Chapter 6 Flashcards

1
Q

True or false: Enzymes are powerful biological catalysts, responsible for the harmonious interplay of ALL cellular processes

A

True!

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2
Q

Why do enzymes have a high degree of specificity?

A

Their specialized pockets called active sites (aka binding sites)

The shape, size, and chemical properties of the active site are complementary to the substrate, meaning that only specific molecules (substrates) can fit into this site.

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3
Q

Describe the two concepts that explain the catalytic power of enzymes

A
  1. They bind most tightly to the transition state of the catalyzed reaction and use binding energy to lower the activation barrier.
  2. Evolution has organized or finely-tuned the design of active sites, such that multiple mechanisms of chemical catalysis can occur simultaneously.
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4
Q

Explain how an enzyme uses binding energy to lower the activation barrier

A

Ultimately derived from the free energy released in forming many weak bonds between an enzyme and its substrate.

This binding energy contributes to specificity as well as to catalysis.

Weak interactions are optimized in the reaction transition state; enzyme active sites are complementary not to the substrates per se but to the transition states through which substrates pass as they are converted to products

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5
Q

Describe Enzyme regulation: (reversible) covalent modifications

A

Phosphorylation and protein kinases/phosphatases.

Phosphorylation is the addition of a phosphate group (PO₄²⁻) to an enzyme, typically at serine, threonine, or tyrosine residues. It is catalyzed by kinases (enzymes that add phosphate groups).

Dephosphorylation is the removal of a phosphate group, typically catalyzed by phosphatases

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6
Q

Describe Enzyme regulation: allosteric modulators

A

Enzyme regulation by allosteric modulators involves the binding of molecules (called allosteric effectors or modulators) to a site on the enzyme that is distinct from the active site, known as the allosteric site.

The binding of these molecules induces conformational changes in the enzyme that can either enhance (activate) or inhibit (deactivate) its activity

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7
Q

Describe Enzyme regulation: proteolytic (de)activation

A

An enzyme is initially synthesized as an inactive precursor, known as a zymogen or proenzyme, and is activated by the irreversible removal of a portion of its polypeptide chain.

This process involves proteolysis, which refers to the cleavage of peptide bonds, typically at specific sites in the enzyme precursor.

This regulation allows the enzyme to be activated only when needed and in the appropriate cellular location, ensuring that its activity is tightly controlled

The activation of a zymogen is typically irreversible, meaning that once the cleavage has occurred, the enzyme remains active

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8
Q

Describe Enzyme regulation: noncovalent interactions with other (regulatory) proteins

A

These interactions typically involve hydrogen bonds, ionic interactions, van der Waals forces, and hydrophobic interactions.

Regulatory proteins can act as activators or inhibitors of the target enzyme. They often bind to a site on the enzyme distinct from the active site, resulting in a conformational change in the enzyme that alters its activity.

could be allosteric, feedback regulation, etc.

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9
Q

Describe Enzyme regulation: pH

A

Enzymes have an optimal pH at which they function most efficiently, and deviations from this optimal pH can lead to a decrease in enzymatic activity or complete inactivation

The optimal pH is determined by the enzyme’s structure and the environment in which it needs to perform its function

Acidic environments (low pH) can protonate amino acid residues, while basic environments (high pH) can deprotonate them.

These changes can disrupt the enzyme’s active site, reducing its ability to bind substrates or catalyze reactions effectively.

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10
Q

What is a cofactor?

A

Cofactors assist in the formation of the enzyme-substrate complex participate directly in the chemical reaction.

Inorganic metal ions such as Zn²⁺, Fe²⁺, Mg²⁺, or Cu²⁺

Assist in stabilizing the enzyme’s structure or participate in the catalytic process by acting as electron carriers, cofactors in redox reactions, or coordinating with substrates

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11
Q

What is a coenzyme?

A

Organic molecules that bind to the enzyme, often in a non-covalent manner, and are required for enzyme activity.

Cofactors often act as carriers of chemical groups or electrons

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12
Q

Define prosthetic group

A

A coenzyme or metal ion that is very tightly or even covalently bound to the enzyme protein is called a prosthetic group.

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13
Q

Draw a free energy diagram of a catalyzed and uncatalyzed reaction. Be sure to include ground and transition state; activation energy; reaction intermediates; rate-limiting step; binding energy

A

Check Textbook for correct answer

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14
Q

define DeltaG10

A

A biochemical standard free-energy change.

AKA the overall standard free-energy change in the direction S–>P

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15
Q

What is DeltaG(with little tree)

A

Activation energy

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16
Q

Define transition state

A

At the top of the energy hill is a point at which decay to the S or P state is equally probable (it is downhill either way).

The transition state is not a chemical species with any significant stability and should not be confused with a reaction intermediate (such as ES or EP). It is simply a fleeting molecular moment in which events such as bond breakage, bond formation, and charge development have proceeded to the precise point at which decay to either substrate or product is equally likely

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17
Q

What does a higher activation energy correspond to?

A

a slower reaction

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18
Q

Define reaction intermediates

A

A reaction intermediate is
any species on the reaction pathway that has a finite chemical lifetime.

the ES and EP complexes occupy valleys in the catalyzed reaction coordinate diagram

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19
Q

Define rate limiting step

A

the overall rate is determined
by the step (or steps) with the highest activation energy; this is called the rate-limiting step. In a simple case,
the rate-limiting step is the highest-energy point in the diagram for interconversion of S and P

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20
Q

What is binding energy?

A

The energy derived from enzyme-substrate interaction is called binding energy, deltaGB. Its significance extends beyond a simple stabilization of the enzyme-substrate interaction. Binding energy is a major source of free energy used by enzymes to lower the activation energies of reactions

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21
Q

Define Keq

A

The equilibrium constant.

Keq= [P]/[S]

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22
Q

The the relationship between Keq
and deltaG10 can be described by the expression:

A

deltaG10= -RT ln Keq

23
Q

Describe how rate constant and rate equation are related for a first order reaction

A

The rate of any reaction is determined by the concentration of the reactant (or reactants) and by a rate constant, usually denoted by k.

For the unimolecular reaction S–>P, the rate (or velocity) of the reaction,
V—representing the amount of S that reacts per unit time—is expressed by a rate equation:
V = k[S]

In this reaction, the rate depends only on the concentration of S

24
Q

What is a first order reaction?

A

The rate depends only on the concentration of S

25
Q

What is a second order reaction?

A

If a reaction rate depends on the concentration of two different compounds, or if the reaction is between two molecules of the same
compound, the reaction is second order and k is a second-order rate constant, with units of M-1s-1
.

26
Q

Give the rate equation of a second order reaction

A

V= k[S1][S2]

27
Q

What is the expression that relates the magnitude of a rate constant to the activation energy:

A

k =(KT/h)e^(-deltaG‡/RT)

28
Q

Give Boltzmann constant and Planck’s constant

A

Boltzmann constant= K=1.38E−23 J/K
Planck’s constant= 6.626E −34 JS

29
Q

How does a catalyst circumvent unfavorable charge development during cleavage of an amide

A

May use acid-base catalysis to protonate or deprotonate functional groups in the transition state, reducing the overall energy of the transition state and lowering the activation energy of the reaction

Protonation of the carbonyl oxygen (on the amide bond) stabilizes the developing negative charge on the oxygen, making it easier for the bond to break.
Deprotonation of the nitrogen atom (from the amide bond) stabilizes the developing positive charge on the nitrogen, helping facilitate the bond cleavage.
Histidine residues in enzymes (like serine proteases) are often involved in this type of acid-base catalysis because of their ability to accept or donate protons in response to changes in pH.

also:
- neucleophilic attack
- electrostatic stabilization

30
Q

Describe how Amino acids work as acid-bases

A

The carboxyl group of an amino acid (-COOH) can act as an acid by donating a proton (H⁺)

The amino group (-NH₂) of an amino acid can act as a base by accepting a proton (H⁺)

31
Q

Define Enzyme kinetics:
pre-steady state

A

Refers to the initial phase of an enzyme-catalyzed reaction, immediately after the enzyme and substrate come together, but before the reaction has reached equilibrium or a steady rate of product formation.

This phase is transient, with the formation of products and the consumption of substrates being fast and fluctuating.

32
Q

Define Enzyme kinetics:
steady state

A

The concentrations of the enzyme-substrate complex (ES) remain constant over time.

This occurs after the initial pre-steady state phase, once the system has stabilized, and is characterized by a balanced rate of enzyme-substrate complex formation and breakdown.

33
Q

Define Enzyme kinetics:
initial rate/velocity

A

The rate at which product is formed (or substrate is consumed) in an enzyme-catalyzed reaction, measured during the early moments of the reaction, before significant changes in substrate concentration or product accumulation occur.

34
Q

Define Enzyme kinetics:
maximum velocity (Vmax)

A

When the enzyme is fully saturated with substrate and operating at its maximum capacity.

In this condition, all enzyme active sites are occupied by substrate molecules, and the enzyme cannot process substrate any faster

35
Q

Enzyme kinetics:
Michaelis Menten equation

A

describes the rate of an enzyme-catalyzed reaction as a function of substrate concentration. It provides a mathematical model for how the reaction velocity (𝑉0) changes with varying substrate concentrations ([S])

V0= (Vmax[S]) / Km+[S]

36
Q

Enzyme kinetics:
Km

A

Km is the substrate concentration at which the reaction rate is half of the maximum velocity (𝑉max).
A lower 𝐾𝑚 indicates a higher affinity of the enzyme for the substrate, meaning the enzyme reaches half-maximal velocity at a lower substrate concentration.

37
Q

Enzyme kinetics:
Lineweaver-Burk equation

A

This is a double reciprocal plot where 1/𝑉0 is plotted against 1/[𝑆]. The result is a straight line, which makes it easier to determine 𝑉max and Km
from experimental data

38
Q

Enzyme kinetics:
kcat aka turnover number

A

It represents the maximum number of substrate molecules that a single enzyme molecule can convert to product per unit of time, when the enzyme is fully saturated with substrate.

Kcat= Vmax/[E total]

39
Q

Inhibition in enzyme kinetics: give the types of reversible inhibition

A

Competitive
Uncompetitive
Noncompetitive (mixed)

40
Q

Inhibition in enzyme kinetics:
competitive

A
  • Inhibitor binds in the enzyme active
    site – competes with normal
    substrate binding (forms EI
    complex)
  • Prevents substrate from binding
    and reacting
  • Usually looks like substrate (or
    transition state of reaction!)
41
Q

Describe competitive inhibitions effect on kinetics

A

Vmax remains constant
Km increases
- Dependent on alpha
Apparent Km: aKm

42
Q

Inhibition in enzyme kinetics:
uncompetitive

A

Inhibitor binds to enzyme-substrate complex at site distinct from active site

Distorts the active site making it inactive via conformational change

43
Q

Describe uncompetitive inhibition effect on kinetics

A

Vmax & Km decrease
Both dependent on a’
Apparent Km: Km/a’
Apparent Vmax: Vmax/a’

44
Q

Inhibition in enzyme kinetics:
mixed

A

Inhibitor binds to either E or ES
Rarely seen …

45
Q

Describe Mixed/Noncompetitive Inhibition effect on kinetics

A

Vmax decreases
Km may increase or decrease
Apparent Km: aKm/a’
Apparent Vmax: Vmax/a’

46
Q

Inhibition in enzyme kinetics:
irreversible

A

Irreversible inhibition occurs when an inhibitor binds covalently to the enzyme, leading to permanent loss of enzyme activity.

47
Q

Inhibition in enzyme kinetics:
mechanism-based inactivators

A

A subclass of irreversible enzyme inhibitors (AKA Suicide inhibitors) that selectively and covalently bind to the enzyme, leading to its inactivation.

They are designed to mimic the enzyme’s normal substrate, but upon binding to the enzyme, they undergo a chemical transformation that results in the covalent modification of the enzyme, thereby irreversibly inactivating it.

48
Q

Inhibition in enzyme kinetics:
transition-state analogs

A

A class of enzyme inhibitors that mimic the transition state of the enzyme-catalyzed reaction.

These analogs are designed to resemble the high-energy, unstable intermediate state that the substrate transitions through during the reaction. Transition-state analogs can be potent inhibitors because they are often bound much more tightly by the enzyme than the substrate itself, effectively blocking enzyme activity

49
Q

What is chymotrypsin’s function/relevant info?

A

A type of digestive enzyme, a serine protease. uses an active serine residue to perform hydrolysis on the C-terminus of aromatic amino acids of other proteins.

Shows specificity for aromatic residues due to its hydrophobic pocket.

Synthesis occurs in the pancreas, but is inactive and not activated until secretion into the ER lumin, where it is activated by trypsin.

50
Q

Draw the chymotrypsin mechanism

A

Check on sheet

51
Q

Name the seven types of enzymes and what they do

A

Classified according to reaction type:

  1. Lyases: Addition of groups to double bonds or formation of double bonds by removal of groups
  2. Isomerases: Transfer of groups within molecules to produce isomeric forms
  3. Ligases: Formation of bonds by condensation reactions coupled to ATP cleavage
  4. Hydrolases: Hydrolysis reactions: Transfer of functional groups to H2O
  5. Oxidoreductases: Transfer of electrons
  6. Transferases: Group transfer reactions
  7. Translocases: Facilitate the movement of molecules, such as proteins or other substances, across cellular membranes
52
Q

Give the scheme for a simple enzyme catalyzed rxn which converts a single substrate into a single product.

A

E+S <–> ES <–> EP <–> E+P

53
Q

Do enzymes affect the rxn equilibria?

A

No. They just lower the activation energy, thereby speeding up the reaction

  • Accelerate interconversion of S and P. The free energy used to lower activation energy comes from binding energy
54
Q

Define the Ping-Pong enzyme mechanism, and draw the scheme.

A

CHECK SCHEME ON CHYMOTRYPSIN PAPER

The Ping-Pong mechanism typically involves two substrates and two products, and the enzyme interacts with both substrates in sequence.

The enzyme undergoes a covalent modification after it binds the first substrate, and this modification is crucial for the catalysis of the second substrate.

the first product is released before the second substrate can bind to the enzyme.

There will be a covalent intermediate formed.