Chapter 6 Flashcards

1
Q

Within an organism’s DNA are the instructions….

A

necessary to build all the proteins it requires

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2
Q

DNA is passed from generation to generation in the form of _____________. ELABORATE

A

Chromosomes
- In eukaryotes, chromosomes may be visible in the cells during cell division. –> appear as the familiar X-shaped objects that are split during mitosis or meiosis.
- The size and # of chromosomes in a cell are specific to each species.

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3
Q

The largest known plant has _______ chromosomes

A

about 1200

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4
Q

How is a protein synthesized from DNA?

A
  • When a particular protein is needed, the portion of DNA (the gene) that codes for this protein is activated.
  • The nucleotide sequence is copied (transcribed) into a molecule of RNA (ribonucleic acid).
    -The RNA then moves to cytosol, where its sequence is translated by the ribosomes into amino acid chains called polypeptides.
  • Elsewhere in the cell, polypeptides are further modified to form functional proteins.
  • How the message in DNA is decoded to make proteins is central to the development of all life
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5
Q

Gregor Mendel overview: who was he & what did he do?

A
  • He was an Austrian monk who studied pea plants (Pisum sativum)
  • Conducted cross-pollination experiments over 7 years in late 1800s
  • Analyzed inheritance patterns in 28,000+ plants
  • His analysis clearly showed how certain traits were expressed in the next gen from each cross-pollination experiment. –> Proposed that traits pass from parent to offspring via “factors”
  • cuz of his work, we now know that a hereditary molecule does exist.
  • Over past 100 years, many experiments, using increasingly sophisticated methods, revealed that DNA = the carrier of the hereditary information
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6
Q

All new cells arise from ________________________, & all the information that is needed for optimal cell functioning is coded in a cell’s ________

A

division of existing cells, DNA

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7
Q

Eukaryotes Vs Prokaryotes: location of DNA

A

Eukaryotes = DNA is stored in the nucleus.
Prokaryotes= stored in the cytosol.
- Regardless of the location, all forms of life use DNA in the same way to build proteins & grow new cells.

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8
Q

Mendel proposed the concept of “factors” for each specific trait inherited by organisms. ELABORATE

A
  • These factors, inherited from parents, determine an organism’s measurable characteristics like size, color, and markings.
  • Today, we know these “factors” as genes= DNA segments with instructions for making proteins that express inherited traits.
    -Genes exist in different forms called alleles, leading to variations in traits.
  • Genes are scattered along an organism’s DNA strands & can vary greatly in length.
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9
Q

Gene similarities within a species and with other species.

A
  • In a species, the gene for a particular characteristic is always found in the same location on a particular chromosome.
  • As scientists continue to study, they are discovering that many fundamental genes (such as those that direct the development of an embryo or the building of cell membranes) are shared by almost every form of life.
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10
Q

A histone is

A

a special protein molecule that is the core around which the DNA strand wraps

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11
Q

An organism’s genome is

A

the complete set of hereditary information that is contained in an organism.
- genome of eukaryote is usually spread over many chromosomes, which often occur as pairs of
homologous chromosomes. –> Each pair represents 2 copies of a particular set of genes. –>Ex, humans have
23 homologous pairs of chromosomes of diff sizes, 1 pair of which are special sex chromosomes
- Each set of 23 chromosomes contains a total
of more than 20 000 different genes, which r combined to form roughly 3 billion base pairs.

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12
Q

About ____________ ago, Mendel hypothesized the existence of a hereditary molecule that passes genetic information through the generations. Less than _________ ago, scientists determined that this hereditary material is, in fact, DNA.

A

150 years, 70 years

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13
Q

Frederick Meischer & his work

A
  • 1868=Frederick Meischer studied cell nuclei to understand their composition.
  • At the time, proteins were thought to be the hereditary material cuz they were known to be complex & carry out numerous biological functions
  • he collected pus (mainly white blood cells) from the bandages of his patients & extracted a substance, rich in phosphorus and acidic, from white blood cells, naming it “nuclein” since it was found in the nucleus.
  • At that time, heredity was poorly understood, with theories suggesting a blending of parental traits. –> they could not explain why a short woman and a tall man produced children with a variety of heights, not a height that was an average of the two parents’ heights
    –> Although Mendel was crossbreeding his peas at
    about the same time (1865), his work was generally unnoticed until the early 1900s.
  • function & composition of nuclein (later identified as DNA) were not understood until >50 years later, and its structure was not determined until decades after that.
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14
Q

Frederick Griffith & Experiment (not conclusion)

A
  • THE TRANSFORMING PRINCIPLE
    -role of Meischer’s nuclein (DNA) was still unknown when Frederick Griffith began studying pneumonia epidemic in europe during World War I.
  • in 1928, Griffith, a medical officer for British Military, carried out an experiment that accidentally shed light on the function of DNA in inheritance.
  • Griffith used 2 strains of pneumonia bacteria:
    –> Smooth strain/S-strain: had capsule that surrounded each cell and caused the bacterial colonies to look smooth & glossy when grown on agar. WAS HIGHLY VIRULENT (PATHOGENIC)
    –> Rough strain/R-strain: Lacked a capsule, forming rough colonies and WAS NON-VIRULENT.
  • Injecting mice with the S-strain caused pneumonia and death in few days, while the R-strain caused no signs of pneumonia & lived.
  • Griffith concluded that capsule surrounding the S-strain was responsible for the virulence.
  • He heated the S-strain cells, destroying capsule that surrounded the cells and killing the bacteria. The dead S-strain no longer caused an infection in the mice.
  • when he mixed the heat-killed S-strain with the live non-virulent R-strain, many of the mice got pneumonia and died.
  • Griffith then isolated living bacteria that appeared like S-strain bacteria from the dead mice. –> Somehow, the living R-strain bacteria acquired some factor from the heat-killed S-strain that made them virulent.
    –> The newly virulent R-strain bacteria even formed smooth colonies when cultured, just like the living S-strain bacteria.
  • We now know that bacteria can take up genetic
    material from nearby bacteria and use this DNA as their own
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15
Q

Griffith’s conclusion

A
  • Although Griffith couldn’t identify exact material involved in inheritance, he understood that some hereditary substance had passed from the dead S-strain cells to the live R-strain cells.
  • When the R-strain bacteria acquired this material,
    they were effectively transformed into infectious S-strain bacteria.
  • He called this process transformation, and he called the factor that was responsible the transforming principle.
  • At the time, the most likely candidates for the transforming principle were proteins and DNA, but further experiments were required to determine its identity
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16
Q

Transformation is

A

a change in a genotype or phenotype caused by the direct uptake of genetic material by a cell

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17
Q

Avery, McLeod, and McCarty

A
  • DNA TRANSFORMATION CONFIRMED
  • In 1944, Oswald Avery, Colin McLeod, and Maclyn McCarty (all researchers) expanded on Griffith’s findings to identify the genetic material.
  • They used S- and R-strains of Streptococcus bacteria, which differ in their disease-causing ability, isolating each strain and growing them in separate cultures
  • Avery’s team hypothesized that either DNA, RNA, or proteins was responsible for transforming R-strain bacteria into virulent forms.
  • They treated heat-killed S-strain extracts with enzymes to selectively destroy DNA, RNA, or proteins, then mixed these extracts with R-strain bacteria to observe the transformation.
  • The experiments showed that DNA was the transforming substance, as only the samples where DNA remained intact could induce transformation.
  • Despite strong evidence, Avery and his team were cautious to conclude DNA’s role as genetic material due to prevailing beliefs in protein-based inheritance and the need for further validation of DNA’s role. –> If some protein had not been destroyed by the enzymes, their results would be incorrect.
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18
Q

Hershey & Chase

A
  • DNA IS THE HEREDITARY MATERIAL
  • In 1952, Bacteriologists Alfred Hershey and Martha Chase sought to identify whether DNA or proteins served as genetic material.
  • They used a bacteriophage (viruse that infect bacteria) with DNA and a protein coat to infect E. coli bacteria. –> The bacteriophage they used had both DNA & a protein coat –>they knew that bacteria could be transformed by viruses, but they did not know which part of the virus—the protein coat or the DNA (or RNA)—did the transforming
  • When bacteriophage infects bacterium, it inserts its genetic material into the bacterium & uses the bacterium’s cellular processes to produce new bacteriophages.–> Note: at the time, no one knew what part or parts of a virus entered cells during an infection or even what a virus looked like. –> too small to be seen with the most powerful microscopes
  • They employed radioisotopes to label molecules:
  • 32P (Phosphorus-32): Tagged DNA, as DNA contains phosphorus and proteins only contain a tiny amount
  • 35S (Sulfur-35): Tagged proteins, as proteins contain sulfur, while DNA does not.
  • Process: Separate bacteriophage groups were labeled with either 32P or 35S and then used to infect E. coli colonies to trace which molecule entered the bacterial cells.
  • This experiment provided crucial evidence that DNA, not protein, is the genetic material that viruses transfer to host cells. –> Radioactivity was only detected within bacterial cells that wre infected
    by viruses containing DNA labelled with 32P. The radioactive protein coats had remained outside the bacterial cells, while the radioactive DNA had entered the cells.
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19
Q

Phoebus Levene

A

In 1920s, Phoebus Levene reported that each DNA molecule contained three major components: deoxyribose sugars, phosphate groups, and nitrogenous bases.
- A DNA molecule is a polymer made of nucleotide subunits. Each nucleotide subunit consists of a nitrogenous base attached to one deoxyribose sugar, which is connected to a phosphate group
- By 1949, the four nitrogenous bases had been identified. –> Adenine (A) & guanine (G) are double-ring structures= purines, while thymine (T) and cytosine (C) are single-ring structures= pyrimidines.

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20
Q

Edward Chargaff

A
  • an organic chemist
  • did not agree with researchers who suggested that DNA contained equal amounts of the 4 nitrogenous bases.
  • In 1950, Chargaff found that these bases always occur in definite ratios.
  • He also found that the quantities of T & A always matched, as did the quantities of G & C.
  • Ex, Human DNA was estimated to contain 30.9 % A, 29.4 % T, 19.9 % G, & 19.8 % C.
  • Scientists now knew DNA’s chemical composition & its role as the molecule of
    inheritance.
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21
Q

X-ray Crystallography

A
  • 1 new tech at that time was X-ray crystallography & this tech involves X-rays bombarding a sample of a compound, which is usually in the form of solid crystal.
  • The atoms deflect the X-rays in a specific way, creating a pattern on a photographic plate.
  • The pattern is then analyzed to help determine the molecular structure of the original sample.
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22
Q

Wilkins & Franklin

A
  • Franklin and Wilkins used X-ray crystallography to investigate DNA’s structure at King’s College, London, working somewhat independently on two crystal forms.
  • had a strained relationship as colleagues
  • Wilkins had produced some preliminary crystallographs of DNA that suggested its helical
    structure, but Franklin was unconvinced. –> Wilkins’ initial DNA samples were impure, resulting in unclear crystallographs.

Franklin’s Achievements:
- Prepared purer DNA samples, producing high-quality crystallographs with a distinctive “X” pattern.
- Suggested that DNA’s sugar-phosphate backbone was on the outside of the molecule, contrary to the prevailing belief.
- Proposed that DNA was a double helix that rotated clockwise with a 2 nm diameter and a 3.4 nm helix turn length.

  • Though aware of Chargaff’s rules, Franklin could not determine the arrangement of nitrogenous bases within the helix and was hesitant to publish her findings due to these uncertainties.
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23
Q

Watson & Crick

A
  • BUILDING A MODEL OF DNA
  • In 1952, the team of James Watson and Francis Crick were building models of the DNA molecule, incorporating everything they knew about DNA. They
    had a wealth of information available to them:
  • four different nitrogenous bases (A, T, C, and G)
  • Chargaff ’s ratios of the nitrogenous bases
  • the phosphate and sugar backbone
  • Without her consent, Maurice Wilkins shared Rosalind Franklin’s findings with Watson, providing them with her concept of a double helix with inward-facing bases & her measurements of DNA’s dimensions.
  • Watson & Crick realized that the double helix could incorporate all of the facts

Structure of the Model:
- DNA was modeled as a double helix with 2 phosphate-sugar backbones twisting clockwise.
- Nitrogenous bases faced inward, connected to those one the opposite strand by H-bonds, with each purine pairing with a pyrimidine (A-T with 2 H-bonds, G-C with 3 H-bonds) according to Chargaff’s rules= complementary base pairing
- The symmetry is key to the structure of DNA
& its ability to divide itself accurately & convey genetic information

  • model showed that DNA molecule could only be stable if the strands ran antiparallel= if they ran in opposite directions.
    –>1 DNA strand must have the hydroxyl of the 3’ C attached to the deoxyribose sugar at one end and the phosphate attached to the 5’ C of the last sugar
    at the other end. The other strand must wind around the first with its 5’ end opposite the 3’ end of the first strand
  • A great deal of research was needed to understand DNA replication, but Watson and Crick’s initial model of the structure of DNA gave scientists a place to start
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24
Q

DNA molecules can be __________ of nucleotides in length, and replication has to occur ____________ with
few _____________.

A

millions, very quickly, (if any) errors

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25
Q

( SLIDESHOW) there are 3 proposed potential mechanisms of DNA replication: List them

A
  • Conservative Model –>the 2 parental strands would act as templates for replication, but then recombine afterwards.
  • Semiconservative Model (scientifically proven one): —-> the 2 parental strands would act as templates for replication & remain separated from each other, incorporated into two new molecules.
  • Dispersive Model (this one was not included in the textbook) –> each strand of both daughter molecules contains a mixture of old & newly synthesized parts
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26
Q

Semiconservative replication is

A

a mechanism of DNA replication in which each of the 2 strands of parent DNA is incorporated into a new double-stranded DNA molecule
- involve separating the 2 parent strands and building a new, complementary replacement strand for each.
- The new molecules would consist of 1 parent strand & 1 new strand
STEPS
- Complementary base pairing in the DNA double helix: G pairs with C, A pairs with T.
- The two chains unwind and separate.
- Each “old” strand is a template for the addition of bases according to the base-pairing rules.
- The result is two DNA helices that are exact copies of the parental DNA molecule with one “old” strand and one “new” strand

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27
Q

Matthew Meselson & Franklin Stahl (Experiment only)

A
  • In 1958, Matthew Meselson & Franklin Stahl carried out an experiment that demonstrated that DNA replication is semiconservative
  • Meselson & Stahl used isotopes to label the parent DNA strands before replication –> they used was “heavy” nitrogen, 15-N.
  • E. coli was grown for 17 gens in a medium with ^15N, ensuring full incorporation of ^15N into DNA.
  • Bacteria were then transferred to a medium with “light” nitrogen (^14N).
  • Allowed to undergo 1-2 rounds of replication (~20 min per round).
  • Any new DNA produced should have lighter 14-N incorporated into its structure, thus making it less dense than the parent 15N DNA. —> To determine density, the DNA was isolated and placed in a centrifuge tube that contained a mixture that, when centrifuged, produces a density gradient
    from most dense at the bottom to least dense at the top. DNA migrates to a level in the
    tube with a density similar to its own.
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28
Q

Matthew Meselson & Franklin Stahl (Results & conclusion)

A
  • before replication, upon centrifuging, the original heavy 15N DNA was in a single band. SEE DIAGRAM ON PAGE 283
  • 1st replication, there was a single band of DNA at a density of hybrid DNA= DNA with equal parts of 15N and 14N –> If replication was conservative, 2 bands would be seen, 1 containing the parental 15N DNA and one containing only new 14N DNA.
  • single band of hybrid DNA confirmed that DNA
    replication was indeed semiconservative.
  • 2nd replication confirmed this conclusion. 2 bands of DNA were detected
    –> 1 had a density consistent with hybrid DNA & 1 corresponded to DNA built only with light 14N nucleotides –> Each double strand of hybrid DNA had been separated and used to build complementary 14N strands, producing 1 band of hybrid DNA & 1 with only 14N.
  • The clarity of the results of Meselson and Stahl’s elegant and innovative experiment left little doubt. DNA replication is semiconservative
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29
Q

Most of our understanding of the process of DNA replication comes from the study of _____________________. Elaborate

A

the bacterium E. coli
- DNA replication in eukaryotes resembles that in prokaryotes, though eukaryotic replication is more complex due to linear DNA structure and higher DNA volume.

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30
Q

DNA replication has 3 steps:

A

1) the parental strands of DNA separate
2) the complementary DNA strands are assembled
3) the new strands are proofread and repaired

31
Q

DNA Replication Step 1: Strand Separation

A
  • 1st the DNA strands must be unwound from each other
  • Specific nucleotide sequences on the genome = replication origins, act as starting points. –> cuz of length of DNA molecules in eukaryotes, there r many replication origins on a DNA strand.
  • Enzyme helicase binds to these origins & begins to unwind the 2 strands of DNA by breaking the H-bonds
    between the complementary base pairs.
  • As the two strands separate, they form a Y-shaped structure = the replication fork
32
Q

A replication origin is

A

a specific sequence of DNA that acts as a starting point
for replication

33
Q

Helicase is

A

a replication enzyme that separates & unwinds the DNA strands

34
Q

Replication fork is

A

the point of separation of the 2 parent DNA strands during replication

35
Q

The seemingly simple separation of DNA strands during DNA replication presents 2 challenges:

A

1) if you have ever tried to separate the fibres in a rope or string by pulling them apart, you know that the tension created can lead to twisting & tangles.
–> SOLUTION: A class of enzymes called topoisomerases relieves this tension in DNA strands by cutting 1 or 2 of the strands near the replication
fork, allowing the strands to untangle, & then rejoining the cut strand(s).
https://www.youtube.com/watch?v=EYGrElVyHnU

2) the 2 separated strands have a tendency to rejoin, or anneal, cuz they r complementary.
–> SOLUTION: Single-strand binding proteins (SSBs) prevent annealing by attaching to the DNA strands to stabilize them and keep them separated –> These proteins r removed during the next phase of replication but r used again when needed.

36
Q

Replication Bubbles

A
  • Helicase complexes separate DNA strands in both directions from a replication origin, forming 2 replication forks.
  • The space between 2 replication forks filled with new DNA is = a replication bubble.
  • Due to great length of eukaryotic DNA, there r many replication bubbles along a DNA strand. –> Each bubble expands along the length of the molecule
    until it meets & merges with another bubble, and this continues until eventually 2 separate daughter strands r made.
37
Q

Why it is important for us to have many replication origins?

A
  • without multiple replication origins, replicating the genome of a typical human would take an impractical amount of time. –> In eukaryotes, new DNA is made at the rate of about 50 base pairs/second at each
    replication fork.
    –> if we only had 1 replication origin, the entire genome of a human would be reproduced in about a month.
    –> Multiple replication origins decrease the time to about 1 h
38
Q

DNA Replication Step 2: Building Complementary Strands

A

During replication, new nucleotides are joined by a group of enzymes= DNA polymerases
- Although prokaryotes & eukaryotes have DNA polymerases, the following description will refer to the polymerases that occur in prokaryotes. Eukaryotes
have several more specialized DNA polymerases, & the system is quite complex
- Prokaryotic DNA polymerases add nucleotides to the 3’ end of a new developing strand while moving along and “reading” the template strand in its 3’ to 5’ direction. –> is the important feature of DNA polymerases: they can only add nucleotides to the 3’ end of an existing DNA (or RNA) strand. Thus, the new
strand is always assembled in the 5’ to 3’ direction.
- DNA polymerase makes the new strand of DNA using nucleoside triphosphates, similar to nucleotides in final DNA –> contain a deoxyribose sugar bonded to 1 of 4 nitrogenous bases & a group of 3 phosphate molecules.
- E is needed to power the reactions carried out by the DNA polymerase to make a new strand. –> provided by phosphate groups attached to the nucleoside molecule. –> E is released by the hydrolysis reaction that cleaves 2 phosphates from the nucleoside triphosphate & by making the phosphodiester bond between the 1 remaining phosphate & the hydroxyl group on the 3’ C at the 3’ end of the growing DNA strand. –> The two released phosphates are hydrolysed to 2 inorganic phosphates (Pi). –> The E released is also used to drive DNA synthesis.

39
Q

nucleoside triphosphate is

A

a building block & E source for replicating DNA
- They contain a deoxyribose sugar bonded to 1 of the 4 nitrogenous bases. as well as a group of 3 phosphate molecules

40
Q

When a replication fork first opens, there is nothing for DNA polymerase to “add to.” Elaborate.

A

DNA polymerase can only assemble a strand by adding nucleotides to the 3’ end of an existing strand.–> when 2 strands are pulled apart, there is no 3’ end to start growing a complementary strand from
- to fix this, RNA primase enzymes begin replication process by building a small complementary RNA segment (10-60 nucleotides) on the strand at the beginning of the replication fork These short RNA pieces of RNA= RNA primers.
- As the replication fork continues to open & separate the parent strands, one strand is oriented in the 3’ to 5’ direction while the other is oriented in the opposite 5’ to 3’ direction.
- After, enzyme DNA polymerase III begins adding DNA nucleotides to the RNA primer. Since DNA pol III only builds the new strand in the 5’ to 3’ direction, the 2 new strands begin to be assembled in opposite directions.
https://www.youtube.com/watch?v=Qqe4thU-os8

41
Q

RNA primase is

A

a replication enzyme that produces RNA primer

42
Q

RNA primer is

A

a RNA replication molecule that acts as a starting point for replication

43
Q

DNA polymerase III is

A

a prokaryotic replication enzyme that builds new DNA
strands from nucleotides

44
Q

Leading Strands VS Lagging Strand

A
  • As the replication fork continues to open, the DNA
    pol III that is building a strand toward the fork is able to keep moving forward continuously. –> no need nor opportunity for RNA primase to add any additional primers –> This strand is= the leading strand.
  • On the opposite strand, DNA pol III is moving away from the opening replication fork. This strand= lagging strand.
    –> When enough fork has opened, RNA primase attaches another primer to the parent strand, allowing another DNA pol III to begin from the new starting point. –> pattern created on the second strand is a series of RNA primers & short DNA fragments called
    Okazaki fragments. –> Cuz the this strand is not made in one continual process, it = the lagging strand
45
Q

Okazaki fragment length in prokaryotes VS Eukaryotes

A
  • Okazaki fragments are thought to be 1000-2000 bases long in prokaryotes
  • much shorter (100-200 nucleotides long) in eukaryotes.
46
Q

As each fragment on the lagging strand extends in the 5’ to 3’ direction, it eventually runs into the RNA primer attached to the Okazaki fragment ahead of it. What happens then?

A

DNA pol I, removes the RNA nucleotides one at a time & replaces them with DNA nucleotides.
- Once the primer is replaced, the last nucleotide is linked to the Okazaki fragment in front of it by the making a phosphodiester bond. –> An enzyme called DNA ligase catalyzes this reaction .
- Eventually, all the RNA primers are removed & replaced by DNA

47
Q

The phosphodiester bond is (GOOGLE)

A

a covalent linkage between the phosphate of one nucleotide & the hydroxyl (OH) group attached to the 3′ carbon of the deoxyribose sugar in an adjacent nucleotide

48
Q

leading strand is

A

the DNA strand that is copied in the direction toward the replication fork

49
Q

lagging strand is

A

the DNA strand that is copied in the direction away from the replication fork

50
Q

Okazaki fragment is

A

the piece of new DNA on the lagging strand

51
Q

DNA polymerase I is

A

a prokaryotic replication enzyme that fills in gaps in the lagging strand between Okazaki fragments
- also proofreads the final strands

52
Q

DNA ligase is

A

an enzyme that catalyzes the formation of a phosphodiester bond between 2 DNA strands, as well as between Okazaki fragments

53
Q

DNA Replication Step 3: Dealing with Errors during DNA Replication

A
  • Errors in DNA replication= usually base-pair mismatches
  • DNA polymerase III checks for base-pair mismatches as it synthesizes new DNA. –> If a mismatch occurs, it cannot move forward and will back up, replace the incorrect base, & continue.
  • Despite proofreading, some errors remain (about 1 error per million base pairs).–> DNA repair complexes scan for these errors after replication. –> These complexes contain proteins and enzymes, including DNA polymerase I and II.
  • DNA polymerase II= slow & often works to repair damage to DNA that occurs between replication events.
54
Q

How do Repair complexes find and fix mismatches base-pairs

A
  • cuz mismatched base pairs cannot bond correctly, they distort the shape of the DNA.
  • The DNA repair complexes move along the strand, locating these distortions. –> Once a distortion is found, a repair complex determines which of the 2 helices has the incorrect base.
  • The repair complex can even recognize the original (correct) strand!
  • An enzyme removes a portion of the strand around the mismatch.
  • resultant gap is filled in by a DNA pol & completed with DNA ligase
55
Q

DNA Replication in Prokaryotes VS Eukaryotes

A
  • most of our knowledge of DNA replication has come from the study of bacteria.–> Research shows DNA replication in prokaryotes and eukaryotes is fundamentally the same but differs due to genome size, structure, and enzyme types.

1) Prokaryotes have smaller, circular genomes with a single replication origin and bubble. Eukaryotes have larger, linear genomes requiring thousands of origins and replication bubbles.
2) Linear DNA in eukaryotes presents challenges at the strand ends, discussed further in other sections.
3) Bacterial DNA polymerases differ from the more varied types found in eukaryotes, though both perform similar functions.

56
Q

unravelling all chromosomes in a single human cell, isolated the DNA, & joining all the double helices end to end, the molecule you made would be about _____ long.

A

1.8 m
- This entire length of DNA must fit into a cell nucleus that is only 10 µm across.

57
Q

The Packing of Eukaryotic DNA

A

DNA (negative) wraps around positively charged histone proteins, which act as spools, forming nucleosomes and reducing space.
- nucleosome= consists of 8 histones with DNA wrapped around them –> nucleosomes r connected by stretches of DNA called linker DNA, creating a “string of beads” appearance.
- Nucleosomes coil into 30 nm cylindrical fibers called solenoids AKA 30nm chromatin fibers, with each coil containing 6 nucleosomes, further condensing the DNA by a factor of 7.
- Most DNA in the nucleus during interphase is
loosely packed nucleosomes or solenoids. –> If the DNA contains active genes, the nucleosomes must be altered to allow the proteins & enzymes that are needed for gene expression to access the coding base sequences.
- Histones assist in regulating gene accessibility; compacted solenoids store inactive or non-coding DNA, protecting it from damage.
- Before cell division, solenoids supercoil to form condensed X-shaped chromosomes, visible during metaphase of mitosis.

  • also have very small amounts of DNA in mitochondria & chloroplasts –> structure of this is similar to the structure of the DNA found in prokaryotes
58
Q

Prokaryotic DNA Organization

A
  • organization of DNA in eubacteria & archaea is simpler & has other features than eukaryotes. –> we will look at eubacteria
  • bacterial DNA consists almost entirely of 1 chromosome that is commonly circular. –> Linear chromosomes can occur in some bacteria, but are rare
  • Bacterial DNA is unbound by a nuclear membrane, allowing easier access for replication enzymes.
  • The region of the cell that contains the looped DNA = the nucleoid.
  • In addition to the primary circular DNA, bacteria contain smaller circular DNA pieces called plasmids, which can transfer between cells through conjugation, promoting natural genetic variation & enabling genetic engineering.
  • Prokaryotes compact their DNA using supercoiling, where DNA twists into tight coils. –> . Imagine
    twisting an elastic band so that it forms tiny coils along its length. Then keep twisting the elastic band until the coils bunch on top of each other and form a tight ball.
  • This formation happens with a bacterial genome and is called supercoiling
  • Archaea also have circular chromosomes but, like eukaryotes, their DNA is associated with histone-LIKE proteins.
59
Q

Supercoiling is

A

the continuous twisting of prokaryotic DNA that reduces the volume of the DNA

60
Q

The structure of eukaryotic DNA presents another problem: DNA loss during replication. Elaborate.

A
  • On the lagging strand, the final RNA primer near the end cannot be replaced with DNA. –> Thus, no DNA is assembled on the lagging strand beyond the position of the last primer.
  • Since the last sequence at the end of the parent strand is not copied, the final DNA is shorter by the amount of this uncopied segment
  • loss of DNA during every cycle of replication causes chromosomes to continually shorten & can lead to the loss or damage of important gene coding regions.
    –> To prevent this loss, zones of repetitive, non-coding sequences r found at the ends of eukaryotic chromosomes. These sequences= telomeres.
    –> Every time DNA replicates, part of its telomeres are lost, but the coding regions of DNA remain complete.
61
Q

A Telomere is

A

a repeating sequence of DNA at the end of a chromosome that protects coding regions from being lost during replication
- in electron micrographs, appear like
small dots at each end of the chromosomes.
- They act like aglets (the bits of plastic or metal at the ends of a shoelace) by capping off the ends of the chromosomes.

62
Q

Telomeres have several functions:

A

1) They help to prevent chromosome ends from fusing to other chromosomes.

2) They prevent DNA degradation from enzymes called nucleases ( a type of hydrolytic enzymes that cleave the phosphodiester bonds between the sugars and the phosphate moieties of nucleic acids. GOOGLE)

3) They assist DNA repair mechanisms in distinguishing DNA breaks from chromosomal ends

4) They may play a role in determining the number of times that a cell can divide, and therefore may play a critical role in determining the lifespan of an organism

63
Q

Telomere Structure:

A
  • telomeres are repeating sequences of nucleotides
  • e.g., 5’-TTAGGG-3’ is a common telomere sequence in humans & other species, repeated up to 2000 times to protect coding DNA –> Of course, the complementary strand has the sequence 3’-AATCCC-5’, repeated a matching number of times
64
Q

Replication and Telomere Loss:

A

rmr DNA polymerase cannot copy the final segment of the lagging strand. –> leading to the gradual shortening of telomeres by about 100 base pairs per replication.
- DNA that is inherited by new cells after mitosis
is fully functional, with all its genes intact –> only diff is that the telomere portions of the chromosome are slightly shorter.

65
Q

After many DNA replications (and the associated cell divisions), the telomeres are….. Elaborate

A

…completely lost and therefore no longer provide protection for the chromosome
- Essential DNA may be lost during subsequent replications. –> a new cell may lose its ability to function properly: may lose ability to grow, metabolize, or divide.
–> This period of decline= cell senescence, may account for the loss of certain functions in individuals as they age.
- Thus, telomeres are like a biological clock, counting down the total # of times that a cell can divide. –> This limit to cell division is = the Hayflick limit (after Leonard Hayflick who discovered it in the 1960s).

66
Q

cell senescence is

A

the period in a cell’s lifespan when it loses the ability to divide & grow; often referred to as cell aging

67
Q

The Hayflick limit is

A
  • the total # of times that a normal cell can divide
  • The Hayflick limit is diff for each species.
    –> Ex, in humans, a cell can divide about 50 times before its telomeres become too short.
  • Although the Hayflick limit is diff for diff species, the length of a species’ telomeres is not necessarily related to how long individuals of the species live.
    –> Ex, a mouse’s telomeres are longer than a human’s
68
Q

Germ Line Cell Replication

A

Germ line cells (which make gametes) r unique cuz they must be able to continue replicating.
- They must maintain their genetic integrity from parent to offspring, gen after gen. –> These cells cant tolerate any loss of genetic material, even telomeres that would eventually run out & leave coding DNA at risk.
–> In these cells, an enzyme called telomerase adds more DNA to the shortening telomeres, continually restoring their length.
–> Stem cells & certain white blood cells also show the presence of telomerase.

69
Q

Telomeres & Aging

A
  • Once a cell reaches its Hayflick limit & senescence begins, the cell’s functioning begins to decline, effectively “aging” the same way that people do.
  • cuz not all cells in an organism reproduce at the same rate, an organism’s cells undergo senescence at
    different times.
  • As an organism ages, more of its cells reach senescence. This makes it more difficult for healthy cells to function at their optimum level.
  • Evidence by gerontologists (scientists who study aging) strongly links certain age-related diseases, such as atherosclerosis, dementia, and macular degeneration, to the senescence of specific cell groups in our bodies.
70
Q

Dolly the Sheep & Telomeres

A
  • Dolly was born in July of 1996 and 1st mammal to be cloned from a mature somatic cell.
  • Cloned from a 6 year old donor’s cell with shorter telomeres, Dolly lived only 6 years, sparking debate over telomere length’s impact on lifespan cuz expected lifespan of sheep of Dolly’s breed is 11 to
    12 years –> she died from complications arising from progressive lung disease & severe arthritis
  • reserchers couldn’t conclude on a link between the shorter telomeres & Dolly’s death cuz it is not unusual for normal sheep to die prematurely from the same
    conditions that Dolly had
  • No conclusive link has been established between donor cell telomere length and clone longevity.
71
Q

How to acc reduce rate of telomere shortening

A
  • Studies suggest that regular exercise and a healthy diet may slow telomere shortening and promote telomerase activity, potentially supporting longevity.
  • Negative lifestyle factors like obesity & smoking are linked to shorter telomeres.
72
Q

Telomeres & Cancer

A
  • The relationships between shortened telomeres & diseases r not clear
  • Cancer cells can be dangerous cuz they never stop dividing. –> cuz cancerous cells produce the enzyme telomerase in great quantities.
  • The telomerase replaces the telomeres that r lost during cell division.
  • Such a growing mass of cancer cells can interfere with other cell groups or organs in the body & cause serious and often life-threatening diseases.
  • knowledge of the role of telomerase has led to new therapies that target & inhibit the production of telomerase within cancer cells.
    –> Shortening telomeres in pre-cancerous cells might naturally stop cell division before cancer develops, but some cells adapt by increasing telomerase production.
73
Q

Telomerase is

A

an enzyme that adds new
telomere sequences to the ends of
chromosomes