CONSTRUCTION ESTIMATE

Question 1

Determine the number and cost of 50kg Cement bags, volume and cost of Sand and Gravel for a concrete slab using class “C” mixture and with dimensions of 5.00m x 3.00m x 0.10m. Compute the cost of materials with unit cost of Cement bags at P250.00 per bag and Sand and Gravel at P150.00 per cubic meter.

Answer 1

5x3x0.1
V= 1.5 CU. M

1. 5*5 = 7.5 = 8 BAGS OF CEMENT
2. 5*1 = 1.5 CU. M OF GRAVEL
3. 5*0.5 = 0.75 CU. M OF SAND

8*250 = 2000 PESOS

1. 5*150 = 225 PESOS
2. 75*150 = 112.5 PESOS

Question 2

Determine the Quantity, Length and Board Feet needed for the 2”x8”x10’ Girder (10PCS) and 2”x6”8’ Joist (15PCS). Compute the cost of each at P16.00 per Board Feet.

Answer 2

(2\*8\*10\*10)/12 = 133.33
133.33\*16 = 2133 PESOS

(2\*6\*8\*15)/12 = 120
120\*16 = 1920 PESOS

Question 3

Determine the Quantity of 20cm x 20cm floor tiles, Portland cement paste, and White cement paste filler (grout) for a floor area of 5.00m x 3.00m. Compute the cost of materials with a unit cost of floor tile at P45.00 per tile, Portland Cement paste at P250.00 per bag, and Grout at P150.00 per kilogram

Question 4

A proposed concrete pavement has a general dimension of 10cm THK, 3.00m wide, and 5.00m long. Determine the quantity of cement in bags, sand, and gravel in cubic meters, required using Class C mixture, 40KG Bags.

Answer 4

Step 1: Determine the volume of the proposed concrete pavement

Volume = Thickness x W x L
V = 0.10 x 3 x 5
V = 1.50 cubic meter

Step 2: Refer to the table and use the multiplier. Multiply volume to corresponding values.

Cement: 1.50 x 6.0 = 9 bags
Sand: 1.50 x 0.50 = 0.75 cu. m
Gravel: 1.50 x 1.00 = 1.50 cu. m

Question 5

A concrete hollow block wall has a general dimension of 3.00 m high by 4.00 m long. Determine the number of CHB, cement, and sand required to construct the wall.

Answer 5

Fundamental Method:

Step 1: Divide the height of the fence by the height of one block.
3.00 / 0.20 = 15 layers

Step 2: Divide the length of the fence by the length of one block
4.00 / 0.40 = 10 pieces

Step 3: Multiply the result of Steps 1 and 2
15 x 10 = 150 pieces

Area Method:

Step 1: Determine no. of CHB per SQM
1.00 m x 1.00 m = requires 12.5 pieces of CHB

Step 2: Get the Area of the Fence
3.00 m x 4.00 m = 12 SQM

Step 3: Multiply with the Multiplier
12.00 SQM x 12.50 = 150 pieces

Question 6

A CHB wall has a general dimension of 3.00 m high by 4.00 m long. Determine the mortar needed.

Answer 6

Area Method:

Step 1: Find Area of Wall

A = 3 x 4 m =12sqm

Step 2: Multiply referring to the table Class B mixture.

Cement: 0.522 x 12.00 = 6.26 bags
Sand: 0.435 x 12.00 = 522 cu m

Question 7

A CHB wall has a general dimension of 3.00 m high by 4.00 m long. Determine the plaster needed.

Question 8

Compute the following for a 3.00m x 5:00m wall:

• Quantity of CHB (0.15 x 0.20 x 0.40) used
• Amount of Cement and Sand used for Block Laying (Class B Mix)
• Amount of Cement, Sand, and Gravel for CHB wall footing
• Amount of Cement, Sand, and Gravel for Posts and Post Footing
• Amount of Cement and Sand for Plastering both sides of the wall (including posts)
• Amount of 10mm dia. rebars for CHB wall footing and CHB wall
• Total cost of materials of wall assuming
  
  • Cement = P130.00 per bag
  • Sand = P450.00 per cu. m
  • Gravel = P400.00 per cu. m
  • CHB = P8.00 per piece

Question 9

Given:

35 SQM
36 tiles (0.60 x 0.60 M)
4 Clusters

Questions:

1. Size of the tile that would perfectly fit the remaining space
2. Band width space between clusters