Convolution Flashcards
if there is a linear system p(t) = q(t), what is the differentiation of p(t) equal to
d/dt[p(t)] = d/dt[q(t)]
if there is another linear system f(t) = y(t), what is the sum of f(t) and p(t) equal to
f(t) +p(t) = q(t) + y(t)
what does 5f(t) + 3p(t) equal
5f(t) + 3p(t) = 5y(t) + 3q(t)
what does a basic unit step function H(t) look like on a graph
- the line stays at H(t) = 0 for t < 0
- then when t = 0 it instantly shoots up to H(t) = 1
- and the line remains at H(t) = 1 forever
what does a delta / impulse function δ(t) look like on a graph
a vertical spike at a given x-axis value
what is the area of an impulse function spike
1
what is the derivative of a step function or step response
an impulse function or impulse response
what is the response of a function in this case
- the less ideal, more realistic version of the function’s behaviour
- because step and impulse functions act in very short time periods they are ‘modelled’ to have instantaneous reactions
- but step / impulse responses show the more ‘capacitor-like’ behaviour of these movements
if you have an impulse function δ(t-b), where is the spike
at t = b
if you have an arbitrary function f(t), what is the product of δ(t-b)*f(t)
δ(t-b)*f(t) = f(b)
what is the important trick to remember when evaluating whether the integration of the product of an arbitrary function and an impulse function is automatically 0
- work out the value of t in the impulse function bracket to get δ(0)
- if this value of t does not lie within the integration boundaries, the integration is automatically 0
if the value of t lies within the integration boundaries, what is another trick for making the integration easy
- simply input that value of t into the arbitrary function and thats your answer
- no actual integration is needed
for finding the step response to a differential equation that equals f(t), what is the first step
set f(t) = 1 and find the general solution
what is the second step
- set the boundary conditions y(0) = 0 and solve for the constant
- if its a second order system set y’(0) = 0 too
what is the third step
- write in the curly brackets that y = 0 for t < 0
- and y = the solution found for t => 0