Chapter 4 Flashcards
First Derivative Test
Take the derivative of f(x)
Find the zeros from f1(x), these zeros display critical points on the graph
Plug 0 values in for f1(x), if the values are negative, the graph is concave down on that section. If they are positive, it is concave up.
Second Derivative Test
Take the second derivative of f(x), or the derivative of f1(x)
plug the zero values into the fII(x) function. if the value is negative, it represents a local maximum. If it is positive, it represents a local minimum. If it is 0, refer to fI(x) for its value
Mean Value Theorem
If you are looking at a graph, with 2 points comprising an integral, there exists a point whose tangent slope is equal to the secant slope of the two points.
f1(c) = (f(point2) - f(point1)/point2 - point1
Find the derivative of f(x), set it equal to the slope from plugging values in and solve
Newtons Method
Use Calculator: y1 = f(x) y2 = fI(x) y3 = y1/y2 y4 = x - y3
There will be an equation and an x value given, y4 = your new x value, complete until you reach the desired steps
Shortest Distance of Point on a graph from origin
Line = 3x + 4, D = sqrt(x-0^2)(y-0)^2 D = x^2 + y^2
- Substitute y with slope ==> D = x^2 +(3x+4)^2
- Take derivative of equation above: 2x + 2(3x+4)(3)
20x-24 = -6/5 - Plug value back into original equation
Linear Approximation
L(x) = f(a) + fI(a)(x-a)
- f(x) is gien as f(x) = sqrt(x+3)
- Find Derivative of Equation = 1/2sqrt(x+3)
- Linearize by plugging in a value = 1 + 1/4(x-1)
- Plug desired values in for X
L’Hospitale’s Rule
When given a limit as a fraction, when you plug in X and the top is either 0/0 or infinity/infinity, take the derivative of both the top and bottom and plug x back in. repeat until you don’t receive an indeterminate form
Indeterminate forms of a function
0/0 (0)(infinity) (0^0) 1^infinity infinity^0
any kind of ininity as the numerator and denominator: infinity/infinity -infinity/infinity infinity/-infinity -infinity/-infinity