Chemistry Flashcards
What are the pH of acids?
Acids = 0 - 6
What are the pH of bases?
Bases = 8 - 14
Are metal hydroxides acids or alkalis/bases?
Bases
Are metal carbonates acids or alkalis/bases?
Alkali/bases
Are metal oxides acids or alkalis/bases?
Alkali/bases
What is the difference between an alkali a base
Bases are solid, alkalis are soluable bases
Define amphoteric
Can act as an acid and a base
What is a general equation for a neutralisation reaction?
Acid + Alkali –> Salt + Water
Write balanced symbol equations for the neutralisation reactions between hydrochloric acid and sodium hydroxide.
HCl + NaOH –> H₂O + NaCl
Acid is a ___ donor
Proton (H+)
Alkalis produce what ion in solution
OH-
Alkali is a ___ acceptor
H+
Acid creates ___ in water
H+
Bases ______ an acid
Neutralises
All alkalis are ___
Bases
What is a nucleophile?
An electron rich species, e.g. a species with a long pair or a negative charge
What is an electrophile?
An electron poor species, e.g. positively charged species
Outline the mechanism for the electrophillic addition of HBr to ethene
State uses for alumina (Al2O3)
The major uses of aluminium oxide is in refractories, ceramics, polishing and abrasive applications.
Describe what happens to ions (Al3+ and O2-) when Al2O3 is electrolysed
Al3+ gains electrons and forms pure Aluminium (Reduction), O2- looses electrons and forms Oxygen gas (Oxidation)
State half equations for the reactions at the electrodes
Anode) 2O2- —> O2 + 4e- Cathode) Al3+ + 3e- —> Al
Describe the reactions at the electrodes as oxidation/reduction
The reaction at the anode is Oxidation (losing electrons), and the reaction at the cathode is Reduction (gaining electrons)
Explain why electrolysis of alumina is expensive
It’s expensive due to the large amount of electricity required to keep the alumina (bauxite) molten to allow the electrolysis to continue 24/7, 365
State uses of titanium
Titanium metal is used as an alloying agent with other metals (e.g. aluminium). Alloys of titanium are used in aerospace, aircraft and engines due to the strong, lightweight, temperature-resistant properties.
Describe the steps in the Kroll process
Step 1) Titanium (IV) dioxide, coke (form of carbon) and chlorine are heated together at 900c to form Titanium (IV) chloride. TiO2(s) + 2C(s) + 2Cl2(g) —> TiCl4(g) + 2CO(g) Step 2) Magnesium is used as a reducing agent, which reacts with the chlorine to remove it from the titanium, forming pure titanium metal, and magnesium chloride liquid. TiCl4(g) + 2Mg(s) —> Ti(s) + 2MgCl2(l)
Explain why the Kroll process is expensive
The process required very high temperatures to break the strong bonds in titanium. It’s very labour intensive. Magnesium (or other metals used) is a very expensive metal, and is used in large quantities to obtain the pure titanium.
State the definition of a transition metal
forms one or more stable ions which has incompletely filled d orbitals
State characteristics of transition metals
-have an incomplete D subshell -have variable oxidation states -forms complex ions -catalysts -coloured componds
State what a complex ion is
Complex ion - a positively charged ion that is surrounded by a number of molecules that are oppositely charged.
State what a dative bond is
Dative bond - when both electrons are donated by one molecule to form a covalent bond.
State what a ligand is
Ligand - a molecule with a lone pair of electrons e.g. water or ammonia.
State what a catalyst is
Catalyst - speeds up chemical reactions
State how a catalyst affects the rate of a reaction
catalyst lowers the activation energy by providing a different pathway
Explain why transition metals make good catalysts
-variable oxidation rates -can be oxidised and reduced (change their oxidation state) -lower thr activation energy by providing an alternitive route
Explain why transition metals form complex ions
They are small with high charge to size ratios. They have empty ‘s’ and ‘d’ orbitals to accept lone pairs from ligands.
Describe the stages of the Contact Process
Stage 1: sulfur dioxide is made (mixed with excess air) Stage 2: sulphur trioxide is made SO2 + V2O5 = SO3 + V2O4 Stage 3:sulphur trioxide is converted into sulphuric acid V2O4 + 0.5 O2 = V2O5
Describe the use of Iron in the Haber process
It makes ammonia.