Chapter 12 Flashcards
Features of crude oil
Fossil fuel- made from decaying plants and animals from millions of years ago
Does not ignite easily
Must be separated to become useful
What kind of bond do alkanes contain and what does it allow them to do
A sigma bind
Acts as a axis so the atoms can rotate freely so the shapes aren’t rigid
How does the chain length of alkanes effect the boiling point
As chain length increases there are more points of contact leading to more London forces between the molecules, therefore the higher the boiling point
How does branching in alkanes effect the boiling point
Branched molecules have fewer points of contact and are further apart then unbranched molecules so there are fewer intermolecular forces so the boiling point decreases as the branches increase
Do alkanes react with common reagents and why
No
C-C and C-H sigma bonds are strong
C-C bonds are non polar
The electronegativity of carbon and hydrogen is so similar that the C-H bond can be considered to be non polar
What are short chain alkanes valuable for
Clean fuels eg natural gas or LPG (liquified propane and butane)
Complete combustion of petrol
Mainly octane
C8H18(l) + 12.5O2(g) ———> 8CO2(g) + 9H2O(l)
Incomplete combustion of petrol
C8H18(l) + 8.5O2(g) ———> 8CO(g) + 9H2O(l)
Properties of carbon monoxide
Colourless odourless highly toxic
Binds IRREVERSIBLY with haemoglobin and prevents oxygen from binding so tissues become starved of oxygen
Conditions for the reaction between Alkanes and halogens
Presence of UV
300 degrees
What happens when an alkane reacts with a halogen in the right condition and an example
Radical substitution reaction :
Covalent bonds broken by Homolytic fission to form radicals with an unpaired electron
A hydrogen atom in the alkane is substituted by a halogen atom
CH4 +Cl2 ———>CH3Cl + HCl
(Bromine reacts in a similar way)
Mechanism for chlorination
Step 1
Initiation
The Cl-Cl bind is broken by Homolytic fission to produce radicals
Cl-Cl——> Cl. + Cl.
Mechanism for chlorination
Step 2
Propagation
A chain reaction, continues until no reactants remain
CH4 + Cl. ———> .CH3 + HCl
.CH3 + Cl2 ———> CH3Cl + Cl.
Limitations of radical substitution
Other mono substituted products are made
Further multiple substitutions occur
Mechanism for chlorination
Step 3
Termination
Two radicals combine to form a molecule
Cl. + Cl. ——> Cl2
.CH3 + .CH3 ——> C2H6
. CH3 + . Cl ——> CH3Cl