Conversions/Equation Flashcards
Converting Celsius to Kelvins
273 + Celsius = K
Converting Kelvin to Celsius
K - 273 = C
Converting to different units
King Henry Died By drinking chocolate milk
K H D B d c m
B= grams, meters, liters B is the base ex) 1056 cm -> ? m You start at c and then you need to go to B in order to do this you move the decimal point to the left 2 places... meaning 1056cm = 10.56 m
Percent Error
Experiement value - accepted value
—————————————————— x 100
accepted value
Determine rounding when dividing or multiplying numbers
LEAST SIG FIGS ex) 0.00000016/ 74.3 ^2 ^3 Answer must be in 2 sig figs = 2.2 x 10^-9 (10 doesn't count)
Determining rounding when adding or subtracting
LEAST Decimal Places
ex) 17 - 3.88
^0 ^2
Answer must have ZERO decimal places
=13
1 mol = ________ molecules
AVOGRADOS NUMBER
6.02 x 10^23 molecules
lets convert from grams to atomic mass
Grams
AMU x Mol
atomic mass
AMU
g/mol
cation
pos charge
SMALLEST IONIC RADIUS
anion
neg charge (ion)
LARGEST IONIC RADIUS
Atomic Mass
(% x mass) + (% x mass) + ….
note: % should be in decimals
use when given multiple amu and dif percents
% composition
use atmoic mass formula but replace % with x
ex) atomic mass (63.546) = ( y x mass [62.9296]) + ( {1 - x} x mass [64.9278])
to find 2nd % composition must subtract original answer by 1
ex) 1-0.6915
Empirical Formula Steps
1) change % to grams (same value)
2) convert grams to mols with molar mass
3) divide by smallest number of mols
4) multiply the values found to get a whole #
- 0.5 x 2
- 0.33 and 0.66 x 3
- 0.25 and .75 x 4
ex) Cr1O1.5 -> Cr2O3
Molecular Formula Steps
1) Find Empirical Formula
2) Change % to grams
3) grams to mols (note molar mass is atomic mass)
4) divide by smallest # of moles
5) Write empirical formula
6) Find molar mass of empirical formula
7) divide molecular formula molar mass by empirical formula molar mass
8) multiple whole # found above to the subscript of empirical formula
Charges where found in periodic table
Skipping transition metals left to right
+1, +2, +3, +4, -3, -2, -1, 0
Balancing ionic compounds with transition metal NAMING
-name of transition metal
- roman numeral (charge)
ex Iron [III] = Fe 3+
-nonmetal ending in ide
Ammonium
NH4+
Cyandide
CN-
Hydroxide
OH-
Acetate
C2H3O2-
Perchlorate
ClO4-
Chlorite
ClO2-
Chlorate
ClO3-
ate and ite rule
-ate always has 1 more oxygen than -ite
Hypochlorite
ClO-
Nitrate
NO3-
Nitrite
NO2-
Carbonate
CO3 2-
Chromate
CrO4 2-
Sulfate
SO4 2-
Sulfite
SO3 2-
Phosphate
PO4 3-
Phosphite
PO3 3-
Bromate
BrO3-
Iodate
IO3-
Dichromate
Cr2O7 2-
Covalent Prefixes
1, 2, 3, 4, 5
1 mono 2 Di 3 Tri 4 Trenta 5 Penta
Covalent Prefixes
6,7,8,9,10
6 Hexa 7 Hepta 8 Octa 9 Nona 10 Deca
Combustion Reaction
CxHy + O2 –> CO2 + H2O
Actual yield
givens in problem (actual)
Theoretical yield
whatever our limiting reactant produces
must use conversions to get from one element to another
Percent Yield
actual yield
————————– x100
theoretical yield
Molarity
liters of solution
1 L = ____mL
1000
1kg = ____g
1000
Gas Law given pressure and volume
P1V1 = P2V2
Gas Law given volume and temp
TEMP MUST BE IN KELVIN
V1/T1 = V2/T2
Gas law given pressure volume and temp
KELVINS
P1V1/T1 = P2V2/T2
Gas Law given pressure and temp
KELVIN
P1/T1 = P2/T2
Gas law given volume and mols
V1/n1 = V2/n2
Ideal Gas Law (no 2nd values)
PV =nRT
R= 0.0821
Calorimetry
q= mC△T
q=heat kJ or J m= mass in g Cs = specific heat capaticity J/g°C △T= change in temp CELCIUS FINAL - INTIAL
Exceptions to Octet Rule
-groups that do not have 4 electrons (always incomplete)
ex B and Be
-an expanded octet has 8+ electrons on central atom 3RD ROW AND BELOW
Formal Charge
FC= valence E - (Bonding electrons (touching) + Individual lone pair)
CENTRAL ATOM MUST = ZERO FOR LEWIS DIAGRAM TO BE CORRECT
S
1 orbital, 2 electrons
P
3 oribitals, 6 electrons
d
5 orbitals, 10 electrons (5 x 2)
needs to be in 5-10 range to be stable
f
7 orbitals, 14 electrons
electron configuaration exceptions s,p,d,f
Cr : [Ar] 4s1 3d5
Cu : [Ar] 4s1 3d10
because d wants to be full/half full
so we take 1 from 4s to fulfill
Atmoic Radius increases
leftward, downward
Ionization energy increases
rightward, upward
ionization energy exceptions
2a and 3a (2a larger)
5a and 6a (5a IE bigger)
pH
-log[H+]
pH and pOH equation
pH + pOH = 14
OH-
10^-pOH
units in molarity
H+
10^-pH
H and OH equation
[H+] x [OH-] = 1 x 10^-14
pOH
-log[OH-]
propane
C3H8
Methane
CH4