connected particles Flashcards

1
Q

what are the 3 assumptions when working with connected particles?

A

string is light - tension is the same

string is inextensible - acceleration is the same at both ends

pulley is smooth - tension is equal on both sides of the plane

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2
Q

what is newtons third law?

A

for every action, there is an equal and opposite reaction

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3
Q

what kind of connectors are used in connected particles?

A

either use a light inextensible string (which will always be taut or a solid rod, which is also light

if the string is taut, tension works in both directions equally

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4
Q

how do you find the acceleration of connected particles?

A

take the total resultant force and the total mass of the whole system and divide force by mass

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5
Q
A
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6
Q

how do you find tension in the connector between 2 bodies?

A

use the mass of ONE BODY with the overall acceleration to find the tension since tension =+ opposite to force exerted by one body to the other

trust me it works

ALWAYS ESTABLISH A POSITIVE DIRECTION

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7
Q

how do you find acceleration of masses connected by pulley?

A

work with each mass separately, defining positive direction as down.
establish which mass is heavier; this will be the mass moving down, hence acc will be down. for the other mass, acc. will be equal but up so if mass B is heavier than A then express T:
T - Ag = Aa where g = 9.8 and
-T + Bg = Ba a = acc.
solve these simultaneously.
this will give acc and tension

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8
Q

how do you deal with connected bodies when movement of one stops but the other continues?

A

separate the motion into halves.
first half: how whole system behaves, suvats until collision.
second half: using final v from first half, use suvats and RF manipulation

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9
Q

how do you deal with connected particles on a slope?

A

resolve wight components first, (using trig ratios) then find resultant forces and follow procedure for norman pulley system (RF = ma for each plane, solve simultaneously)

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10
Q

how do you find overall tension on a pulley?

A

reorganise into a force triangle and solve trigonometrically, alternatively use equation

2T Cos θ = total force

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