Ch 24 - Carbonyl Condensation Rxns Flashcards

0
Q

3 main steps of aldol rxn?

A

1) deprotonate alpha C w/base ➡ enolate
2) enolate attacks 2nd carbonyl (nuc addn)
3) protonate O on beta C (former carbonyl O of 2nd carbonyl)

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1
Q

General rxn of aldol rxn?

A
  • 2 aldehydes/ketones rxt w/each other in base ➡ beta-hydroxy carbonyl compd
  • nuc addition of enolate (nucleophile) to aldehyde/ketone
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2
Q

Dehydration of aldol ➡ ?

A

Alpha,beta-unsaturated carbonyl compd (C=C bet alpha & beta C)

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3
Q

General mechanism for dehydration of aldol in base?

A

1) deprotonate alpha C w/base ➡ enolate
2) form C=C w/enolate C, elim of LG (-OH)
“E1CB”

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4
Q

When is crossed aldol rxn (use of 2 diff carbonyls) useful?

A

1) when only one of the carbonyl compds has an alpha H

2) when one carbonyl compd has very acidic H’s (Y-CH2-Z, Y,Z = C=O or nitrile)

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5
Q

Aldol rxn w/? ➡ 5 membered ring

A

1,4-dicarbonyl compd (CH2CH2 bet two C=O)

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6
Q

Aldol rxn w/? ➡ 6 membered ring

A

1,5-dicarbonyl compd

(CH2)3 bet 2 C=O

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8
Q

General rxn of Claisen rxn?

A
  • 2 esters rxt w/each other in alkoxide base ➡ beta-keto ester
  • nuc sub of OEt w/enolate
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9
Q

Mechanism of Claisen rxn?

A

1) -OEt deprotonates alpha C ➡ enolate
2) enolate attacks carbonyl C of 2nd ester (nuc addn)
3) elim of LG (-OEt)
4) deprotonate CH2 between 2 C=O ➡ enolate (drives equilibrium)
5) protonate enolate w/acid

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10
Q

When is crossed Claisen rxn (two diff carbonyls) used?

A

1) bet 2 diff esters when only 1 ester has alpha H’s

2) bet an ester and a ketone (enolate)

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11
Q

Dieckmann (intramecular Claisen) w/? ➡ 5 membered ring

A

1,6-diester

(CH2)4 bet two C=O

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12
Q

Diekmann rxn (intramolecular Claisen) w/? ➡ 6 membered ring

A

1,7-diester

(CH2)5 bet 2 C=O

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13
Q

General rxn of Michael addn?

A

1,4 addn of enolate to beta C of alpha, beta-unsaturated carbonyl compd

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14
Q

Mechanism of Michael addn?

A

1) -OEt deprotonates alpha C of carbonyl compd ➡ enolate
2) enolate attacks beta C of alpha, beta unsat. ➡ new enolate (on alpha C)
3) protonate alpha C w/water

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15
Q

Robinson annulation: alpha,beta-unsaturated CO + enolate ➡ ?

A
  • Six membered ring & 2 new sigma bonds, 1 new pi bond

* 2-cyclohexenone ring

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16
Q
Mechanism of Robinson annulation:
Part 1 (Michael addn ➡ 1,5-dicarbonyl compd)
A

1) base deprotonates alpha C of carbonyl compd ➡ enolate
2) enolate attacks beta C of alpha, beta-unsat. ➡ new enolate (on alpha C)
3) protonate enolate w/H2O ➡ 1,5-dicarbonyl compd

17
Q
Mechanism of Robinson annulation:
Part 2 (intramolecular aldol rxn ➡ 2-cyclohexenone)
A

4) base deprotanates alpha C of part not in ring ➡ enolate
5) enolate attacks carbonyl C ➡ form 6 membered ring (1 new sigma)
6) protonate carbonyl O
7) deprotonate same alpha C ➡ enolate
8) form C=C with enolate C, loss of LG (-OH) ➡ 2-cyclohexenone

18
Q

Mechanisms to know for ch. 24!

A
  • intramolecular aldol

* Robinson annulation

19
Q

Mechanism of intermolecular aldol?

A

1) -OEt deprotonates outer alpha C ➡ enolate
2) nuc addn of “2nd carbonyl compd” (other C=O in same compd)
3) protonation of 2nd carbonyl O
4) -OEt deprotonates alpha C again
5) form C=C w/enolate C, elim of LG (-OH)