Chapter 2: DNA Replication and Repair Flashcards
Polymerases?
enzymes that synthesize nucleic acids by forming phosphodiester (PDE) bonds
Nucleases? (moreso MOA)
enzymes that hydrolyze PDE bonds
Exonucleases?
remove nucleotides from the 5’ or the 3’ end of a nucleic acid
Endonucleases?
cut within the nucleic acid and release nucleic acid fragments
Is the p arm of the chromosome the long or short arm?
short arm
Is the q arm of the chromosome the long or short arm?
long arm
High fidelity synthesis occurs with RNA polymerase or DNA polymerase?
DNA polymerase
Low fidelity synthesis occurs with DNA or RNA polymerase?
RNA polymerase
Do you need primer for RNA polymerase?
no primer needed
Compare and contrast require substrates for DNA or RNA polymerase?
dATP, dGTP, dCTP, dTTP (for DNA polymerase)
ATP, GTP, CTP, UTP (for RNA polymerase)
Do you require primer for RNA polymerase?
no
Is there proofreading activity with RNA polymerase? DNA polymerase?
no
yes
List the steps in DNA replication. (prokaryotes)
- Base sequence at the origin of replication is recognized
- Helicase breaks the H bonds holding the base pairs together. This allows the 2 parental strands of DNA to begin unwinding and forms 2 replication forks
- ssDNA binding protein (SSB) binds to the single stranded portion of each DNA strand, preventing them from reassociating and protecting them from degradation by nucleases
- Primase synthesizes a short (about 10 nucleoties) RNA primer in the 5’ -> 3’ dir., beginning at the origin on each parental strand; parental strand is used as template.
- DNA polymerase III begins synthesizing DNA in the 5’ -> 3’ direction, beginning at the 3’ end of each RNA primer. Strand can be made continuously in one long piece (“leading strand”)
- RNA primers are removed by RNAase H in eukaryotes and an uncharacterized DNA polymerase fills in the gap with DNA; in prokaryotes, DNA polymerase I both removes primer (5’ exonuclease) and synthesizes new DNA, beginning at the 3’ end of the neighboring Okazaki fragment
- Both eukaryotic and prokaryotic DNA polymerases proofread
- DNA ligase seals the “nicks” between Okazaki fragments, converting them to. a continuous strand of DNA
- DNA gyrase (DNA topoisomerase II) provides a “swivel” in front of each replication fork. As helicase unwinds DNA at replication fork the DNA ahead of it becomes overwound and positive supercoils form. (DNA gyrase inserts negative supercoils be nicking both strands of DNA, passing DNA strands through the nick, and then resealing both strands.)
Why are RNA primers required for DNA polymerase?
because DNA polymerases are unable to initiate synthesis of DNA can only extend a strand from the 3’ end of a preformed “primer”
What is the lagging strand?
synthesized discontinuously as series of small fragments known as Okazaki fragments
Each Okazaki fragment is initiated by synthesis of an RNA primer by a primase, and then completed by synthesis of DNA using what enzyme?
DNA polymerase III
Purpose of RNAase H?
5’ exoribonuclease acivity
digest the RNA primer from fragment 1
In eukaryotic cells, DNA polymerase extends the next fragment to fill in the gap
In prokaryotic cells DNA polymerase 1 has both the 5’ exocnulease acitivity to remove primers, and the DNA polymerase acitivty to extend the next fragment to fill in the gap
In both types of cells DNA ligase connects fragments 1 and 2 by making a phosphodiester bond
What is telomerase?
completes replication of the telomere sequence at both ends of eukaryotic chromosome
Where is telomerase present?(What type of cells)
embryonic cells, fetal cells, and certain adult stem cells;
inappropriately present in many cancer cells
Where is telomerase not present?
in adult somatic cells
What are telomeres?
repeitive sequences at ends of linear DNA moelcules in eukaryotic chromsomes
Relate telomeres and aging of cells?
with each round of replication in most normal cells the telomeres are shortened because DNA polymerase cannot complete synthesis of the 5’ end of each strand
Compare and contrast origin of replication for prokaryotes and eukaryotes.
Prokaryotes:
one ori site per chromsome
Eukaryotes:
multiple ori sites per chromsome
Compare and contrast how unwinding of DNA double helix is performed in prokaryotes and eukaryotes?
helicase in both