Chapter 2: Quadratics Flashcards

1
Q

4 ways of solving quadratic equations?

A

-Factorisation
-Solving without factorisation
-Completing the square
-Quadratic formula

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2
Q

1st step in solving 2x+√x+1=0

A

Let √x=y

2y^2+y+1=0
Solve…

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3
Q

For solving without factorisation method, solve:

(x-1)^2=5

A

x-1=+/-√5
x=+/-√5

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4
Q

For ax^2+bx+c=0

How do I solve for x?

A

x=-b+/-√b2-4ac
2a

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5
Q

When is the quadratic formula most appropriate to use?

A

-Co-efficient of x^2 is large
-3 parts are hard to be easily divided by a number

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6
Q

Define completing the square.

A

Putting a quadratic equation in the form (x+a)^2+b=0/a(x+b)^2+c=0

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7
Q

When is completing the square often used.

A

When x only appears once in the expression (ie (x+2)^2)

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8
Q

Solve, using completing the square, 3x^2-18x+4=0

A


(x-3)^2-23/3=0
(x-3)^2=23/3
x-3=+/-√23/3
x=+/-√23/3 + 3

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9
Q

Prove, using completing the square, that ax^2+bx+c=0

x=-b+/-√b2-4ac
2a

A

x^2/a+bx/a+c/a=0
(x+b/2a)^2-b^2/4a^2+c/a=0
(x+b/2a)^2=b^2/4a^2 - c/a
(x+b/2a)^2=b^2-4ac/4a^2
x+b/2a=+/-√b^2-4ac
2a
x=-b+/-√b2-4ac
2a

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10
Q

Define the domain of a function.

A

Set of values of possible inputs of function.

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11
Q

Define the range of a function.

A

Set of values of possible outputs of a function.

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12
Q

Define the roots of a function.

A

Values of x when f(x)=0

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13
Q

f(x)=2x-10
g(x)=x^2-9

a) Find g(5)
b) Find the values for x when f(x)=g(x)
c) Find the roots of f(x)
d) Find the roots of g(x)

A

a)
25-9=16
b)x^2-9=2x-10
x^2-2x+1=0
(x-1)(x-1)=0
x=1
c)2x-10=0
2x=10
x=5
d)x^2-9=0
(x+3)(x-3)=0
x=3 or x=-3

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14
Q

How can you determine the value of the maximum/minimum of a function.

A

By completing the square

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15
Q

(x-3)^2-7
What is the minimum value.

A

(3,-7)

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16
Q

How do I know what the minimum value would be of a function, in terms of inputting values?

A

Putting in number that will produce lowest possible output, 0, and then output of this is the minimum value of function.

17
Q

How can you prove that completed-the-square versions of quadratics will always create minimum values, not maxima?

A

As anything squared=0

Therefore co-efficient of x^2 is positive.

Therefore u-shaped parabola.

Therefore turning point of quadratic will be a minimum point.

18
Q

Discuss the general shape of a quadratic graph.

A

-Depends on co-efficient of x^2
-If x^2 is greater than 0, then u-shaped parabola
-If x^2 is less than 0, then n-shaped parabola

19
Q

Y-intercept?

A

Value of y when x=0

20
Q

X-intercept?

A

Value of x when y=0

21
Q

Roots of a quadratic function?

A

Values of x when f(x)=0

Therefore as y=0, x-intercepts of graph.

22
Q

Minimum/maximum value of graph?

A

Highest/lowest point of curve, discovered by process of completing the square.

23
Q

What are the components of a sketch?

A

-General shape drawn, no specific points
-Axes values not written
-Only special co-ordinates of interest are usually included, like intercepts or POIs of multiple lines etc.

24
Q

Equation of line of symmetry is calculated how for a quadratic graph?

A

X-value of minimum=eqn. of line of symmetry

e.g.
Minimum (-3,-7)

Line of symmetry eqn. x=-3

25
Q

If the minimum point is (5,-2), what is the equation of the normal to this quadratic eqn.

A

Same as line of symmetry to curve,
minimum x-co-ordinate=5
Therefore, eqn. of normal to curve: x=5

26
Q

In the graph of y=ax^2+bx+c=0

The graph has a minimum at (7,-2) and passes thru. (8,0). Find a,b, and c.

A

Minimum (7,-2)
Therefore, line of symmetry x=7
For (8,0) reflection in line of symmetry x=7= (6,0)

Therefore, 0=(x-8)(x-6)
x^2-14x+48=0
a=1 b=-14 c=48

27
Q

For graphs with 2 roots that do not multiply to give y-intercept, how do we know what the eqn. is?

Exemplify.

A

Multiply by this as a scale factor
e.g. Roots=6,2
Y-intercept=3
3/12=1/4

Hence, 1/4(x-6)(x-2)
Expand.

28
Q

A line of ax^2+bx+c=0 passes through (6,0) with a minimum (5,-3). What are a,b,c.

HINT: At end of calc. when completed square, minimum occurs?

A

Minimum= (5,-3)
Line of symmetry: x=5

Reflection of (6,0) in line of symmetry x=5 is (4,0)

(x-6)(x-4)
=x^2-10x+24

Complete square:
(x-5)^2-25+24
(x-5)^2-1
Not give minimum (5,-3)

So, let scale factor=k
k(x-6)(x-4)

Sub (5,-3) into eqn:
-3=k(5-6)(5-4)
-3=k(-1x1)
-3=-k
k=3

Therefore, 3(x-6)(x-4)
3(x^2-10x+24)
=3x^2-30x+72

a=3,b=-30,c=72

29
Q

If the discriminant, b^2-4ac is greater than 0?

A

2 distinct, real roots.

30
Q

If discriminant=0

A

Equal, repeated roots

31
Q

Discriminant is less than 0?

A

No real roots.

32
Q

For a quadratic curve of 2 distinct, real roots?

A

Passes thru x-axis twice (when x=0 root occurs)

33
Q

For a curve of equal, repeated roots?

A

Touches it once, hence is tangent to x-axis.

34
Q

For a curve of no real roots?

A

Never touches/passes thru. the x-axis (minimum/maximum above/below the axis).

35
Q

Hence,

e.g. Find, using the discriminant, the values of K when L is a tangent to C.

A

If tangent, one solution, therefore repeated roots, b^2-4ac=0

Apply this to eqn of POI of L and C.

36
Q

Discuss the relation of p(x=q)^2+r=0 of r in this equation and the real roots of the equation.

A

If r is greater than 0, no real roots, with min point above the x-axis.
If r=0, there is equal, repeated roots, with the min point being on the x-axis (equation tangent to it).
If r is less than 0, two distinct real roots, min point below x axis, with equation passing thru. it twice.

37
Q

What is modelling in mathematics?

A

Utilisation of mathematical theory in real-life situations.

38
Q

Why are models used?

A

They can be used to solve a problem in a real-life situation, where normally some simplifying assumptions are applied.