Chapter 6 Flashcards

1
Q

Acid catalyze addition of an alcohol

A

Hydrogen goes to a carbon, the rest goes to the other carbon, same as addition of water

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2
Q

Ether

A

R-O-R

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3
Q

Rearrangement

A

Tertiary carbocation are more stable, so prioritized and produce a surprise product that is major

Can only shift hydrogens and alkyl group 1 bond away

Ex: 1,2-Hydride shift (doesn’t have to be carbon 1 to 2, just means shift to next carbon)

If changes from a ring to a bigger ring will deminish angle strain

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4
Q

hydroboration-oxydation

A

BH3 Electrophile

Flat molecule with empty p orbital waiting for electrons

When added to reaction, gives the antimarkovnikov product

OH added where most hydrogens
H added where least hydrogens

No rearrangements

1.BH3/THF
2. HO-, H2O2, H2O

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5
Q

Addition Br2 or Cl2

A

Each Br or Cl goes to a carbon

Vicinal dibromide or dichloride (dihalide)

Produces cyclic bromonium ion as an intermediate

Product are initially anti and will rotate (if single bond) because second halide comes from the opposite side of the one in the cyclic
called an anti addition

If in a ring (ex cyclopentane) then doesn’t rotate, stays anti, always trans

No rearrangement because cyclic bromonium ion is not a carbocation

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6
Q

Addition I2

A

Alkenes do not add I2, product unstable, equilibrium lies to the left

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7
Q

Conversion of alkenes to vicinal halohydrins

A

Anti addition

Addition of halogen and something with OH (ex water)

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8
Q

Halohydrin formation

A

Br and ROH are anti, so trans, (wedges and dash)

Oxygen goes to place with less hydrogen, even if it causes steric hynderance
X goes to place with most hydrogens (less alkyl group)

In transition state, bond breaking which is making carbon more positive is quicker than bond forming with O, so carbon better at stebalizing this positive charge is the one with the most alkyl groups

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9
Q

Transition state

A

Up in the G graph

Show bonds breaking and forming as dashed lines

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10
Q

Ozonolysis of alkene

A

Produces ozonide

O3

Splits molecule in half with each an oxygen and a double bond between oxygen and carbon

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11
Q

Stereoselective

A

Solution is selective of a stereoisomer

Can be not stereoseletctive if X can go equally up and down on the planar molecule

If the reactant does not have an asymmetric center and the reaction forms a product with an asymmetric center, the product will be a racemic mixture.

If the reactant has an asymmetric center and the reaction forms a product with a new asymmetric center, the product will be a pair of diastereomers.
X will come for place with less substrates (if CH3 dashed, then X will be wedged)

Will produce syn (same side) or anti (opposite side)

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12
Q

Syn addition to trans and trans isomers

A

Trans: threo Fischer projection (same groups on opposite sides)
Cis: erythryo Fischer projection (same groups same side)

Cis anti threo can change 2 but not 1 or 3

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