Chapter 24 - Particle Physics Flashcards
Alpha scattering experiment
- A narrow beam of photons (with the same Ek were fired at a thin sheet of gold foil)
- The alpha particles were scattered and detected on a zinc sulfide screen mounted on the end of a microscope
- Each alpha particle created a tiny speck of light so they counted the amount of particles scattered through different angles per minute
Alpha scattering experiment observations
If the plum pudding model were correct all of the alpha particles would have passed straight through
- Around 1 in every 2000 particles were scattered
- Around 1 in every 10000 was deflected at an angle >90
Alpha scattering experiment findings
Most of the atom was empty space (most passed through)
The atom had a concentration of mass (some deflected at angles >90)
The atom had a concentration of positive charge (some deflected)
The nucleus must have a size of around 10^-14 m
Charge of a nucleus formula
Q = +/- Ze
where Z is the atomic number
Why were alpha particles scattered
Because of the electrostatic repulsion with the electric field of the nucleus, they wouldn’t actually hit the nucleus
Kinetic energy formula from the alpha scattering experiment
Ek = Qq/4πε0d
where Q, q are the two charges and d the distance to the nucleus
Size of a nucleus
Around 10^-15 m
Size of an atom
Around 10^-10m
Isotopes
Nuclei of the same element that have the same amount of protons but a different amount of neutrons
Atomic labelling system
A
X
Z
where A is the nucleon number (protons + neutrons) and P is the proton number
Atomic mass unit (u) definition
One twelfth of the mass of a neutral carbon-12 atom
Atomic mass unit (u)
(1.661 x 10^-27)kg
Protons and neutrons can be treated as having a mass of 1 u and electrons 0
Radius of a nucleus formula
R = r0 A^1/3
where r0 is the minimum radius of a nucleus and A the nucleon number
r0
around 1.2 x 10^-15
Finding density of a nucleus
Mass is nucleon number x u
Volume is 4/3 π r^3
ρ = m/V