Chapter 1 Flashcards
Velocity is constant when the slope of a displacement vs time graph is a straight line, and/or when acceleration is 0 on a neighboring acceleration vs time graph.
EK 18, 216
To find the total distance traveled, solve for the total area between the line and the x-axis (area under the
graph) in a velocity vs time graph.
EK 18, 216
If you see a velocity vs time graph with discontinuous lines, it means the direction suddenly changed.
EK 18, 216
a constant slope on the velocity vs. time graph represents constant acceleration
EK 18, 216
Since both skydivers are at constant velocity, their acceleration is zero, and by Newton’s Second Law
they must both experience a net force of zero.
EK 18, 216
Acceleration and net force directly related. If there is a net force, there will be acceleration.
EK 19, 21
Whenever you see an inclined plane, think mg sinS. This is always the net force down any inclined plane due to gravity and the normal force. Likewise, mg cosS is always the normal force. These formulas work regardless of the angle of the plane.
EK 25
Unit circle
http://theunitcircle.weebly.com/answers.html
Normal force is always perpendicular to the surface that applies it (surface being a plane) of contact, for example, the surface of a floor or wall, preventing the object from falling.
Normal force is not always equal in magnitude to the force of gravity; for example, the normal
force on an inclined plane
EK 28, 217
wikipedia
According to Newton’s Law of Universal Gravitation, all things exert force on each other, but for things the differ greatly in mass, the force is very small. It still exists, as according to Newton’s 2nd Law (F=ma), the mass or force is not 0, so neither can acceleration be.
EK 28, 217
PROJ: In projectile motion, use the Y components of velocity to determine the time it is airborne.
TBR 36
PROJ: 45 deg angle in projectile motion is greatest distance, 90 deg angle is highest height.
TBR
PROJ: When launched at complementary angles, identical projectiles exhibit the same range
TBR 40
PROJ: In projectile motion, the x component of velocity is constant. The y component is positive in the first half of projectile motion, and then at the apex it essentially is “overpowered” by gravity and is 0. Then the projectile starts decelerating and the y component is negative. Y component is 0 if the projectile is launched horizontally. Acceleration for projectile is always gravity (disinclude air resistance).
TBR 36
PROJ: PE depends on height (all same initial height, all same PE). KE depends on initial speed (all same initial speed, all same KE). If all finish at same final height, all have same final PE. KEf + PEf =KEi+PEi
TBR 40
