Chapter 4 Flashcards
hydrochloric acid
HCl
sulfuric acid
H2SO4
nitric acid
HNO3
ethanoic acid/vinegar
CH3COOH
acid characteristics
ph under 7
contains H in formulae
releases H+ ions in solution when dissolved in water
strong acid
completely dissociates in aqueous solution
weak acid
partially dissociates in aqueous solution
base
neutralises an acid to form a salt
alkali
base that dissolves in water and releases OH- ions
metal oxides
MgO
CaO
CuO
metal carbonates
Na2CO3
CaCO3
CuCO3
alkali
NaOH
KOH
NH3
acid +alkali ->
salt + water
acid + metal oxide ->
salt + water
acid +metal carbonate ->
salt + water+ carbon dioxide
acid+ metal ->
salt +hydrogen
neutralisation
H+ and OH– to form H2O
- The student prepares a 250.0 cm3 solution from 1.513 g of A.
- The solution of A is added to the burette and titrated with 25.0 cm3 volumes of 0.112 mol
dm−3 NaOH(aq). - 1 mol of A reacts with 2 mol of NaOH.
- The student obtains a mean titre of 27.30 cm3.
i. Calculate the molar mass of A from these results.
n(NaOH) = 0.112 x 25/1000 = 0.00280
n(A) IN 25cm3 = 0.00280/2 = 0.00140
n(A) in 250cm3 = 0.00140 x 250/27.30= 0.0128
Mr(A) = 1.513/ 0.0128 = 118g mol-1
titration
technique used to accurately measure the volume of one solution that reacts exactly with another
titrations used for
finding concentration of a solution
identification of unknown chemicals
finding purity of a substance
standard solution
solution of known concentration
preparing a standard solution
- solid is weighed and dissolved using less water than needed to fill
- solution is transferred to a volumetric flask (last bits rinsed with distilled water)
- flask filled to graduation line by adding water drop at a time until bottom of meniscus aligns
- invert flask to mix the solution thoroughly
acid- base titration procedure
- add measured volume of one solution to conical flask
- add the other solution to a burette and record initial reading to 0.05 nearest
- add indicator to conical flask
- run solution in whilst swirling- colour change= end point of titration
- record final reading, difference= titre
(trial is done to find approximate titre) then is repeated accurately until two titres are concordant
concordant
within 0.10m3 of eachother