe(OH)2 (s)
- Fe(OH)3 (s)
- Mn(OH)2 (s)
no further reactions as precipitates do not dissolve

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