Chapter 12: Alkynes Flashcards

1
Q

What is this alkyne called?

A

Terminal Alkyne

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2
Q

What is this alkyne called?

A

Internal Alkyne

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3
Q

Why is sp3 hybridized carbon the least stable base and F- the most stable base

A

Use ARIO; Most importantly atom and orbital
sp3 hybridized carbon is the least stable base because it the smallest atom, there are no resonance structures, and sp3 is the least stable hybridized orbital

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4
Q

Why can’t you use RO- (alkoxide) such as NaOEt or NaOMe to deprotonate a terminal alkyne?

A

Bases that are more stable than an alkynide ion can not be used to deprotonate a terminal alkyne to form one

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5
Q

What is this molecule?

A

Alkynide ion

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6
Q

How is an alkynide ion formed?

A

A terminal alkyne is deprotonated by a strong base (less stable base)

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7
Q

What is the significance of these reagents?

A

They are strong bases that can deprotonate a terminal alkyne to form an alkynide ion

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8
Q

What is the mechanism for an alkylation reaction?

A

A strong base deprotonates the terminal alkyne to from an alkynide ion. The alkynide ion then acts as a strong nucleophile that, when treated with an electrophile, will undergo a SN2 reaction. This is called alkylation.
Only efficient when the electrophile is a Me-Halide or RCH3-Halide

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9
Q

What is the outcome of this reaction?

A
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10
Q

Why won’t this reaction work?

A

Can only alkylate terminal alkynes (shown is an internal alkyne)

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11
Q

Why do you have to form two separate alkynide ions in this reaction?

A

A dianion is too high in energy and doesn’t exist

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12
Q

What is happening in this reaction?

A

E2 elimination reaction of geminal dihalide

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13
Q

What is happening in this reaction?

A

E2 elimination reaction of vicinal dihalide

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14
Q

What is this reaction?

A

Complete hydrogenation (reduction)
alkyne reduced to alkane

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15
Q

What is this reaction?

A

Partial hydrogenation (reduction)
Using a partially deactivated catalyst (Lindlar’s catalyst) will result in a cis alkene to form

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16
Q

What is this reaction?

A

Partial hydrogenation (reduction)
Using Na, NH3 as reagents will result in a trans alkene to form

17
Q

NaNH2 vs Na, NH3 as reagents

A

NaNH2 is used as a strong base to deprotonate a terminal alkyne to from a alkynide ion

Na, NH3 is used to partially reduce an alkyne through a dissolving metal reduction to form a trans alkene

18
Q

What reagents in a hydration reaction of an alkyne will result in markovnikov regiochemistry?

A

H2SO4, H2O
HgSO4

19
Q

What is this molecule?

A

Enol
it is a tautomer of a ketone (constitutional isomer that can rapidly interconvert via the migration of a proton)
Equilibrium greatly favors a ketone over enol

20
Q

Why does this hydration reaction form two products?

A

It is an asymmetrical internal alkyne and the reaction will occur on both sides of the alkyne

21
Q

What reagents in a hydration reaction of a terminal alkene will result in anti-markovnikov regiochemistry?

A

BH3 THF (or R2BH) and H2O2, NaOH
Called Hydroboration-oxidation
It is anti-markovnikov because BH3 is bulky and sterically hindered by the more substituted carbon
Results in an aldehyde formation

22
Q

What are these used for?

A

Hydroboration oxidation reaction of alkynes

23
Q

What is this molecule?

A

Enol (also can look like this)

24
Q

What is happening here?

A

The same alkyne can be converted to an aldehyde or a ketone based on what reagents are used in the reaction

25
Q

What is the mechanism for acid-catalyzed tautomerization?

A

this reaction is reversible

26
Q

What is the mechanism for base-catalyzed tautomerization?

A

this reaction is reversible

27
Q

What are the products of ozonolysis of a terminal alkyne?

A

Carboxylic acid + CO2

28
Q
A