Chapter 18 Lognormal Distribution Flashcards
pdf of a Normal Distribution
(1/(sigma * sqrt(2pi))) * exp(-(1/2) * (((x - u) / (sigma))^2))
What is symmetry of a distribution and does the normal distribution have this property
it is phi(mu - x) = phi(mu + x) for the same sigma and mu and yes it has it
N(-a) =
1 - (N(a))
aX1 + bX2 where x1 and x2 are normally distributed
N(amu1 + bmu2, sigma1 + sigma2 + 2abcovsigma1*sigma2)
Central Limit Theorem
As number of observations grow very large, it resembles a normal ditribution.
A variable y is log normal if
ln(y) is normal
why are stock prices lognormal distributed.
The returns are normally distributed, and ln(st/s0) = r(0,t), then st = e(r(0,t)) * s0
the product of lognormal distributions is
lognormal
e^(x) * e^(y) = e^(x+y) and x + y is normal
pdf of lognormal
(1/(y * sqrt(sigma^2 * 2pi))) * exp(-(1/2) * ((ln(y) - mu)/sigma)^2)
Expected value of a lognormal distribution
e^(mu + (1/2) * sigma^2)
Using the lognormal model for stocks, we find St =
s0 * exp(((a-delta-1/2(sigma^2))t) + sigma * sqrt(t) * Z)
In lognormal model, E(St) =
s0 * exp((a - delta) * t)
Median price for ST in the lognormal model
Set Z = 0
s0exp((a - delta - 1/2sigma^2)*t)
using log-normal pricing P(S < K)
N(-d2) with A (actual rate) replacing r risk free rate
using log-normal pricing P(S > K)
N(d2) with A (actual rate) replacing r risk free rate
getting intervals using the log-normal model is done by
finding mean and SD of St, then plug in p like always and exponentiate and divide by S0
E(st | st < K) i.e. a put
s0 * (exp(a - delta)*t) * (n(-d1) / n(-d2))
For a call there are no negatives on the ds
for mean adding more frequent periods of data
does nothing
for SD adding more frequent periods of data
helps improve accuracy
the lognormal model predicts that returns on stocks will be normal, but in practice, they
have leptokurtosis (peak around 0) and fat tails one explanation is normal but mean an sd change over time.
order statistics
is the data in order
i.e. 1,4,5,7,10…
normal probability plot
takes the value of the quantiles graphed agains the coresponding Normal quantile. So for 3, 4, 5, 7, 11, 3 is the 10% quantiles, so N-1(0.1) = -1.282 so, the first point is 3, -1.282. The straight line connects the 25 and 75 quantile and if the data is also a stright line then the plot is noral.