Chapter 6 Circles - Year 1 Flashcards

1
Q

What is important about perpendicular bisector s of a circle?

A

It passes through the middle of the circle therefore the midpoint of a perpendicular bisector will be the centre of a circle

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2
Q

What is the equation of a circle?

A
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3
Q

If you know the center of a circle and 1 point on the edge how do you calculate the radius?

A

You can use pythagorus as you can work out the lateral and vertical values

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4
Q

What is a common mistake made when working out the radius of a circle?

A

If you have used 2 points on the edge of a circle you need to divide your answer by 2 to get half which is the radius

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5
Q

What changes with the values of the center of the circle and the equation?

A

The sign flips (as the equation is x-a and y-b

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6
Q

If you are given 2 points on the edge of a circle how do you work out the center of the circle?

A

Find the midpoint of those points (then reverse the signs to get the first part of the equation

Then find the difference between the 2 points to find the length of the diameter (then divide it by 2)
Then square that to get the radius squared

Then fill in the equation

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7
Q

How can you find the center and radius of a circle if the equation of the circle is in it’s expanded form?

A

You can complete the square
Then bring everything without an x and y to the right side then square root it to find the radius

The center will be from the squared brackets (opposite signs)

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8
Q

What do you use to show that a line and a circle never meet?

A

The discriminant

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9
Q

What is special about the tangent?

A

It only touches the circle at 1 point
It is perpendicular to the radius

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10
Q

How can we use a chord to get the center of a circle?
(As long as you already know the y co ordinate

A

Find the perpendicular bisector

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11
Q

What is special about chords in circles?

A

If you find the perpendicular bisector of it you can find the center of the circle

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12
Q

How do you find the perpendicular bisector of a chord?

A

You find the midpoint of it
You find the m of and then take the negative reciprocal so you now know the m of the perpendicular bisector
You can then use y-y1=m(x-x1) to find the equasion

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13
Q

What is the significance of knowing that the perpendicular bisector chord passes through the center?

A

If you have 2 chords and hence found 2 bisectors you can pin point the center of the circle

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14
Q

How to you verify that a point lies on a circle?

A

You substitute the values into the circle and see if the 2 sides say equal

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15
Q

If you are given a an equation of a circle and you are told the gradient of a tangent how do you work out he equations of the tangents?

A

State the m of the radius (negative reciprocal)
Substitute that equation into the equation of the circle

Then substitute thise answers into y-y1=m(x-x1) to get the equations of the triangles

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16
Q

What is meant if a triangle inscribes a circle?

What is the word in term of the circle?

A

All 3 points of the triangle are on the circumference of the circle

The circle circumscribes the triangle

17
Q

If the circumscribing shape is a circle what is it called?

A

Circumcircle

18
Q

What is the center or a circumcircle called?

A

Circumcenter (or center)

19
Q

What are the 2 methods to show that a line is a diameter?

A

Method 1 - Using pythagorus
You prove that the sum of the squares of 2 side lengths equal the square of the diameter length

Method 2 - You show that the other 2 lines are perpendicular

Calculate the m’s of the other 2 lines
Multiply them to get -1
Then state AC is perpendicular to BC as their gradients have a product of -1
Therefore AB is the diameter

20
Q

How do you find the equation of a circle when you are given 3 points which are on it’s circumference?

A

Find the perpendicular bisector of 2 chords
Then put them equal to each other and solve for x and then get your y value
You now know the center of the circle (swap the signs)

Then you work out the diameter of the circle and divide your answer by 2 to get the diameter
Then square it and fill in your equation of the circle