Chapter 9: Linear Momentum Flashcards
An object cannot be treated as a single particle when it either ___ or ___.
Rotates; deforms/changes shape.
The center of mass (COM) of a system of particles moves as if___ and ___.
All the mass of the system were concentrated on the COM; all external forces acting on the system are concentrated on the COM.
To calculate the COM for a system of N particles of total mass M:
(mi(yi) + mi2(yi2) + mi3(yi3) + …)/M
There (must)/(need not) be actual physical mass at the location of the COM.
Need not
The COM is biased towards the particles with the (greater)/(lesser) mass.
Greater
Newton’s Second Law for the motion of COM:
a(arrowsubcom) = (F(arrowsubnetext))/M
What is the linear momentum of a particle of mass m and velocity v(arrow)?
ρ = mv
SI unit: kg * m/s
Is linear momentum a vector quantity?
Yes!
TRUE or FALSE: F(subnet) = ma(arrow) = m((dv)/(dt)) = (d/(dt)(mv(arrow)) = (dρ(arrow))/(dt)
True!
For position, velocity, and acceleration of the COM:
Use the same equation as that used to calculate the COM, substituting the position values with the independent velocity or acceleration velocities to suit your needs.
Impulse (J) is as follows: J(arrowsubnet) = (dρ(arrow))/dt = Δρ(arrow). Graphically, this is the ___ on a ___ graph.
Area under the curve on a force vs. time graph.
If the net external force on a system equals zero, then ρ(arrow) is…
Constant
If an object is falling towards Earth’s surface, and the system ONLY includes the object, momentum (is)/(is not) constant.
Is not
If an object is falling towards Earth’s surface, and the system includes both the object AND Earth, linear momentum (is)/(is not) constant, because F(arrowsubgrav) is internal, and both objects would therefore have (the same)/(different) momentum, meaning (one)/(both) have a velocity directed towards the other.
Is; the same; both.
With collisions in Chapter 9, there is no external force on the system. Therefore, ΔP = …
0; P(subix) = P(subfx)
m(sub1)v(sub1i) + m(sub2)v(sub2i) = m(sub1)v(sub1f) + m(sub2)v(sub2f)