Chapter 14- Part 1 Discovery of DNA Flashcards

1
Q

Many scientists believed that ____ were most like hereditary molecule.

A

Protein

Several experiments, proved DNA not protein is genetic material.

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2
Q

What did the hammerling experiment determine?

A

Discovered hereditary information is stored in the cells nucleus.

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3
Q

Describe the hammerling Reciprocal graft experiment:

A

Cells of green alga were cut into peices and observed.

He interchanged two different types of alga bases (containing the nucleus) but inserted the stem of a different type.

The alga’s type of cap and color was corresponded with that of the nuclues, not of the stem.

Thus nuclues in the base determines type of cap regenerated.

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4
Q

Who conducted the transformation experiment that could genetically transform bacteria (transformation)? What were those bacteria?

A

Fredrick Griffith in 1928.

Two strains of streptococcus pneumonia:

  • Smooth strain(s) is highly infective (virulent) which quickly causes pneumonia and killing mice. Capsule might have caused it. Pathogenic.
  • Rough Strain (R) is nonvirulent and does not kill mice: non-infective, non-pathogenic.
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5
Q

What two bacterium did Griffith’s experiment study?

A

Two strains of streptococcus pneumonia:

  • Smooth strain(s) is highly infective (virulent) which quickly causes pneumonia and killing mice. Capsule might have caused it. Pathogenic.
  • Rough Strain (R) is nonvirulent and does not kill mice: non-ineffective, non-pathogenic.
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6
Q

What were the results of Experiment 1 in Griffiths experiment?

A

First, griffith, injected Mice with live S cells (control to show effect of S strain)

Results: Mice die, Live S cells in their blood(live s bacterium propagated inside organism), shows S cells are virulent and pathogenic.

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7
Q

What were the results of Experiment 2 in Griffiths experiment?

A

Second, Griffith injected live R cells into mice (control to show effect of R cells)

Results: Mice live. No live R cells in their blood; shows R cells cells are virulent.

Capsule is responsible for virulence of S strain.

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8
Q

In Griffith’s experiment, what is responsible for S train virulence?

A

The capsule is responsible of the S strain.

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9
Q

What were the results of Experiment 3 in Griffiths experiment?

A

In his third experiment, he injected mice with Heat-Killed S cells (control to show effect of S cells)

Results: Mice Live. No Live S cells in their blood; shows that live S cells are necessary to be virulent to mice.

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10
Q

What were the results of Experiment 4 in Griffiths experiment?

A

In his 4th experiment, Mice injected with heat-killed S cells plus live R cells.

Expectation: mice will live

Results: Mice Die. Live S cells in their blood shows that living R cells can be convereted into virulent S cells with SOME FACTOR [transforming principle] present in and derived from dead S cells.

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11
Q

In Griffith’s experiment, what happened when mice were injected with both heat-killed S cells and live R cells?

A

Mice Died. Live S cells were found in the blood which indicated that R cells can somehow be converted to virulent S cells by a transforming principle.

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12
Q

Who discovered the chemical nature of the transforming principle in Griffith’s experiment?

A

1940s- Oswald Avery, McLeoid, and McCorty

Discovered it was DNA.

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13
Q

Detail Avery’s Experiment.

A

Avery broke down heat-killed S bacteria and destroyed one class of molecules: proteins, DNA, or RNA.

When Proteins or RNA were destroyed, the extract still transformed live R cells to virulent S cells.

But when DNA was destroyed, no transformation occurred thus the TRANSFORMING PRINCIPLE was DNA.

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14
Q

What did Avery’s Experiment Discover.

A

When DNA was erased from S bacteria, R bacteria no longer transformed.

Thus, DNA had to be the transforming principle in Griffith’s Experiment.

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15
Q

In a nutshell, what did Avery’s experiment discover?

A

Avery removed all lipid and proteins from bacteria and found no reduction in transforming activity. DNA destroyed all transforming activity.

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16
Q

What did the Hershey-Chase, 1953 experiment do in a nutshell?

A

They labled DNA and proteins with radioactive isotope tracers and determined hereditary information was DNA not protein.

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17
Q

Describe the organism studied in the Hershey-Chase experiment.

A

Bacteriophages are viruses that can infect the bacterium [E.coli.]

This virus has a protein “head” [capsule] and a DNA core. A bacteriophage infects when the virus injects DNA into a bacterial cell.

Here they used radioactive 35 S to mark the protein and 32 P to mark the DNA.

35 S marked proteins like methonine and cystine.

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18
Q

What did Hershey and Chase want to determine?

A

Which of these molecules [DNA or proteins] is the genetic material that is injected into the bacteria.

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19
Q

What is a virus?

A

Infectious agent made of DNA or RNA surrounded by a protein coat. Reproduces only in a host cell, using host cell materials.

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20
Q

What “phage” did Hershey and Chase study?

A

T2 bacteriophage which consists only of a core of DNA surrounded by proteins.

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21
Q

Bacteriophage DNA was labeled with what?

A

Radioactive phosphorus

32P

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22
Q

Bacteriophage proteins were labled with what?

A

Radioactive sulfur
35 S

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23
Q

Detail the Hershey-Chase Experiment.

A

Two cultures of phages were created. One marked proteins with 35 S. The other marked phage DNA with 32 P.

Cultures of E.Coli were infected with one specific type.

These radioactive molecules were tracked.

These phages infected E.Coli by injecting their DNA to reproduce using the cell’s mechanism.

Then through MECHANICAL FORCES, the phage “coat” without the DNA is discarded.

These cultures were then blended and centrifuges to separate cells from virus.

The results were as follows: With the 35 S, protein marked phages, less than 1% of radioactivity in progeny phages. [Supernatant with coats were radioactive and the pellet with bacteria with Viral DNA not. progeny]

The 32 P marked culture showed >30% progeny radioactivity [pellet with progeny bacteria was radioactive and supernatant with coat not having any]

Result: 32P which was used in phage-infected cells and in progeny phages show DNA is genetic material.

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24
Q

What was the conclusion of the hershey-chase experiment?

A

A tangible amount of 32 P used to label DNA was found in phage-infected cells and later progeny phages indiciated DNA IS the genetic material.

35S used to label proteins, was found in phage coats after infection, but not within the infected cell or in progeny phages, showing proteins are not genetic material.

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25
Q

What was in the pellet and supernantant of the culture contaning 35S labeled phages?

A

The supernatant had radioactive phage coats with the pellet had no instance of radioactivity in affected E.coli and later progeny stages.

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26
Q

What was in the pellet and supernantant of the culture contaning 32P labeled phages?

A

The supernantant containing coats had no radioactivity while the pellet with infected bacturium had significant ammounts of radioactivity along with radioactivity in progeny phages proving DNA is the genetic material.

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27
Q

What did Maurice Wilkins and Rosalind Franklin study at KCL?

A

Using X-ray diffraction, they studied DNA structure.

Franklin devised that DNA has a helical structure based on her interperation of the X-shaped distribution of spots in the diffraction pattern.

28
Q

What is X-ray diffraction and who used it?

A

Used by Maurice Wilkins and Rosalind Franklin.

When X-ray beam is directed at a molecule in the form of a solid (ideally a crystal ) and positions of atoms in the molecule are deduced from diffraction patterns produced on photographic film.

29
Q

Franklin’s X-shaped DNA diffraction pattern was the basis for what?

A

Basis for watson and crick to develop a model for DNA structure.

30
Q

What is the main thing Rosalind Franklin discover?

A

Performed X-ray diffraction studies to identify the 3-D strucutre by using Maurice Wilkin’s DNA fibers she discovered that (a) DNA is helical and (b) DNA has a diameter of 2 nm and makes a complete turn every 3.4 nm. Deduced by the repeating pattern shown in diffraction patterns.

31
Q

How many base pairs and length in one complete turn of the helix?

A

10 Base Pairs.
3.4 nm.

0.34 nm b/w base pairs.

32
Q

What did Watson and Crick discovery of the structure of DNA molecule explain?

A

How genetic information is stored and replicated- launching a molecular revolution in biological sciences making it possible to regulate genetic traits and develop a universal molecular code.

33
Q

Did watson and Crick perform an experiment when determining the structure of DNA?

A

They DID NOT perform a single experiment themselves related to DNA and deduced the structure using evidence given to them from chargaff, franklin and others.

Their proposed double helix structure was already proposed by Franklin.

34
Q

What concerns the Nobel Prize for Watson, Crick and Wilkins?

A

They all shared a noble prize for their work in deducing DNA structure in 1962 but it was not awarded posthmously to Franklin who died in 1958 because of cancer from X-ray radiation.

35
Q

Briefly describe DNA structure.

A

DNA is composed of nucleotides (is a nucleic acid).

Has a 5 Carbon sugar called deoxyribose.

A phosphate(PO4) group is attached to the 5’ carbon.

A Nitrogenous base (Adenine, thymine, cytossine, guanine) - split into purines and pyrimidines.

Free Hydroxyl (-OH)group at the 3’ carbon

2’ Carbon has OH in RNA and H in DNA.

Sugar is known as ribose.

36
Q

What is the sugar in DNA called?

A

Ribose; deoxyribose.

37
Q

Purines have how many rings?

A

2 rings
Adenine and Guanine

38
Q

Pyrimidines have how many rings?

A

1 Rings: Cytosine, Thymine(DNA only), and Uracil(RNA only)

39
Q

What nitrogenous bases are Pyrimidines?

A

Cytosine, Tyrosine, Uracil all have 1 ring.

40
Q

What nitrogenous bases are purines?

A

Adenine and Guanine.

41
Q

What is the main difference between Thymine and Uracil? [structure wise]

A

At the 10 O’clock [5’] carbon, Uracil has a hydrogen while Thymine has a methyl.

42
Q

What are the differences between Cytosine and Uracil?

A

Uracil has a double bonded Oxygen at the 12 PM carbon (6’) while cytosine has a NH2.

43
Q

What are differences between Cytosine and thymine.

A
  1. At 12 PM carbon, (6’). there is a double bonded oxygen in thymine and a NH2 in Cytosine.
  2. At the 10 PM carbon. (5’) there is a H attached to the carbon in cytosine and a methyl in Thymine.
44
Q

What are the 3 differences between the two purines?

A

Adenine and Guanine.

In succession: the 12 PM carbon (6’) is attached to double bonded oxygen in guanine and NH2 in Adenine.

The 2 PM Nitrogen (1’) is attached to H in guanine and to nothing in Adenine (double bond to 6’ C)

The 4PM Carbon (2’) is attached to NH2 in guanine and H in Adenine.

45
Q

What is attached differently to the 2’ carbon deoxy/ribose sugar in DNA and RNA?

A

DNA has an -H
RNA has an -OH attached to the 2’ carbon sugar.

46
Q

Where is the phosphate group attached in the sugar?

A

attached to the 5’ carbon of the sugar.

47
Q

What is attached to the 3’ end of the cabon?

A

A free hydroxyl group -OH

48
Q

what is the bond between adjacent nucleotides?

A

Phosphodiester bonds: formed between the phosphate group at the 5’ of one nucelotide and the 3’ OH of the next.

49
Q

Between what are phosphodiester bonds created?

A

formed between the phosphate group at the 5’ of one nucelotide and the 3’ OH of the next.

50
Q

A chain of nucelotides have what orientation?

A

5’ to 3’ orientation with 5’ phosphate and 3’ free hydroxyl

51
Q

How many polynucleotide chains in a DNA molecule?

A

2

52
Q

What bonds connect two polynucleotide chains together between nitogenous bases?

A

H bonds

2H between AT
3H between GC

53
Q

Which base paring has two H bonds?

A

Adenine and Thymine

54
Q

Which base paring has three H bonds?

A

Guanine and Cytosine

55
Q

Two chains of connected polynucleotides are what of each other?

A

Anti-Parallel

5’ to 3’ connected to 3’ to 5’

56
Q

Why can’t Cytosine not pair with Tyrosine and Adenine not with guanine?

A

Because of H-bonding requirments. Also Because purines and pyrimidines paired together fill EXACTLY the space between two chains in a double helix and the 2 H bond in AT and 3 in GC stabilize the paring.

57
Q

Complementaty pairing of bases gives consistant what ____ to DNA.

A

diameter. the 2 AT H bonds and 3 GC H bonds make the DNA double helix a certain width which allows it to be 2nm wide throughout.

58
Q

Two strands of DNA molecule are _______ to each other.

A

Complementary: Whenever A occurs in one stand T must be opposite to it.

G must be opposite to C.

59
Q

What was charaff’s rules?

A

Erwin Chargaff determined that:

Amount of adenine = Amount of thymine

Amount of cytosine = amount of guanine

Always equal proportions of purines (A and G) and pyrimidines (C and T)

A=T and G = C, and A + G = C + T

Ex: 26 % A = 26% T
24% G = 24 % C
26+ 24 = 24+ 26

60
Q

Describe polarity within DNA molecules.

A

Polypeptide chain of DNA has polarity because phosphate group is bound to 5’ carbon of deoxyribose and a hydroxyl group is bound to the 3’ end. With 2 strands anti-parallel, they are polar.

61
Q

What are the two grooves in DNA?

A

Minor and Major grooves which are usually subsequent when DNA’s helical strucure twists.

Major groove is where proteins bind to DNA>

62
Q

Where do proteins like histones bind to DNA?

A

Major groove where there is a large gap.

63
Q

What is the distance between base pairs?

A

0.34 nm

b/c 3.4 nm between one full circle, 10 base pairs in twist.

64
Q

Distance between a full twist of DNA?

A

3.4 nm

65
Q

Give the corresponding DNA polypeptide chain with marked ends:

5’ CGGTTACCGCTA 3’

A

3’ GCCAATGGCGATS 5’