Chapter 28 (Amines) Flashcards

1
Q

Why do primary aliphatic amine act as bases?

A

The lone pair on the nitrogen is readily available to form a covalent bond with a H+ so accepts a proton.

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2
Q

Why are primary aliphatic amines weak bases?

A

Only a low concentration of hydroxide ions is produced.

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3
Q

Why are primary aliphatic amines stronger bases than ammonia?

A

The alkyl groups are electron releasing and push electrons towards the nitrogen atom and make it a stronger base.

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4
Q

Why are secondary amines stronger bases than primary amines?

A

They have more alkyl groups that are substituted onto the N atom in place of H atoms. Therefore the electron density is pushed onto the N atom.

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5
Q

Why are tertiary amines weaker bases than secondary amines?

A

Tertiary amines are less soluble in water.

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6
Q

Why are aromatic amines weaker bases than aliphatic?

A

The lone pair of electrons on the nitrogen delocalise with the ring of electrons in the benzene ring so the N is less able to accept protons.

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7
Q

Equation between methyl amine and proton

A

CH3NH2 (aq) + H+ (aq) > CH3NH3+(aq)

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8
Q

Example of equation between secondary amine and proton

A

(CH3CH2)2 NH (aq) + H+ (aq) > (CH3CH2)2NH2+(aq)

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9
Q

Example of equation between tertiary amine and proton

A

(CH3CH2)3 N (aq) + H+ (aq) > (CH3CH2)3NH+(aq)

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10
Q

What is reacted with an amine to form an ammonium salt?

A

A base

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11
Q

What is added to an ammonium salt to convert it back to an amine?

A

NaOH

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12
Q

How do ammonium salts appear?

A

Ionic crystals after water has been evaporated due to strong ionic interactions

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13
Q

How is a buffer formed from an amine?

A

Combing a weak base with a salt of that base

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14
Q

What mechanism forms primary amines?

A

Nucleophilic Substitution

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15
Q

Why is nucleophilic substitution not a good way to form primary amines?

A

The lone pair on the N can react in a successive of reactions to form other amines and ammonium salts. This means that the desired product would need to be separated from the other products.

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16
Q

What is the initial nucleophile in the mechanism to form primary amines?

A

Ammonia dissolved in ethanol

17
Q

How can the yield of primary amines be increased?

A

Use excess ammonia which limits subsequent reactions.

18
Q

How is a secondary amine formed from a primary amine?

A

The lone pair of electrons on the N will react with a haloalkane.

19
Q

How is the yield of ammonium salts increased?

A

Excess of haloalkanes

20
Q

What can ammonium salts be used for and what is their purpose?

A

Cationic surfactants

Reduce the surface tension of liquids as the positive nitrogen is attracted towards a negatively charged surface.

21
Q

Describe the method for preparing amines from nitriles

A

1) Convert haloalkane to nitrile using KCN in ethanol

2) Reduce nitrile to amine using LiAlH4 or by reducing with H2 and Ni catalyst.

22
Q

Whats are the reagents, conditions and mechanism for reducing a nitroamine to an aromatic amine?

A

Reagent: Sn and HCl or Fe and HCl

Condition: Heat

Mechanism: Reduction

23
Q

What is the disadvantage of using a haloalkane first to produce an amine from a nitrile?

A
  • Two step reaction so may have a lower yield

* Uses KCN which is toxic

24
Q

What is the reagent and condition for changing functional group from acyl chloride/acid anhydride to secondary amide and what type of mechanism?

A

Reagent: Primary amine

Conditions: Room Temperature

Mechanism: Nucleophilic addition-elimiantion

25
Q

What is a use of aromatic amines?

A

Dye making as cause colour change and ability of dyes to bond to fabric

26
Q

Why do the methods for making aliphatic amines not work for aromatic amines?

A
  • Benzene rings repels nucleophile due to delocalised electrons. N in ammonia is nucleophilic.
  • Aromatic ring is e- attracting so lone pairs of halogens are pulled towards the ring. Shortens the C-X bond making it less reactive.
27
Q

Why are two moles of ammonia used when reacting with acyl chloride/acid anhydride?

A

First acts as a nucleophile and seconds acts as a base (deprotonates the amine group)

28
Q

Give order of base strength weakest to strongest

A

Aromatic < Ammonia < Primary < Tertiary < Secondary