chapter 11 - Gene mutation, DNA repair, homologous recombination Flashcards

1
Q

What is the role of transposase?

A

Transposase is responsible for making staggered cuts of the DNA seq and carrying the transposable element to the target sequence.

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2
Q

What is an IS element?

A

Insertion element… is transposable.

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3
Q

What is the difference between an IS element and a composite transposon?

A

Composite - a type of transposon that carries genes such as antibiotic resistant genes

IS element - transposable elements, carry genes that code transposase/catalyze transposition activity

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4
Q

What are the steps of transposable element insertion into target sequences?

A

1 - transposase makes staggered cuts and leave DNA strands from target seq, leaving single stranded ends in the target seq.

2- transposable element is inserted into target seq, carried by transposase

3- gaps filled by DNA polymerase

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5
Q

What are transposable elements, also known as “jumping genes”?

A

-DNA sequences found in both eukaryotes and prokaryotes that have multiple copies and are able to move within the genome

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6
Q

What are point mutations?

A

Changes in one or a few base pairs… can be somatic (non heritable mutations, not egg/sperm) or germ-line (heritable, egg/sperm)

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7
Q

What are the two types of BASE PAIR SUBSTITUIONS?

A

Transition - Purine to purine… pyrimidine to pyrimidine

Transversion - Purine to pyrimidine, pyrimidine to purine

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8
Q

What are the types of base-pair substitutions that occur in the coding sequence?

A

Synonymous mutation
missense mutation
nonsense mutation
frameshift deletion
frameshift insertion

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9
Q

What is a wild type sequence also known as?

A

Sense codon

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10
Q

What is a synonymous mutation?

A

-mutation in coding seq
-change in DNA, amino acids stay the same… change in a wobble

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11
Q

What is a missense mutation?

A

-mutation in coding seq
-change in DNA that changes the amino acid

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12
Q

What is a nonsense mutation?

A
  • mutation in coding seq
    -change from a sense codon to a stop codon : UAG, UAA, and UGA
    -shortens seq of proteins
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13
Q

What is a frameshift insertion/deletion?

A
  • mutation in coding seq
    -a single base pair is added or removed, causing all of the amino acids to be off
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14
Q

What are the four regulatory mutations?

A

1- Promotor mutation

2- polyadenylation mutation

3- splice site mutation

4- DNA replication mutation (triple repeat expansion)

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15
Q

Describe the process of strand slippage, and what type of mutation is it?

A

-regulatory, DNA replication mutation

1 - DNA segment contains CAG-triplet repeats
2 - DNA polymerase slips off of strand during synthesis of daughter strand , causing the formation of hairpin loop
3 - in the next replication cycle, CAG repeats number is increased due to the hairpin loop (ex: beginning 6 CAG to end 11 CAG)

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16
Q

What could result from a promotor mutation?

A

Change in timing/amount of transcription

17
Q

What could result from a polyadenylation mutation?

A

Alter sequence of mRNA

18
Q

what may result from a mutation in the splice site?

A

Retaining introns/excluding exons

19
Q

What may result from a DNA replication mutation?

A

increase (sometimes decrease) number of short repeats of DNA

20
Q

What are the three types of reverse mutations?

A

1- true reversion

2- Intragenic reversion

3- second site/intergenic/silence reversion

21
Q

Describe a true reversion?

A

There is a second mutation (revertant) in the same codon that causes the mutated codon to encode for the wild-type amino acid

22
Q

Describe an intragenic reversion?

A

-a mutation that occurs in the same gene, but not the same spot
-two base pairs are deleted, following the insertion of two new base pairs, restoring the reading frame to wild type

23
Q

Describe a second site/intergenic/repressor reversion

A

-a mutation that occurs not in the same gene, occurs in a second gene
- represses certain genes in order to restore to wild-type or near wild-type

24
Q

What is the difference between a spontaneous and induced mutation?

A

Spontaneous - no external reason for mutation outside of cell

induced - can detect a reason outside of the cell for mutation

25
Describe chemical mutagen: Hydroxylating agent
- addition of hydroxyl (OH) group to a recipient compound by a donor known as hydroxylating agent - hydroxylamine is a hydroxylating agent that adds a hydroxyl group to cytosine by displacing an H2, creating hydroxylaminocytosine. -Hydroxylaminocytosine pairs with guanine but frequently mispairs with adenine, leading to transition mutations
26
What is the purpose of the Ames test?
- Uses bacteria to detect carcinogens - determine if chemicals can cause mutations in the cell - chemicals that have mutagenic effect on cells is considered carcinogenic - detects a reversion from his- to his+
27
Why add s9 activation enzymes from rat liver in the Ames test?
The S9 extract allows you to see if a mutagenic substance can be created by digestive reactions.
28
How does his- strains differ with base-pair substitutions and frameshift mutations?
Base pair sub - there is consistent growth in revertant colonies as medium increases frameshift - there is no growth at all ] conclusion: his- strains only revert under base-pair substitution
29
What are UV photoproducts?
formation of photoproducts cause by UV irradiation formed from adjacent pyrimidines (TT) distorts double helix, blocks replication
30
How does UV radiation damage DNA?
- mutagenic properties of UV radiation derives from legions it creates in DNA - alters DNA nucleotides by inciting formation of additional bonds known as photoproducts (TT bonds)
31
Describe photoreactive repair?
1- UV light causes a thymine dimer to form (TT) 2- photolyase binds to the dimer 3- visible light (300-500 nm) energized photolyase 4- photolyase released, DNA repaired
32
Describe Nucleotide excision repair (NER)?
1- UVR A binds to UVR B and helps it get to the damage site, binding opposite of the thymine dimer 2- UVR A leaves, and UVR C binds to UVR B, catalyzing 3' and 5' cuts. 3 - UVR D (helicase) releases damaged strand, DNA poly + ligase fill gaps, restoring DNA
33
What is Xeroderma Pigmentosum?
a skin condition caused by a mutation in the NER system, individuals are homozyous recessive and cannot go into the sun - freckles -photophobia - skin cancer -tumor in eye -premature skin aging - neurological problems
34
Describe Mismatch repair?
1 - mutH binds to hemi-methylated CTAG recognition site 2 - MutS binds to the mismatch site 3- MutL is attracted by MutS, forms the bed which contacts MutH 4 - MutH cleabes from pre mismatch to site of methylation, causing single strand gap 5 - gap filled in by ligase and polymerase
35
What are the three types of DNA repair systems?
1 - photoreactive repair 2 - nucleotide excision repair (NER) 3 - Mismatch repair
36
Describe Meiotic recombination?
Crossing over occurs during meiosis between two homologous non sister chromatids.... 1 - protein binds to one of the strands, causing a double strand break, making the strands offset 2 - Enzymes bind to the strands, digesting them 5-3 creating single strand segments 3 - proteins bind to exposed single strands, top strand falls between the two bottom strands (strand invasion), causing bottom strand to form a D Loop/holliday junction/heteroduplex region 4 - strands are extended by polymerase, displaced D loop, pairs with complementary single strand dna to form second heteroduplex region 5 - dna poly extension fills gaps in strand paired with d loop, forming a second d loop in top strands 6 - double hollidays junctions form
37
What are the two possible outcomes of meiotic recombination?
Opposite sense resolution: - EW and NS cuts : common, results in recombination of flanking genes, creates offset heteroduplex regions. Same sense resolution: - EW and EW cuts : not common, no recombination of flanking genes, creates offset heteroduplex region