Compounds and Stoichiometry Flashcards
Molecule:
combination of two or more atoms held together by covalent bonds
Formula unit:
representing the emperical formula of the compound
Formula weight:
found by adding up the atomic weights of the constituent ions according to its empirical formula
Atomic weight:
a weighted average of the masses of the naturally occuring isotopes of an element not their weights
Molecular weight:
the sum of the atomic weights of all the atoms in a molecule
Mole
quantity of any substance equal to the number of particles that are found in 12 grams of carbon 12
Avogadro’s number (NA):
6.022 X 10^23 mol^-1
Molar mass:
The mass in grams of one mole of an element or compound
Moles =
mass of sample (g) / molar mass (g/mol)
Equivalents:
A mole of charge in the form of electrons, protons, ions or other measerable quantities that are produced by a substance
Gram equivalent weight=
molar mass/n
Equivalents=
Mass of compound (g)/ gram equivalent weight (g)
Normality (N):
A concentration unit equal to the number of equivalents per liter of solution
Molarity=
Normality/n
Calculate the molar masses of the following substances: NaBr
23 + 80 = 103 g/mol
Calculate the molar masses of the following substances: SrCl2
87.6 + (2 x 35.5) = 87.6 + 71 = 158.6 g/mol
Calculate the molar masses of the following substances: C6H12O6
(6x12) + (12 x 1) + (6 x 16) = 180 g/mol
Calculate the number of moles in 100g of each of the following substances: NaBr
100g /103 g/mol = 0.97 moles
Calculate the number of moles in 100g of each of the following substances: SrCl2
100g/ 158.6 g/mol = 0.625 moles
Calculate the number of moles in 100g of each of the following substances: C6H12O6
100g/ 180 g/mol = 0.555 moles
How do the number of molecules in 18 g of H2O compare to the number of formula units in 58.5 g of NaCl?
both values equal one mole of the given substance. The number of entities in a mole is always the same (6.02 x 10^23)
Determine the normality of the folowing solutions. (Species of interest is H+) H3PO4
N = M x [equivalents/ mole]
0.25 M x [ (3 equiv H+)/ mol H3PO4] = 0.75 N H3PO4
Structural formulas:
the graphic representation of a molecule depicting how its atoms are arranged
Law of constant composition:
any pure sample of a given compound will contain the same elements in an identical mass ratio
Emperical formula:
gives the smallest whole number ratio of atoms of each type in the compound
Molecular formula:
exact number of atoms in an element in the compound and is a multiple of the emperical formula
Percent composition:
the percent of a specific compound that is made up of a given element
Percent composition:
[Mass of element in formula/ molar mass] x 100
What are some similarities and differences between molecular and emperical fomulas?
both the molecular and emperical formulas contain the same elements in the same ratios. They differ in that molecular formulas give the actual number of atoms of each element in the compound; emperical formulas give only the ratio and therefore may or maynot give the actual number of atoms
Combination reaction:
has two or more reactants forming one product
Example of a combination reaction:
2 H2 (g) + O2 (g) -> 2 H2O (g)
Decomposition reaction:
opposite of a combination reaction: a single reactant breaks down into two or more products, usually as a result of heating, high frequency radiation ot electrolysis
Example of a decomposition reaction:
2HgO (s) -Δ-> 2Hg (l) + O2 (g)
Combustion reaction:
a special type of reaction that involves fuel (usually a hydrocarbon), and an oxidant (normally oxygen)
Example of a combustion reaction:
CH4 + 2O2 -> CO2 + 2H2O
Single-displacement reaction:
occurs when an atom or ion in a compound is replaced by an atom or ion of another element
Example of a single-displacemnt reaction:
Cu (s) + AgNO3 (aq) -> Ag (s) + CuNO3 (aq)
Double-displacement reaction:
elements from two different compounds swap places with each other to form two new compounds
Another name for double-displacement reaction:
metathesis reaction