Chem4 Flashcards

1
Q

What is the primary ore used in aluminum extraction and its chemical formula?

A

Bauxite, with the chemical formula Al₂O₃.

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2
Q

Why is cryolite (NaAlF₆) added to the mixture during aluminum extraction?

A

It acts as a solvent for bauxite, allowing the aluminum oxide to dissolve for electrolysis.

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3
Q

What role does fluorspar (CaF₂) play in aluminum extraction?

A

It acts as a flux, reducing the mixture’s melting point from 2045°C to 950°C, saving energy.

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4
Q

What material is used for the anode in aluminum extraction, and what happens there?

A

Graphite bars; oxidation occurs, producing O₂ gas:
Al₂O₃ → 2Al³⁺ + 3O²⁻ → 3/2O₂ + 6e⁻.

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5
Q

What material is used for the cathode, and what forms there?

A

An iron container lined with graphite; molten aluminum (Al) deposits via reduction:
2Al³⁺ + 6e⁻ → 2Al(l).

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6
Q

Write the total reaction for aluminum extraction.

A

2Al³⁺ + 3O²⁻ → 2Al(l) + ³⁄₂O₂(g).

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7
Q

Why do graphite anodes need periodic replacement?

A

Oxygen reacts with graphite, forming CO/CO₂ gases, eroding the bars:
2C(s) + ³⁄₂O₂(g) → CO(g) + CO₂(g).

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8
Q

What modern alternative improves upon cryolite in aluminum extraction?

A

A mixture of Na, Ca, and Al fluoride salts—lower melting point and density.

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9
Q

How does the modern fluoride salt mixture improve efficiency?

A
  1. Lower melting point saves energy.
  2. Lower density eases molten aluminum separation.
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10
Q

Where does metal deposition occur in all electrolysis experiments?

A

At the cathode (reduction site).

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11
Q

What gas evolves at the anode during aluminum extraction?

A

Oxygen gas (O₂).

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12
Q

Why is the high melting point of pure Al₂O₃ a problem?

A

Melting it alone requires excessive energy (2045°C); cryolite/fluorspar reduce this to 950°C.

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