Chapter 12 Flashcards

1
Q

Sigma bond

A

The result of two overlapping orbitals

Pair of electrons shared between bonding atoms

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2
Q

Alkanes shape

A

109.5

Tetrahedral shape

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3
Q

Why does more carbon atoms = ^ boiling point

A

More carbons
Larger surfaces area of contact points between molecules
More London forces
Higher strength of attraction between alcane chains
More heat need to overcome forces

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4
Q

Why does more branching = lower bp

A

More branching
Less surface area of contact points between molecules
Less London forces
Lower strength of attraction between molecules
Less energy needed to overcome forces

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5
Q

Complete combustion of alkanes

A

Alkane + oxygen –> carbon dioxide + water

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6
Q

Incomplete combustion of alkanes

A

Limited supply of oxygen

Alkane + oxygen –> carbon monoxide / carbon (soot) + water

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7
Q

Alkanes undergo radical substitution (halogénation)

A

Presence of uv radiation

Initiation propagation termination

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8
Q

Initiation of radical substitution

A

Halogen molecule absorbs uv radiation
Undergoes homolytic fission
2 highly reactive radicals

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9
Q

Propagation radical substitution 2 steps

A

Step 1
Halogen reacts with hydrogen in h-c bond
Producing an alkane radical and a hydrogen halide compound

Step 2
Alkane radical reacts with another halogen molecule
Producing an haloalkane and halogen radical

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10
Q

Termination - radical substitution

A

2 radicals collide
Producing a molecule with all electron pairs
The radicals are removed from the reaction mixture - stopping the reaction

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11
Q

What are the limitations of radical substitution and why does it happen

A

Produces a mixture of Of products, that may be unwanted and need to be filtered

If there is too much halogen
The hydrogen on wanted product with react with the halide forming an unwanted product
To stop this make sure there is an excess of alkane so there is a greater chance of the halogen radical colliding with alkane

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