ch 6 projectiles Flashcards
What is important to remember about projectiles?
-The question can be split into a vertical and horizontal plane.
What is unique about the horizontal plane in SUVAT?
-No acceleration in the horizontal plane.
What is the initial speed in the vertical direction?
0
If you have a vertical and horizontal component how could you work out the distance?
-Pythag using both distances.
How can you find the initial velocity of a projectile?
-Try and find the time the vertical component hits the ground and this value of time can be used in the horizontal component.
How do you deal with a projectile at an angle?
-Divide it into horizontal component for initial speed and vertical component for initial speed.
Using opposite sin and adjacent cos.
How is the greatest height found in projectiles?
When vertical velocity = 0.
How to find the total time of flight in projectiles?
When vertical displacement = 0 as it has returned to starting position.
What must you be careful of when working with displacement in vertical direction?
-If the ball is above xm above ground its displacement will be -xm when hits ground.
How do you find the horizontal distance in projectiles two steps? DISTANCE AX
step 1 work out the time where it gets to X in vertical.
step 2 work out the distance x time.
What is the formula for time of flight?
2Usintheeta/ g
How to work out the formula for Range of horizontal distance?
- Use the value of T= 2UsinTheeta/ g
- Then sub this into D=ST
-U^2Sin2Theeta
How do you derive the formula for (x,y).
- Create a formula for displacement in terms of Y
- Create a formula for displacement in term of X.
-COmbine the two to create y=xtanθ - gx2/2u2cos2θ(1 + tan^2).
Why are there two values of theta for the intersection?
It could have intersected on the way up or it could have interacted on the way down.
