Chapter 7 Periodicity Flashcards
How did Mendeleev organise his periodic table?
arranged using atomic mass and grouped elements that had similar properties.
–> If grouped properties did not fit, Mendeleev swapped elements around and left gaps, assuming the atomic mass measurements were incorrect
How is the modern Periodic table organised?
114 elements organised into 7 horizontal periods and 18 vertical groups
–> position is linked to physical and chemical properties
–> arranged in increasing atomic number
Groups and periods
vertical columns: groups which all have atoms with the same number of outer-shell electrons and similar properties
horizontal rows: periods
–> no on period gives number of highest energy electron shell in an element’s atom
Periodicity & properties
repeating trends in properties of elements
–> electron configuration
–> ionisation energy
–> structure
–> melting point
Trends across a period
Across period 2, 2s sub-shell fills with two electrons, then 2p sub-shell with 6 electrons e.g. Be is (He)2s^2 and Ne is (He)2s^2,2p^6
Across period 3 same pattern of filling for 3s and 3p sub-shells
Across period 4, although 3d sub-shell is involved, highest shell number=4 so from n=4, only 4s and 4p sub-shells are occupied
Trends down a group
Elements have the same number of electrons in each sub-shell (can be divided into 4 distinct blocks)
–> Group 1&2 are s-block
–> Group 3-12 are d block
–>Group 13-18 are p-block
Names and numbers of groups
1- Alkali metals
2- alkaline earth metals
3-12 Transition elements
15 pnictogens (N,P,As,Sb,Bi)
16 chalcogens (O,S,Se,Te,Po)
17 Halogens
18 Noble gases
Ionisation energy
How easily an atom loses electrons to form positive ions
First ionisation energy
energy required to remove one electron from each atom in one mole of gaseous atoms of an element to form one mole of gaseous 1+ ions
Na(g) –> Na+(g) + e- //. X(g) –> X+(g) + e-
Successive ionisation of Chlorine
Cl(g) –> Cl+(g) +e- It is not diatomic because ionisation energy is from ONE atom at a time
IE2: Cl+(g) –> Cl2+(g) + e- (only one electron is removed per ionisation energy)
Factors that affect ionisation energy
Atomic radius, nuclear charge, electron shielding
Atomic radius IE
The greater the distance between the nucleus and outer electrons, the less nuclear attraction
–> force of attraction falls of sharply with increasing distance so atomic radius has a large effect
Nuclear Charge IE
More protons in nucleus= greater attraction between nucleus and outer electrons
Electron Shielding IE
Inner-shell electrons repel outer-shell electrons and reduces the attraction between the nucleus and outer electrons
Why is the second ionisation energy greater than the first IE?
Once an electron is lost, the single electron is pulled in closer as there are now more protons than electrons.
–> causes a stronger attraction on the remaining electron