CP 3 Stoichiometry

Question 1

How do we use moles as a conversion factor

Answer 1

of particles x 1 mol / 6.022x10^23 = # of moles

of moles x 6.02x10^23 / 1 mole = 3 of particles

Question 2

TF 1 mole of c-12 atom is exactly 12 grams

Answer 2

T

Question 3

How do we find the molar mass of CO2

Answer 3

Mass of C = 12.01 amu
Mass of O = 15.999 amu
Mass of O = 15.999 amu
- add all together = 44.009

Question 4

How many moles of Ca are in 20g of Ca

Answer 4

mass of Ca = 40.078g

20gCa x 1 mole Ca / 40.078g = 1/2 mole Ca

Question 5

what is the Law of conservation of mass

Answer 5

Mass of reactants equals mass of products