Clinical Electron Beams Flashcards

1
Q

What is changed between a linac in its photon mode or electron mode?

A

The electron gun current is reduced to significantly decrease the dose rate.

A primary and secondary scattering foil is positioned in the head to spread out the beam and flatten the beam, respectively.

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2
Q

How are electron beams collimated and why?

A

Electrons are collimated with applicators added to the head of the linac.

These are necessary as MLCs and jaws are not useful due to the significant scattering of the electrons in air. Therefore, the applications should be positioned as close as possible to the surface of the patient.

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3
Q

How can electron energy be characterised?

A

Possible metrics are:

1) Maximum energy, E_{m}
2) Probable energy, E_{p}
3) Mean energy
4) Energy spread

Note that mean energy and E_{p} will decrease with depth, while energy spread will increase.

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4
Q

How does an electron PDD change with increasing energy?

A

1) D_{max} will increase with energy.
2) The relative surface dose increases with energy (note that surface doses from electron beams is significantly greater than observed with photon beams).
3) The contribution from the bremsstrahlung tail increases.

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5
Q

What causes the build-up region for electron beams? And how is this different than with photon beams?

A

The deeper into the medium, the more oblique the path of the electrons. This means that there are more interactions per unit length. This results in a build-up of dose at depth.

Photon beams have a build-up region resulting from the generation of secondary charge carriers, which propogate the energy from the interaction site.

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6
Q

How is SDD defined for electron beams?

A

The SDD is defined as the position at which the electron beam appears to diverge from.

This is the result of scatter within the head of the linac. Therefore, the electrons appear to come from a different position than observed with photon beams.

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7
Q

How is the Virtual source distance (VSD) determined?

A

Solve the following for f:

( I_{0] / I_{g} )^{-1/2} = (g / [f+d] )+1,

where I_{0} and I_{g} are two beam intensities for beams with different SSDs, d is a constant representing the measurement depth, g is the different between the two SSDs used, and f is the VSD.

Note that the VSD will vary between linac models and is head specific.

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8
Q

What is an alternative method for determining VSD, other than simply using two SDD measurements?

A

Measuring the differences in beam intensities for a number of different SSDs, and plotting the square root of their ratios versus the difference in the SSDs will produce a linear scatter plot. The gradient of the resultant relationship is equal to 1/(VSD + d), where d is the measurement depth.
This can be solved for VSD.

[Alternatively, plot the square root of the ionisation current against the distance from a 100 cm SSD and the x-axis intercept will be the VSD.]

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9
Q

How is electron beam quality defined?

A

R_{50,D} - that is the depth in water where the adsorbed dose has fallen to half its maximum for a 100 cm SSD beam.

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10
Q

How is the reference depth, z_{ref}, for electron beams defined?

A

z_{ref} = 0.6 R_{D,50} - 0.1, [units of cm]

where R_{D,50} is the depth at which the beam quality is defined.

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11
Q

Why is R_{100,D} not used as the beam quality for electron beams?

A

The difference between different linac models at higher energies becomes apparent at depth of maximum dose causing in inconsistencies. Furthermore, the PDD is relatively flat about R_{100, D}; increasing uncertainty.

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12
Q

Why is the definition of z_{ref} used? (electron beams)

A

This quantity has been found return a correspondence between the stopping powers and R_{50,D} over a range of manufacturers.

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13
Q

How is R_{50,D} determined? (electron beams)

A

R_{50, I} is measured with an ion chamber.

R_{50,D} = 1.029 R_{50,I} - 0.063 [units of cm]

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14
Q

How is a PDD measured for an electron beam?

A

1) Measure the raw PDD with an ion chamber.
2) account for the change in stopping powers with changing depth, and apply the appropriate factor to convert to absorbed dose.
3) apply perturbation and ion recombination corrections.

[Alternatively, a suitably commissioned diode may be used.]

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15
Q

What is the empirical formula for determining whether a phantom is large enough to measure the bremsstrahlung tail for an electron beam?

A

= 5 + 1.25 R_{50,I} [units in cm]

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16
Q

What is the issue with using non-water phantons when considering electron beam measurements?

A

Some materials such as PMMA can result in charge storage effects.

Recommended materials are advised within the electron code of practice. It is also best practice to use slabs with at least 1.2 cm thickness and to cover the chamber in a sheath with the same material as the medium.

It is necessary to account for the change in the water equivalent path length of the electrons by taking ratios of the stopping power ratios.

Finally, need to verify against a water phantom.

17
Q

What is the NPL’s method for calibrations a secondary standard?

A

1) A graphite calorimeter is used as the primary standard.
2) Then z_{ref, w} is water with their standard.

3) Range scaling is used to account for the graphite as follows:
z_{ref, g} = z_{ref, w} x ( R_{50,g} / R_{50,w} )

4) Then calibrate chamber against the calorimeter, in graphite at z_{ref,g}; as follows:
N_{ref,g} = ( D_{ref,g} / M_{ref, g} )

5) Then convert from graphite to water as follows:
N_{D,ref,w} = N_{D,ref,g} x ( p_{ref,w} / p_{ref,g} ) x ( s_{w/air} / s_{g/air} )

6) Compare user chamber against the reference chamber:
N_{D,user,w} = N_{D,ref,w} x (M_{ref,w} / M_{user,w} ).

[process is defined more clearly in COP]

18
Q

Why not use higher voltages in ion recombination measurements?

A

Over measurements due to electron cascade.

Can warp the shape of the chamber.

Can produce a charge from the insulator.

19
Q

Outline the 3 types of electron interaction with matter.

A

1) Elastic scatter with the nuclei, resulting in scatter but little energy loss.
2) Inelastic collisions with atomic electrons. Resulting in ionistions and excitation.
3) Inelastic collisions with the nuclei; bremsstrahlung and characteristic radiation.

20
Q

Define electron path length, range and range straggling.

A

Path length - the total distance travelled by an electron.

Range - the displacement of an electron in a given direction.

Range straggling - the effect of the probablistic impact of electronic interactions. Therefore, electrons with the same initial energy travel to different depths.

21
Q

What makes a clinical electron beam appealing?

A
  • High surface dose
  • Steep dose fall off
  • low photon contamination dose.
22
Q

Define therapeutic range and interval.

A

Therapeutic range - depth of the most distal isodose contour used for treatment.

Therapeutic interval - the distance between the isodose contours used for treatment.

(typically defined as 90% or sometimes 95% of max dose).

23
Q

Describe the characterisics of an electron isodose curve.

A
  • Applicator size is typically greater than the width of the 80% isodose.
  • Surface dose is dependent on beam energy, distance from applicator, and use of cutouts.
  • Low energy electrons at depth experience larger scattering angles, thus a bulging is experienced.
  • High isodose levels are constricted laterally at depth relative to the central axis.
24
Q

What is the effect on an electron PDD with increasing energy and why?

A
  • Increase in surface dose due to decrease in the relative doses between the surfacs and d_{max}.
  • Decrease in rate of fallout as there is greater contribution from more energetic electron at depth.
  • bremsstrahlung tail contribution increases.
25
Q

What are the characteristics of a smaller field sized electron PDD?

A
  • d_{max} drifts toward the surface.
  • surface dose increases.
  • practical range is unchanged.
26
Q

What is the effect of bone in the electron beam?

A
  • Higher density thn soft tissue. Therefore, increased attentuation.
  • Increased scattering per unit length.
  • Increased dose in bone.
  • Increased dose adjacent to bone due to scatter.
  • Decreased dose beyond bone.
27
Q

What is the effect of lung and air in the path of an electron beam?

A
  • Less attenuation

- Less scatter per unit depth (needs to be corrected for).

28
Q

What is the effect of a high z medium in electron beam?

A
  • Electrons are scattered away form high density material to low density material.
  • Results in increased electron fluence and dose scatter lobes in low density or Z material.
29
Q

What is the effect of a surface obliquities in electron beams?

A

On an angled surface, the dose is brought to the surface and the isodose contours also move toward the surface.

30
Q

What is the effect of an oblique electron beam on a flat surface?

A

Isodoses are tilited, but remain parallel to surface.

31
Q

What is the effect if a curved surface meaning an electron beam?

A

Isodoses run parallel to the skin surface.

32
Q

What is the impact of increasing the SSD of a clinical electron beam?

A
  • Useful treatment volume reduces, due to convergin high dose isocontours.
  • More scatter means diverging of low dose electrons.
33
Q

What is the effect of bolus on electron beams?

A

Shift PDD towards the surface of the patient.

When considering bolus thickness, consider the therapeutic interval and surfce dose.

34
Q

How to increase the therapeutic interval for electron beams?

A
  • Alter the energy of the beam (more bremsstrahlung and reduced gradient in fallout region of PDD).
  • Use thin foils on surface to act as a scatter to increase the dose at the surface. This will increase the scatter, but results in less energy loss than with bolus.
35
Q

How to increase the therapeutic interval for electron beams?

A
  • Alter the energy of the beam (more bremsstrahlung and reduced gradient in fallout region of PDD).
  • Use thin foils on surface to act as a scatter to increase the dose at the surface. This will increase the scatter, but results in less energy loss than with bolus. The advantage of foi is that reduced energy can be used; meaning more tissue sparing at depth.
36
Q

What are the advantages of using cutouts with electron beams?

A
  • Spares adjacent tissue.
  • Produces more homogenious doses.
  • Reduces penumbra.
  • Reduces impact of patient motion.