chem periodic table/trends in physical properties Flashcards

1
Q

periodicity

A
  1. elements in the same group have the same properties
  2. the repeating pattern of physical and chemical properties shown by different periods is known as periodicity
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2
Q

periodicity consequence

A

periodicity consequence

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3
Q

what is the position of an element in the periodic table based on?

A

what is the position of an element in the periodic table based on?

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4
Q

in base of what are the elements placed in the periodic table?

A

in base of what are the elements placed in the periodic table?

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5
Q

what do e, p and n define?

A

e-chemical properties
p-identity
n-mass

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6
Q

periods and groups

A

periods and groups

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7
Q

metals non metals and metalloids

A

metals-metallic compound
non metals- covalent bonds
metalloids- they have the same numb of valence e as non metals (same chem prop) while they have similar phyisical prop as metals

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8
Q

name of the separate group of elements below the periodic table

A

lanthanoids and actinoids

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9
Q

exceptions in electron configuration

A

Cr has Ar 4s1 3d5 instead of 4s2 3d4
Cu has Ar 4s1 3d10 instead of 4s2 3d9

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10
Q

nucleons

A

protons+neutrons

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11
Q

half life

A

it means that it cannot be stable

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12
Q

division of energy level

A

energy levels n=1
sublevels s p d f
orbitals 1 3 5 7

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13
Q

Mn2+ electron configuration

A

remove 2 electrons
starting from the last energy level so 4s2 is before 3d10 for example (dram the triangle)

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14
Q

noble gas electron conf of I

A

Kr 5s2 4d10 5p5

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15
Q

atomic radius definition

A

the distance between the nucleus and the outermost e, but since we cannot predict the position of the e we can say that it is half the distance between the two nuclei of two bonded atoms of the same element

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16
Q

atomic radius trends

A

increases down a group- because the energy levels increase which means that the outermost e get further away from the nucleus meaning that the distance increases

decreases across a period because electrons and protons are added so there is a stronger positive charge which causes the outermost electron to be more attracted to the nucleus (nuclear charge increases=attraction between outermost e and nucleus increases)

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17
Q

ionic radius trends

A

increases down a group (with increase of neg charge)
decreases across a period (with increase of pos charge)

pos ions are smaller than their parent atom because to form a cation we are removing e from the outermost shell so the attraction between the outermost e and the nucleus increase resulting in a smaller size; so the increased attraction causes the e to move closer to the nucleus

neg ions are bigger then their parent atoms because to form anions we add e so the attraction between the outermost shell and the nucleus reduces; so there is an increase repulsion which causes the e to move further away

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18
Q

what is important to consider when answering questions about ionic radius?

A

to mention how many occupied energy levels they have so defining the pull between the outermost e and the nucleus

19
Q

which molecules exist as diatomic molecules

A

N O F CL Br I H

20
Q

How to know which ionic radius is smaller when two ions have the same e and therefore the same conf.

A

we talk about protons and who has extra protons, you calculate this by subtracting the rounded relative atomic mass and the atomic number

21
Q

outer electrons

A

-involved in chemical reactions
-do not experience full nuclear charge (they are shielded from the nucleus)
-outer e of metals experience less effective nuclear charge the the ones of non metals

22
Q

simple general trends in the periodic table

A

down a group-increase in atomic size
across a period-increase in nuclear charge

23
Q

ionization energy definition

A

-measure of attraction between the nucleus and the outer e
it is the energy required to remove 1 mol of electron from 1 mol of gaseous atoms in their ground state (kjmol-1)
Ca(g) -> Ca+(g) + e-
Ca+(g) -> Ca2+(g) + e-

24
Q

ionization energies trends

A

increases across a period-increase in effective nuclear charge so the attraction between the outer e and the nucleus is stronger=more E is required to remove the outer e

decreases down a group-increase in atomic radius, so the increased dist between the nucleus and outer e is reduces the attraction so it requires less energy to remove the outer electron

25
Q

ionization energy exception 1

A

there is a large decrease between the last element of a period and the first of the next
-because there is a rapid increase in atomic
radius
-because there is increased shielding by inner e

both out weight the increased nuclear charge

26
Q

ionization energy exception 2

A

Be and B decreases
Mg and Al decreases
because it is easier to remove an e from the 2p orbital then from the 2s orbital

27
Q

ionization energy exception 3

A

N and O decreases
P and S decreases
because it is easier to remove paired electrons then unpaired electrons

28
Q

why is it easier to remove paired electrons

A

because when e pair up there is increased repulsion therefore it is easier to remove

29
Q

shielding

A

shielding is like putting layers between the nucleus and outer electrons, making the attraction a bit weaker. It helps explain why outer electrons might not feel the full force of the positive nucleus in an atom

30
Q

nuclear charge

A

positive charge in the nucleus due to the protons
=atomic numb

31
Q

effective nuclear charge

A

net positive charge experienced by an electron in an atom, which is affected by the shielding effect from the inner e (it provides a more realistic measure of the attractive force experienced by outer electrons )

32
Q

difference between nuclear charge and effective nuclear charge

A

the first one only takes into consideration the positive charge of the nucleus without considering any electron shielding

33
Q

shielding trends

A

it increases down a group since the energy levels increase, and it decreases across a period since the nuclear charge increases

34
Q

which is larger the 2nd IE or the 1st?

A

the second it increases gradually, when there are big jumps it means that we are moving from one energy level to the next, when there are smaller shift it means that we are moving from one orbital to the other within the same energy level. it increases because when you remove an electron from a cation it is harder and requires more energy then removing it from an atom so therefore it increases every time

35
Q

equation for the 9th IE of Al

A

Al8+(g) -> Al9+(g) + e-

36
Q

IE graphs

A

from outer to inner e, the ones closest to zero are the outer e which are easier to remove, the first electrons indicate the valence e

37
Q

electronegativity

A

ability of its atoms to attract e in a covalent bond, it only applies to the consideration of covalent bonds

38
Q

electronegativity exceptions

A

noble gases do not have it since they already have a stable electron configuration

39
Q

electronegativity trends

A

same as ionization energy
-decreases because the shared pair of e is further from the nucleus
-increase because the shared pair is more strongly attracted

40
Q

electron affinity

A

energy change that occurs when an e is added to an isolated atom in the gaseous state

energy change that occurs when one mole of e is added to one mole of gaseous atoms to form 1 mole of gaseous ions

X(g) + e -> X-(g)

41
Q

exothermic

A

the process gives out energy since the e is attracted to the nucleus, the 1st is always exothermic, so negative

42
Q

electron affinity trends

A

down a group it becomes less exothermic (because less energy is realised when an e is brought into the outer most shell), across a period it become more exothermic

43
Q

electron affinity exceptions

A

oxygen, the first is exothermic while the 2nd is endothermic