Chapter 10 Flashcards
1
Q
Trigonal Planar
A
- Trigonal Planar 120°
- 3 e- groups
- 3 bonding groups
- 0 lone pairs
- Bent <120°
- 3 e- groups
- 2 bonding groups
- 1 lone pair
2
Q
Tetrahedral
A
- Tetrahedral 109.5°
- 4 e- groups
- 4 bonding groups
- 0 lone pairs
- Trigonal Pyramidal <109.5°
- 4 e- groups
- 3 bonding groups
- 1 lone pair
- Bent <109.5°
- 4 e- groups
- 2 bonding groups
- 2 lone pairs
3
Q
Trigonal Bipyramidal
A
- Trigonal Bipyramidal 120° (equatorial), 90° (axial)
- 5 e- groups
- 5 bonding groups
- 0 lone pairs
- Seesaw 120° (equatorial), <90° (axial)
- 5 e- groups
- 4 bonding groups
- 1 lone pair
- T-Shaped <90°
- 5 e- groups
- 3 bonding groups
- 2 lone pairs
- Linear 180°
- 5 e- groups
- 2 bonding groups
- 3 lone pairs
4
Q
Octahedral
A
- Octahedral 90°
- 6 e- groups
- 6 bonding groups
- 0 lone pairs
- Square Pyramidal <90°
- 6 e- groups
- 5 bonding groups
- 1 lone pair
- Square Planar 90°
- 6 e- groups
- 4 bonding groups
- 2 lone pairs
*
5
Q
Bond Order
A
- Positive Bond order means there are more electrons in bonding MO’s than in antibonding MO’s
- The higher the bond order, the stronger the bond
BO = ½(#bonding - #antibonding)
6
Q
Molecular Shape & Polarity (Determination)
A
- Draw a lewis structure and determine the molecular geometry.
- Determine whether the molecule contains polar bonds.
- Determine whether the polar bonds at together to form a net dipole moment.
7
Q
Polar Bonds
A
Polar if the two bonding atoms have sufficiently different electronegativities.
8
Q
VSEPR
A
Valence Shell Electron Pair Repulsion Theory
Electrong groups repel one another through coulombic forces.
9
Q
Valence Bond Theory
A
- Electrons reside in quantum-mechanical orbitals localized on individual atoms.
- A chemical bond results from the overlap of two half-filled orbitals with spin-pairing of the two valence electrons.
- The shape of the molecule is determined by the geometry of the overlapping orbitals.
10
Q
sp3 Hybridization
A
One s orbital and three p orbitals combine to form sp3 orbitals.
11
Q
sp2 Hybridization
A
One s and two p orbitals results in three sp2 hybrids and one leftover unhybridized p orbital.