Chapter 20: Electrochemistry Flashcards
Oxidation
Loss of electrons
Reduction
Gain of electrons
Balancing oxidation-reduction equations: Acidic solutions
1) Assign oxidation states and identify substances being oxidized or reduced
2) Separate overall reaction into two half-reactions
3) Balance each reaction: (a) balance all elements other than H&O, (b) balance O by adding H2O, (c) balance H by adding H+
4) Balance half reaction wrt charge by adding e-
5) Make number e- in both half-reactions equal by multiplying one or both by small whole number
6) Add half-reactions; cancel electrons as necessary
7) Verify
Balancing redox reactions: Basic solutions
1) Assign oxidation states; identify substances being oxidized/reduced
2) Separate into half-reactions
3) Balance all elements except H&O, balance O with H2O, balance H by adding H+, neutralize H+ by adding enough OH- to neutralize each H+; add sam number OH- to each side of the equation
4) Balance wrt charge (electrons)
5) Make number of electron equal for both
6) Add equations
Electrical current
Flow of electric charge
Electrochemical cell definition
Generation of electricity through redox reactions carried out in this device
Voltaic (Galvantic) cell definition
Electrochemical cell that produces electrical current from a spontaneous chemical reaction
Electrolytic cell definition
Consumes electrical current to drive non spontaneous reactions
Voltaic Cell Components
- Half-cell (one of the two electrodes)
- Anode: Electrode where oxidation occurs
- Cathode: Electrode where reduction occurs (electrons flow into cathode)
- Salt bridge (inverted, U-shaped tube with strong electrolytes to connect half-cells)
Ampere
(A) AKA amps; measurement of electrical current
Potential difference and its significance
- Measure of difference in PE (joules) per unit charge (coulombs)
- Large potential difference corresponds to strong tendency for electron flow
Cell potential (Ecell or cell emf)
- Potential difference between two electrodes
- Depends on relative tendencies of cell to undergo oxidation and reduction; concentrations of reactants and products in the cell and temperature
E˚cell
- Standard cell potential (1M, 1 atm, or 25˚C)
E˚cell = E˚final - E˚initial | E˚cathode - E˚anode
Cell diagram/line notation
- Represent electrochemical cell with compact notation
1) Write oxidation of half-rxn. on the left; reduction on right. Double vertical line represents salt bridge.
2) Substances in different phases are separated by single vertical line
3) For some redox rxns, reactants/products of one or both of half-rxn. may be in same phase; separate reactions and products from each other with comma in line diagram
Standard electrode potential
Electrode in each half-cell’s own individual potential
Standard hydrogen electrode
- Half-cell electrode normally chosen to have potential of zero
Summary of Standard Electrode Potentials
- Electrode in any half-cell with greater tendency to undergo reaction is positively related to SHE
- Electrode in any half-cell with lesser tendency negatively charged
- Cell potential of any electrochemical cell is difference between electrode potentials of cathode and anode
- Ecell is + for spontaneous reactions and - for non spontaneous reactions
Calculating Standard Potential
1) Separate into oxidation and reduction reactions
2) Use standard electrode potentials; add half reactions, calculate E˚cell
3) E˚cell = E(cathode) - E(anode)
Predicting Spontaneous Reactions
- Half-reaction with more positive electrode potential will attract more electrons and undergoes reduction
- Half-reaction with more negative repels and undergoes oxidation
- Any reduction reaction is spontaneous when paired with reverse of any reactions listed below on table
Predicting whether metal will dissolve in acid
- Most acids dissolve metals by reduction of H+ ions to hydrogen gas and corresponding oxidation of metal to its ion
- Generally metals whose half-reactions are listed below reduction of H+ to H2 dissolve; metals above do not
Faraday’s Constant
- Quantifies charge that flows in an electrochemical reaction; change in charge of coulombs of 1 mol of electrons (C/e-)
∆G˚ = -nFE˚cell
Relating E˚cell and K
E˚cell = 0.0592V/n(logK)
Cell Potential and Concentration (Nernst)
Cell = E˚cell - (0.0592V/n)(logQ)
Nernst Equation:
Q = 1
Q < 1
Q > 1
- Ecell = E˚cell
- Ecell > E˚cell
- Ecell < E˚cell
