Ch. 8 Flashcards

1
Q

Why is a pi bond less stable

A

The electron density is above and below the C, which is further from the nucleus and less stable

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2
Q

____ bonds are more stable than pi bonds. ______ bonds will break down to sigma bonds

A

Sigma/single
Double

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3
Q

Electrophilic Additions

A

An addition in which the electrophile bonds to one of the double-bonded carbon first, followed by the nucleophile

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4
Q

Electrophilic Addition mechanism

A

The pi bond attacks the electrophile to form a carbocation. A nucleophile attacks the carbocation

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5
Q

Markovnikov’s Rule

A

for an electrophilic addition to the alkene, the electrophile adds in such a way as to generate the most stable intermediate

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6
Q

Anti-Markovnikov Product

A

an orientation that is the opposite of that predicted by the original statement of Markovnikov Rule

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7
Q

When does the anti-Markovnikov Product

A

Only works with HBr in the presence of peroxide

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8
Q

How do you form radicals from ROOR

A

R-O. and .O-R with heat

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9
Q

In Free-Radical addition, the radical on the _____ substituted carbon

A

more

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10
Q

How does addition of water work

A

It dilutes the acid to force equilibrium with the alcohol

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11
Q

What is hydroboration?

A

the addition of borane or one of it’s derivatives to a molecule

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12
Q

Is BH3 a strong electrophile or strong nucleophile?

A

Strong electrophile

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13
Q

Does hydroboration-oxidation do markovnikov or anti-markovnikov

A

anti-markovniov

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14
Q

What is halohydrin?

A

Alcohol with a halogen on the adjacent carbon. Must have a good nucleophile presence like water

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15
Q

Enantioselective Synthesis

A

the formation of an optically active product from an optically inactive starting material.

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16
Q

What does enantioselective synthesis require

A

the use of an optically active reagent or catalyst

17
Q

Carbene

A

a molecule containing a neutral carbon atom with a valence of two and two unshared valence electrons

18
Q

Acid-Catalyzed Opening of Epoxides

A

Acid catalyzed reaction, water attacks the protonated epoxide and forms an anti-diol

19
Q

Hydroxylation

A

the addition of two hydroxyl groups, one at each carbon of the double bond