Chapter 5: Linkage Recombination and Eukaryotic Gene Mapping Flashcards
What information about recombination frequencies enables scientists to create linkage maps?
A) The recombination frequency between two genes reveals the nucleotide sequence of the two genes
B) The lower the recombination frequency, the farther apart two genes are on a chromosome
C) The recombination frequency is proportional to the distance between the two genes
D) The recombination frequency between two genes is equal to the distance in nanometers between the two genes
C
C) The recombination frequency is proportional to the distance between the two genes
A researcher crosses and F1 heterozygous progeny (BbTt x BbTt) and the F2 progeny is shown below:
BBtt = 24
BbTt or BBTT = 55
bbTT = 26
bbtt = 2
What is the most likely explanation for why homozygous recessive progeny (bbtt) are in this cross?
A) Recombination
B) Random mutagenesis
C) Horizontal gene transfer
D) Independent assortment
A
A) Recombination
In German cockroaches, bulging eyes (bu) are recessive to normal eyes (bu+). Curved wings (cw) are recessive to straight wings (cw+). Both traits are encoded by autosomal genes that are linked.
A cockroach has genotype bu+ bucw+ cw and the genes are in repulsion. (the spacing in the genotype matters)
Which set of genes will be found in the most common gametes produced by this cockroach?
A) bu cw+
B) bu+ bu
C) cw+ cw
D) bu+ cw+
E) bu cw
A)
A) bu cw+
This is because these genes are nonrecombinant and will appear more commonly than recombinant genes.
Two heterozygous individuals procreate. Predict the amount of possible phenotypes of the progeny if…
R is completely dominant to r
Only 2 possible phenotypes.
Explanation: If R is completely dominant to r then RR and Rr have the same phenotype, leaving rr to be the second possible phenotype
Two heterozygous individuals procreate. Predict the amount of possible phenotypes of the progeny if…
R is codominant with r
3 possible phenotypes
Explanation: Since R is not completely dominant over r, RR will be its own phenotype, rr will be its own phenotype, and Rr will be its own phenotype between the two opposites, leading to a total of three phenotypes.
Two heterozygous individuals procreate. Predict the amount of possible phenotypes of the progeny if…
R and S are completely dominant to r and s. R and S are linked by 20 m.u. and do not interact with each other.
Four possible phenotypes
Explanation: In the Rr x Ss cross, you get 4 results. RRSS, RRss, rrSS, and rrss. This results in 4 different phenotypes.
What is Mendel’s first law?
Equal segregation of gametes
What is Mendel’s Second Law?
Independent assortment of gene pairs
What products are made in prophase I when NO CROSSING OVER takes place?
Each gametes receives a nonrecombinant chromosome with an original combination of alleles.
What products are made if crossing over DOES take place in prophase I?
Half of the resulting gametes will have an unchanged chromosome (nonrecombinant) and half will have a recombinant chromosome
Define coupling
When wild-type alleles are together on one chromosome
Define repulsion
When wild type alleles are on different chromosomes
Define genetic map unit (m. u)
The percent chance of a recombination between two locations on a chromosome (also called a centimorgan)
How many map units are there if you have a recombinant frequency of 0.01%?
1 m. u
How does a genetic map differ from a physical map?
Genetic maps are based on rates or recombination while physical maps are based on physical distances (bases)